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What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20?

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What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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What is the sum of all possible solutions to \(|x-3|^2 - |x-3| = 20\)?
A) -1
B) 6
C) 7
D) 12
E) 14

Source: GMAT Prep Now - http://www.gmatprepnow.com/module/gmat- ... video/1018
[Reveal] Spoiler: OA
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Re: What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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New post 16 Sep 2015, 08:51
I didn't think of using substitution on this question. I wanted to do the square of |x-3| but couldn't think of I could do that.
My question: is there a way to multiply two absolute values?
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Re: What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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skylimit wrote:
What is the sum of all possible solutions to \(|x-3|^2 - |x-3| = 20\)?
A) -1
B) 6
C) 7
D) 12
E) 14

Source: GMAT Prep Now - http://www.gmatprepnow.com/module/gmat- ... video/1018


Let, |x-3| = y

i.e. \(|x-3|^2 - |x-3| = 20\) ---> y^2 - y = 20
i.e. y(y-1) = 20
i.e. Product of two consecutive Numbers = 20
but 5*(5-1)= 20 and also (-4)*(-4-1) = 20
i.e. y = 5 or (-4)
but \(|x-3|\) can't be Negative i.e. can't be (-4)

Hence, \(|x-3| = 5\)
i.e. x = 8 or -2
Sum of these two solutions = 8+(-2) = 6

Answer: option B
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Re: What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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New post 16 Sep 2015, 11:24
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skylimit wrote:
What is the sum of all possible solutions to \(|x-3|^2 - |x-3| = 20\)?
A) -1
B) 6
C) 7
D) 12
E) 14

Source: GMAT Prep Now - http://www.gmatprepnow.com/module/gmat- ... video/1018

Important Property:\(\sqrt{x^2}=|x|\)
Since \(|x-3|=\sqrt{(x-3)^2}\), \(|x-3|^2= (x-3)^2\)
When \(x>3, |x-3|=x-3\) and when \(x<3, |x-3|=3-x\).
When \(x>3\), \((x-3)^2-(x-3)=20\) yields two solutions \(x=-1\) or \(x=8\), but since \(x=-1\) is not in the range \(x>3\), this solution should be rejected.
When \(x<3\), \((x-3)^2-(3-x)=20\) yields two solutions \(x=-2\) or \(x=7\), but since \(x=7\) is not in the range \(x<3\), this solution should be rejected.
The valid solutions are \(x=-2\) and \(x=8.\) Their sum is 6.
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Re: What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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New post 16 Sep 2015, 20:27
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skylimit wrote:
What is the sum of all possible solutions to \(|x-3|^2 - |x-3| = 20\)?
A) -1
B) 6
C) 7
D) 12
E) 14

Source: GMAT Prep Now - http://www.gmatprepnow.com/module/gmat- ... video/1018


Similar question to practice: what-is-the-sum-of-all-possible-solutions-of-the-equation-x-85988.html
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What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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New post 31 Oct 2015, 11:56
that's a very tricky one..I started to think of combinations +/+ +/- -/+ -/-, but then noticed that it can be rewritten:
|x-3|^2-20 = |x-3|
it means that |x-3| = 20
now this is more simple!!!
x-3 = 20 -> x = 23
x-3 = -20 -> x=-17
the sum is thus 6.

is my method correct, or just got the right answer by luck? :)
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Re: What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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New post 31 Oct 2015, 16:48
mvictor wrote:
that's a very tricky one..I started to think of combinations +/+ +/- -/+ -/-, but then noticed that it can be rewritten:
|x-3|^2-20 = |x-3|
it means that |x-3| = 20
now this is more simple!!!
x-3 = 20 -> x = 23
x-3 = -20 -> x=-17
the sum is thus 6.

is my method correct, or just got the right answer by luck? :)


No, your method is not correct. If you plug in x=23 or x=-17 back to the original equation, you will realize that these are not solutions to the original equation.
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Re: What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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Re: What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20? [#permalink]

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New post 18 Jan 2018, 23:00
GMATinsight wrote:
skylimit wrote:
What is the sum of all possible solutions to \(|x-3|^2 - |x-3| = 20\)?
A) -1
B) 6
C) 7
D) 12
E) 14

Source: GMAT Prep Now - http://www.gmatprepnow.com/module/gmat- ... video/1018


Let, |x-3| = y

i.e. \(|x-3|^2 - |x-3| = 20\) ---> y^2 - y = 20
i.e. y(y-1) = 20
i.e. Product of two consecutive Numbers = 20
but 5*(5-1)= 20 and also (-4)*(-4-1) = 20
i.e. y = 5 or (-4)
but \(|x-3|\) can't be Negative i.e. can't be (-4)

Hence, \(|x-3| = 5\)
i.e. x = 8 or -2
Sum of these two solutions = 8+(-2) = 6

Answer: option B


(|x-3|^2 - |x-3| = 20)
Let y = |x-3|
So, y^2 - y = 20
y^2 -y - 20 = 0
(y-5)(y+4) = 20

|x-3| = 5,-4
|x-3| = 5 as -4 is -ve and not possible
x-3 = +/- 5
x = 8, -2

Sum of values = 8 -2 = 6
[Reveal] Spoiler:
Answer B

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Re: What is the sum of all possible solutions to |x-3|^2 - |x-3| = 20?   [#permalink] 18 Jan 2018, 23:00
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