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Re: What is the hundreds digit of the integer z? [#permalink]

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26 Feb 2011, 07:38

subhashghosh wrote:

Please elaborate a bit more on this :

"Any number from this range rounded to the nearest hundreds will be 9,300."

One of my doubts is, how are we converting the ten's and unit's place to 0 while rounding off ?

Regards, Subhash

The statement says nearest 100.

Take few examples;

575: 575 is between 500 and 600 but which one is the nearest 100 to 564; 600 or 500; 600 because it is just 25 away from 600 and 75 away from 500. So; 564 rounded to nearest hundred is 600.

Likewise; 9,230 is between 9200 and 9300; but the nearest 100 for 9230 is 9200.

For the range; 9250<z<9350; take any number; 9251, 9260, 9270, 9299, 9300, 9315, 9340, 9349; there is only one number that is their nearest 100; that number is 9300.

So; if z=9260, then the nearest hundred is 9300 If z=9340; the nearest integer is 9300.

Thus, Statement 2 is not sufficient to uniquely deduce the hundreds digit of z. It could be either "2" as in 9260 or "3" as in 9340.
_________________

For option A, z can be 9312 which gives the answer 3. Why can't z also be 93.12 ?

First of all we are told that z is an integer. But even more importantly, 10z = 93,120, gives z = 93,120/10 = 9,312.

Silly me. Totally ignored the fact that z is an integer. I thought the answer cannot be so straightforward and there has to something else to it that I am missing. Thank you!