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29 Dec 2020, 01:15
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What is the remainder when a three-digit integer ABC (where A, B, and C are hundreds, tens and units digits respectively) is divided by 7?
(1) 2A + 3B + C is divisible by 7
(2) Three-digit integer ABC is divisible by 49.
Are You Up For the Challenge: 700 Level Questions
(1) 2A + 3B + C is divisible by 7
(2) Three-digit integer ABC is divisible by 49.
Are You Up For the Challenge: 700 Level Questions
29 Dec 2020, 01:36
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The three digit number is
100A+10B+C
S1 : 2A+3B+C is divisible by 7
So,Subrracting the given equation from ABC
100A+10B+C -2A-3B-C = 98A+7B
Hence ABC is divisible by 7
Sufficient
S2: sufficient. If a number is divisible by 49 its obviously divisible by 7.
Answer D
Posted from my mobile device
100A+10B+C
S1 : 2A+3B+C is divisible by 7
So,Subrracting the given equation from ABC
100A+10B+C -2A-3B-C = 98A+7B
Hence ABC is divisible by 7
Sufficient
S2: sufficient. If a number is divisible by 49 its obviously divisible by 7.
Answer D
Posted from my mobile device
29 Dec 2020, 02:38
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IMO D
St 1
X is divisible by 'a' if 'y' & compound such as X+y or x-y is also divisible by 'a'
therefore, (100A+10B+C)-(2A+3B+C) = 98A + 7B = divisible by 7
hence, 100A+10B+C will also be divisible by 7
note: it is tricky to find do calculations hence, remembering the generic division rule will help in pre-thinking
st2:
straight forward we can say it is divisible by 7.
St 1
X is divisible by 'a' if 'y' & compound such as X+y or x-y is also divisible by 'a'
therefore, (100A+10B+C)-(2A+3B+C) = 98A + 7B = divisible by 7
hence, 100A+10B+C will also be divisible by 7
note: it is tricky to find do calculations hence, remembering the generic division rule will help in pre-thinking
st2:
straight forward we can say it is divisible by 7.
