Last visit was: 19 Nov 2025, 19:20 It is currently 19 Nov 2025, 19:20
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
tkarthi4u
Joined: 08 Jan 2009
Last visit: 12 Aug 2013
Posts: 141
Own Kudos:
320
 [39]
Given Kudos: 5
Concentration: International business
Posts: 141
Kudos: 320
 [39]
2
Kudos
Add Kudos
37
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,379
 [10]
4
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
General Discussion
User avatar
fluke
User avatar
Retired Moderator
Joined: 20 Dec 2010
Last visit: 24 Oct 2013
Posts: 1,099
Own Kudos:
5,095
 [4]
Given Kudos: 376
Posts: 1,099
Kudos: 5,095
 [4]
3
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
Sachin9
Joined: 22 Jul 2012
Last visit: 25 Dec 2015
Posts: 351
Own Kudos:
174
 [1]
Given Kudos: 562
Status:Gonna rock this time!!!
Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE:Information Technology (Computer Software)
GMAT 2: 630 Q47 V29
Posts: 351
Kudos: 174
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
tkarthi4u
What is the area of parallelogram ABCD ?
1) AB = BC = CD = DA = 1
2) AC = BD = (2^1/2)


(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

C.

Bunuel,
A rhombus and a square with same lengths have different areas?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,379
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sachin9
Bunuel
tkarthi4u
What is the area of parallelogram ABCD ?
1) AB = BC = CD = DA = 1
2) AC = BD = (2^1/2)


(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

C.

Bunuel,
A rhombus and a square with same lengths have different areas?

Good question.

If you squeeze a square along its diagonal you'll get a rhombus. Different rhombuses you'll get while doing that, will have different area. So, the answer to your question is yes.

Hope it's clear.
User avatar
Sachin9
Joined: 22 Jul 2012
Last visit: 25 Dec 2015
Posts: 351
Own Kudos:
Given Kudos: 562
Status:Gonna rock this time!!!
Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE:Information Technology (Computer Software)
GMAT 2: 630 Q47 V29
Posts: 351
Kudos: 174
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Pardon me. I didn't get you, Bunuel..

Are you saying that the square and different shapes of rhombuses with same length will have different areas?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,379
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sachin9
Pardon me. I didn't get you, Bunuel..

Are you saying that the square and different shapes of rhombuses with same length will have different areas?

Yes, that's what I'm saying.
User avatar
Sachin9
Joined: 22 Jul 2012
Last visit: 25 Dec 2015
Posts: 351
Own Kudos:
Given Kudos: 562
Status:Gonna rock this time!!!
Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE:Information Technology (Computer Software)
GMAT 2: 630 Q47 V29
Posts: 351
Kudos: 174
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Sachin9
Pardon me. I didn't get you, Bunuel..

Are you saying that the square and different shapes of rhombuses with same length will have different areas?

Yes, that's what I'm saying.

ok thanks..
Now 2 questions:
1)if the square and different shapes of rhombuses with same length will have different areas, the square will have the largest area . Guess this is correct.

2)this question seems dubious now to me.. A square is also a parallelogram and even a rhombus is.. so how can we be sure that ABCD is not a square and is a rhombus.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
778,379
 [1]
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,379
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sachin9
Bunuel
Sachin9
Pardon me. I didn't get you, Bunuel..

Are you saying that the square and different shapes of rhombuses with same length will have different areas?

Yes, that's what I'm saying.

ok thanks..
Now 2 questions:
1)if the square and different shapes of rhombuses with same length will have different areas, the square will have the largest area . Guess this is correct.

2)this question seems dubious now to me.. A square is also a parallelogram and even a rhombus is.. so how can we be sure that ABCD is not a square and is a rhombus.

Not sure I understand what you are trying to say.

Anyway:
From (1) we have that the parallelogram is also a rhombus (because the sides are equal).
From (2) we have that the parallelogram is also a rectangle (because the diagonals are equal).

So, our parallelogram is a rhombus AND a rectangle, so it's a square!
User avatar
swati007
Joined: 14 Jun 2011
Last visit: 22 May 2015
Posts: 52
Own Kudos:
274
 [1]
Given Kudos: 15
GMAT 1: 560 Q41 V25
Posts: 52
Kudos: 274
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?\
User avatar
PathFinder007
Joined: 10 Mar 2014
Last visit: 21 Oct 2018
Posts: 129
Own Kudos:
Given Kudos: 13
Posts: 129
Kudos: 733
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
swati007
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A rhombus is a special type of a square, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram \(ABCD\)?

