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Bunuel

Tough and Tricky questions: Statistics



What is the median of set A {-8, 15, -9, 4, N}?

(1) N is a prime and N^6 is even
(2) 2N + 14 < 20

A.

1) N is prime and N^6 is even implies N is 2 (as all other primes are odd and odd^6 = odd)
hence A is sufficient.

2) 2N + 14 < 20
N < 3
clearly insufficient.

Hi, I have a silly question.

Why is n<3 insufficient. Does it not point towards the fact the N=2?

Shouldnt the answer be D?
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Bunuel

Tough and Tricky questions: Statistics



What is the median of set A {-8, 15, -9, 4, N}?

(1) N is a prime and N^6 is even
(2) 2N + 14 < 20

A.

1) N is prime and N^6 is even implies N is 2 (as all other primes are odd and odd^6 = odd)
hence A is sufficient.

2) 2N + 14 < 20
N < 3
clearly insufficient.

Hi, I have a silly question.

Why is n<3 insufficient. Does it not point towards the fact the N=2?

Shouldnt the answer be D?

N < 3 means that N can be ANY number less than 3, not necessarily 2. It can be say, -1000 or -1000000 or 0 or 1 or 1.2.
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alanforde800Maximus
What is the median of set A {-8, 15, -9, 4, N}?

1) N is a prime and N^6 is even.

2) 2N + 14 < 20

Please assist with above problem.
1) N^6 is even ,it means N is even number
Further any even number which is prime also is only 2.
So we have N=2 ,thus we can calculate median of set.....sufficient
2)2N + 14 < 20
2N < 20- 14
N<3
so N can have as many values <3
so we cannot calculate median of given set.........insufff..

Ans A
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Bunuel

Tough and Tricky questions: Statistics



What is the median of set A {-8, 15, -9, 4, N}?

(1) N is a prime and N^6 is even
(2) 2N + 14 < 20

We don't necessarily need to know the exact value of N to find the median of the set (middle number)- but we possibly need to know a range.

Statement 1

Any odd number to any power will always result in an odd number- the only prime number that satisfies the condition in statement 1 is the number 2- sufficient

Statement 2

This reduces to

2n <6
n < 3

There are infinite possibilities for "N" (-∞, 2) - insufficient

Hence
"A"
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Bunuel

Tough and Tricky questions: Statistics



What is the median of set A {-8, 15, -9, 4, N}?

(1) N is a prime and N^6 is even
(2) 2N + 14 < 20

Primes, indeed, can only be positive. I think this is a bit beyond a 500 level question.

St 1

Only 2 can satisfy this value

insuff
St 2

n could be -500 or -2 or 0 which would alter the median

insuff

A
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Bunuel

Tough and Tricky questions: Statistics



What is the median of set A {-8, 15, -9, 4, N}?

(1) N is a prime and N^6 is even
(2) 2N + 14 < 20

In order to find out median, we need to know value of N.

As per Option(1), N is a prime and \(N^6\) is even.
The only way a product of integers is odd is if each thing in the product is odd. So in order for \(N^6\) to be even N has to be even. 2 is only prime number which is even so \(N\) is 2

Option 2 doesn't give us exact value of N. From option 2, N can be anything less than 3 i.e. -9,0,1,2 etc.

Option 1 is sufficient to get an answer.
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Statement 1: n is prime and the 6th power of N is even. This means that N is clearly 2 since it is the only prime number that will result in a even number. We can now calculate the median. Sufficient
Statement 2: 2N + 14 < 20 i.e.
2N < 6 ---> N<3, N can be any below less than 3 and this will keep changing the median. Not Sufficient
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From this can we say N can be 2 or -2, how can we be sure that N is positive?
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apurvag95
From this can we say N can be 2 or -2, how can we be sure that N is positive?

A prime numbers are positive only, 2 being the smallest one.
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Bunuel
What is the median of set A {-8, 15, -9, 4, N}?

(1) N is a prime and N^6 is even
(2) 2N + 14 < 20
Write the set in order
Set A = { −9, −8, 4, 15, N }.
To find the median, we’ll need the numbers in increasing order.
[hr]
From (1): “N is a prime and N6 is even.”
If N6 is even, then N must be even (because any even number raised to any power stays even, odd → odd).
The only even prime = 2.
→ So N = 2.
Now set A = { −9, −8, 2, 4, 15 }
This is already in order.
→ Median = the 3rd number = 2.

* Statement (1) alone is sufficient.
[hr]
From (2): “2N + 14 < 20.”
Simplify → 2N < 6 → N < 3.
So N can be any number less than 3 (e.g., 2, 0, −1, −8 etc.).
If N = 2, set = { −9, −8, 2, 4, 15 } → median = 2.
If N = 0, set = { −9, −8, 0, 4, 15 } → median = 0.
Different medians possible.

* Statement (2) alone is not sufficient.
[hr]
Final Answer:
Statement (1) alone is sufficient; statement (2) alone is not.
Answer (A).
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