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chetan2u
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chetan2u
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What is the hundreds digit of \(201^{201}\) ?
(A) 0
(B) 1
(C) 2
(D) 5
(E) 7

New question!!!..

pattern of hundreds digit of \((201)^n\):-
2-4-6-8-0
Cyclicity:- 5

We have \(\frac{201}{5}\) leaves 1 as remainder.
So, hundreds digit of \((201)^{201}\) is same as hundreds digit of \((201)^1\).

Therefore, the required hundreds digit is 2.

Ans. (C)
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chetan2u
What is the hundreds digit of \(201^{201}\) ?
(A) 0
(B) 1
(C) 2
(D) 5
(E) 7

New question!!!..

\((201)^0\) - Hundred's digit is 0
\((201)^1\) - Hundred's digit is 2
\((201)^2\) - Hundred's digit is 4
\((201)^3\) - Hundred's digit is 6
\((201)^4\) - Hundred's digit is 8
\((201)^5\) - Hundred's digit is 0
\((201)^6\) - Hundred's digit is 2
\((201)^7\) - Hundred's digit is 4

A pattern emerges and 8 is the hundred's digit for the 4,9,14,19.......199th power of 201.

Therefore, the hundred's digit of \(201^{201}\) is 2(Option C)
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PKN
chetan2u
chetan2u
What is the hundreds digit of \(201^{201}\) ?
(A) 0
(B) 1
(C) 2
(D) 5
(E) 7

New question!!!..

pattern of hundreds digit of \((201)^n\):-
2-4-6-8-0
Cyclicity:- 5

PKN, how do you know the pattern is 2-4-6-8-0?

I solved this using binomial expansion.
If you think of 201^201 = (200+1)^201 = 201C0*200^201 + 201C1*200^200 + ... + 201C200*200^1 + 201C201*200^0
^the highlighted term equal 201*200 = 40200
^the highlighted part is the hundreds digit. All other terms will have higher powers and won't contribute to the hundreds term.

Answer: C
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chetan2u
What is the hundreds digit of \(201^{201}\) ?
(A) 0
(B) 1
(C) 2
(D) 5
(E) 7

New question!!!..

The answer is (c)2.

My approach might be lengthy yet easy! Here it goes.

Note: 401, 601 etc are all the last 3 digits

\(201^{201}\) can be written as \(201^{200}\) * 201.
= \((201^{2})^{100}\) * 201
= \((401)^{100}\) * 201
= \((401^{2})^{50}\) * 201
= \(801^{50}\) * 201
= \(((801)^{2})^{25}\) * 201
= \((601)^{25}\) *201
= \((601^{2})^{12}\) * 201 * 601
= \((201)^{12}\) *201 * 601
= \(((201)^{2})^{6}\) *201 *601

again \(201^2\) is 401 hence substitute,
\(401^2\) is 801
= 601 * 801 * 201 * 601
the hundreds digit of the above is 2.

Thanks,
Uma
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pushpitkc
chetan2u
What is the hundreds digit of \(201^{201}\) ?
(A) 0
(B) 1
(C) 2
(D) 5
(E) 7

New question!!!..

\((201)^0\) - Hundred's digit is 0
\((201)^1\) - Hundred's digit is 2
\((201)^2\) - Hundred's digit is 4
\((201)^3\) - Hundred's digit is 6
\((201)^4\) - Hundred's digit is 8
\((201)^5\) - Hundred's digit is 0
\((201)^6\) - Hundred's digit is 2
\((201)^7\) - Hundred's digit is 4

A pattern emerges and 8 is the hundred's digit for the 4,9,14,19.......199th power of 201.

Therefore, the hundred's digit of \(201^{201}\) is 2(Option C)


I do understand your answer, but calculating hundred's for these numbers to understand the cyclicity will be time taking process in exam, wouldn't it take som much of time
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(200+1)^201
As all terms except last 2 has huge no of zeros let’s
Focus on last 2 terms:
201C200 (200)+201C201 .1
=40200+1

We get 2

Posted from my mobile device
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