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22 May 2017, 14:22
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Difficulty:
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Question Stats:
92% (01:15) correct
8%
(01:51)
wrong
based on 642
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What is the perimeter of the figure above" ?
(A) 380
(B) 360
(C) 330
(D) 300
(E) 230
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kCko6To.jpg [ 7.88 KiB | Viewed 12948 times ]
22 May 2017, 14:37
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The answer is (A) 380.
The missing side is x more then 70.
To get the value of x, let us form a right triangle on the right side of the figure, which its sides are 60 and x and the hyp is 100. This is a right triangle with ratio 3:4:5. So side x to 60 is in ratio 4 to 3.
Hence, x=80 and the perimeter is 60+70+100+150=380.
Sent from my Redmi 4 using GMAT Club Forum mobile app
The missing side is x more then 70.
To get the value of x, let us form a right triangle on the right side of the figure, which its sides are 60 and x and the hyp is 100. This is a right triangle with ratio 3:4:5. So side x to 60 is in ratio 4 to 3.
Hence, x=80 and the perimeter is 60+70+100+150=380.
Sent from my Redmi 4 using GMAT Club Forum mobile app
sashiim20
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Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
Posts: 612
22 May 2017, 18:03
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carcass
What is the perimeter of the figure above" ?
(A) 380
(B) 360
(C) 330
(D) 300
(E) 230
Diagram can be cut into a rectangle and a right triangle.
Rectangle with sides 60, 70 and Right triangle with sides 100, 60 and one side unknown. Let that side be x.
Pythagorean Theorem to find x:
\(x^2\) + \(60^2\) = \(100^2\)
\(x^2\) = \(100^2\) - \(60^2\) = 6400
x = \(\sqrt{6400}\) = 80
Perimeter = 60 + 70 + 100 + 80 + 70 = 380
Answer A...
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