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We need to find the units digit of \(2^{105}+3^{105}+4^{105}+5^{105}?\)

Refer below image for cyclicity of units digit of number

Attachment:
Cyclicity.jpg
Cyclicity.jpg [ 127.71 KiB | Viewed 727 times ]

Units digit of \(2^{105}\)

Cycle = 4
105/4 reminder is 1
=> Units digit of \(2^{105}\) = Units digit of \(2^{1}\) = 2

Units digit of \(3^{105}\)

Cycle = 4
105/4 reminder is 1
=> Units digit of \(3^{105}\) = Units digit of \(3^{1}\) = 3

Units digit of \(4^{105}\)

Cycle = 2
105/2 reminder is 1
=> Units digit of \(4^{105}\) = Units digit of \(4^{1}\) = 4

Units digit of \(5^{105}\)

Cycle = 1
=> Units digit of \(5^{105}\) = 5

=> Units digit of \(2^{105}+3^{105}+4^{105}+5^{105}\) = Units digit of (2 + 3 + 4 + 5) = Units digit of 14 = 4

So, Answer will be B
Hope it helps!

Link to Theory for Last Two digits of exponents here.

Link to Theory for Units' digit of exponents here.
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