Notice that we are told that ABCD is a parallelogram.

(1) \(AB = BC =CD = DA = 1\) --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to \(\frac{d_1*d_2}{2}\) (where \(d_1\) and \(d_2\) are the lengths of the diagonals) or \(bh\) (where \(b\) is the length of the base and \(h\) is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) \(AC = BD = \sqrt{2}\) --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Answer: C.

Hope it's clear.

HI Bunnel,

Diagonal of a square is also equals. then if both the diagonals are equal and root 2 then we have side as 1 and we can calculate the area.

Please clarify.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,379
Kudos
Add Kudos
Bookmarks
Bookmark this Post
PathFinder007
Bunuel
swati007
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A rhombus is a special type of a square, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram \(ABCD\)?

Notice that we are told that ABCD is a parallelogram.

(1) \(AB = BC =CD = DA = 1\) --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to \(\frac{d_1*d_2}{2}\) (where \(d_1\) and \(d_2\) are the lengths of the diagonals) or \(bh\) (where \(b\) is the length of the base and \(h\) is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) \(AC = BD = \sqrt{2}\) --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Answer: C.

Hope it's clear.

HI Bunnel,

Diagonal of a square is also equals. then if both the diagonals are equal and root 2 then we have side as 1 and we can calculate the area.

Please clarify.

Please read the red part in my solution. Why should the sides equal to 1? Why cannot they be any numbers satisfying \(x^2+y^2=2\)?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
778,379
 [1]
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,379
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
PathFinder007
Bunuel


Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A rhombus is a special type of a square, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram \(ABCD\)?

Notice that we are told that ABCD is a parallelogram.

(1) \(AB = BC =CD = DA = 1\) --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to \(\frac{d_1*d_2}{2}\) (where \(d_1\) and \(d_2\) are the lengths of the diagonals) or \(bh\) (where \(b\) is the length of the base and \(h\) is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) \(AC = BD = \sqrt{2}\) --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Answer: C.

Hope it's clear.

HI Bunnel,

Diagonal of a square is also equals. then if both the diagonals are equal and root 2 then we have side as 1 and we can calculate the area.

Please clarify.

Please read the red part in my solution. Why should the sides equal to 1? Why cannot they be any numbers satisfying \(x^2+y^2=2\)?

For more on this trap check the following questions:
the-circular-base-of-an-above-ground-swimming-pool-lies-in-a-167645.html
figure-abcd-is-a-rectangle-with-sides-of-length-x-centimete-48899.html
in-right-triangle-abc-bc-is-the-hypotenuse-if-bc-is-13-and-163591.html
m22-73309-20.html
points-a-b-and-c-lie-on-a-circle-of-radius-1-what-is-the-84423.html
if-vertices-of-a-triangle-have-coordinates-2-2-3-2-and-82159-20.html
if-p-is-the-perimeter-of-rectangle-q-what-is-the-value-of-p-135832.html
if-the-diagonal-of-rectangle-z-is-d-and-the-perimeter-of-104205.html
what-is-the-area-of-rectangular-region-r-105414.html
what-is-the-perimeter-of-rectangle-r-96381.html
pythagorean-triples-131161.html
given-that-abcd-is-a-rectangle-is-the-area-of-triangle-abe-127051.html
m13-q5-69732-20.html#p1176059
m20-07-triangle-inside-a-circle-71559.html
what-is-the-perimeter-of-rectangle-r-96381.html
what-is-the-area-of-rectangular-region-r-166186.html
if-distinct-points-a-b-c-and-d-form-a-right-triangle-abc-129328.html

Hope this helps.
User avatar
PathFinder007
Joined: 10 Mar 2014
Last visit: 21 Oct 2018
Posts: 129
Own Kudos:
Given Kudos: 13
Posts: 129
Kudos: 733
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Because diagonal of a square = site root2

now as it is given diagonals are equal and this is also property of a square . so if diagonal is root 2 then my site will be 1. and area of a square would be one.

