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# What is the perimeter of the figure above"

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Re: What is the perimeter of the figure above" [#permalink]
carcass

What is the perimeter of the figure above" ?

(A) 380

(B) 360

(C) 330

(D) 300

(E) 230

Similar question: https://gmatclub.com/forum/what-is-the- ... 24508.html
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Re: What is the perimeter of the figure above" [#permalink]
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carcass

What is the perimeter of the figure above" ?

(A) 380

(B) 360

(C) 330

(D) 300

(E) 230

Attachment:
kCko6To.jpg

Draw a perpendicular line as follows:

From here, we have two different ways to find the value of x

Approach #1: Recognize that 60 and 100 are each 20 times the lengths of the basic 3-4-5 right triangle.
That is (20)(3) = 60 and (20)(5) = 100
So, x = (20)(4) = 80

Approach #2: Apply the Pythagorean theorem
We get: 60² + x² = 100²
Simplify: 3,600 + x² = 10,000
Subtract 3,600 from both sides to get: x² = 6,400
Solve: x = 80

At this point we can find the perimeter....

Perimeter = 60 + 70 + 100 + 80 + 70 = 380

Cheers,
Brent
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Re: What is the perimeter of the figure above" [#permalink]
is it a 6-8-10 triangle since 60-x-100? therefore x = 80?

just over 2 minutes using pythagoreum :/
Re: What is the perimeter of the figure above" [#permalink]
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