Thanks
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,379
Kudos
Add Kudos
Bookmarks
Bookmark this Post
PathFinder007
Because diagonal of a square = site root2

now as it is given diagonals are equal and this is also property of a square . so if diagonal is root 2 then my site will be 1. and area of a square would be one.

Thanks

First of all from (2) we know that ABCD is a rectangle, not necessarily a square.

Next, the fact that the diagonals equals to \(\sqrt{2}\) does not mean that the sides must be equal to 1. The sides can be:

\(\frac{1}{2}\) and \(\frac{\sqrt{7}}{2}\);
\(\frac{1}{3}\) and \(\frac{\sqrt{7}}{\sqrt{3}}\);
...

Basically the lengths of the sides can be any positive (x, y) satisfying \(x^2+y^2=(\sqrt{2})^2\).

Please follow the links in my post above for questions which use the same trap.
User avatar
23a2012
Joined: 03 Oct 2013
Last visit: 14 Jun 2015
Posts: 64
Own Kudos:
Given Kudos: 144
Status:Kitchener
Location: Canada
Concentration: Finance, Finance
GPA: 2.9
WE:Education (Education)
Posts: 64
Kudos: 49
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Knesl
What is the area of parallelogram ABCD ?

(1) AB = BC = CD = DA = 1
(2) AC = BD = \(\sqrt{2}\)

(C) 2008 GMAT Club - M13-05

Dear Bunuel, can we say - based on statement 2- that the parallelogram could be rhombus? If the answer is not can

you tell me why?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,379
Kudos
Add Kudos
Bookmarks
Bookmark this Post
23a2012
Knesl
What is the area of parallelogram ABCD ?

(1) AB = BC = CD = DA = 1
(2) AC = BD = \(\sqrt{2}\)

(C) 2008 GMAT Club - M13-05

Dear Bunuel, can we say - based on statement 2- that the parallelogram could be rhombus? If the answer is not can

you tell me why?

From (2) we have that ABCD is a rectangle, and if it's a square, then it becomes a rhombus too.
User avatar
earnit
Joined: 06 Mar 2014
Last visit: 21 Dec 2016
Posts: 164
Own Kudos:
Given Kudos: 84
Location: India
GMAT Date: 04-30-2015
Products:
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
tkarthi4u
What is the area of parallelogram ABCD ?
1) AB = BC = CD = DA = 1
2) AC = BD = (2^1/2)


(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of the diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.


I would really appreciate if a fault in my logic is pointed out.

Statement 1: ABCD is either a square or a rhombus, so different areas. Insufficient.

Statement 2: ABCD is a parallelogram with equal diagonals, so cannot be a rhombus. Possibly a rectangle or a square. Insufficient.

1+2. It must be a square.

Answer C
User avatar
GMATBusters
User avatar
GMAT Tutor
Joined: 27 Oct 2017
Last visit: 14 Nov 2025
Posts: 1,924
Own Kudos:
Given Kudos: 241
WE:General Management (Education)
Expert
Expert reply
Posts: 1,924
Kudos: 6,647
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hii
if we know one of the diagonal length & we know that it is a rhombus ( as all sides are equal)
We can find the length of both diagonals using geometrical properties and also the area. (Tag me if you want to know the procedure)
Area of rhombus = (product of diagonal/2)

Answer would be C in that case also.

vietnammba
Hi Bunuel,

If the second statement states that the diagonal length is different from square root of 2, the right choice will be E?
User avatar
GMATBusters
User avatar
GMAT Tutor
Joined: 27 Oct 2017
Last visit: 14 Nov 2025
Posts: 1,924
Own Kudos:
Given Kudos: 241
WE:General Management (Education)
Expert
Expert reply
Posts: 1,924
Kudos: 6,647
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi

the area of rhombus is not fixed only by the length of sides of rhombus.
To find are of rhombus, following information required:
1) Both diagonals
2) sides and angle between sides.
3) sides and a diagonal

In fact Square has the max area of all the rhombus having same side lengths.
Attachment:
WhatsApp Image 2018-05-12 at 08.55.17.jpeg
WhatsApp Image 2018-05-12 at 08.55.17.jpeg [ 61.09 KiB | Viewed 9557 times ]


Sachin9
Pardon me. I didn't get you, Bunuel..

Are you saying that the square and different shapes of rhombuses with same length will have different areas?
 1   2   
Moderators:
Math Expert
105390 posts
496 posts