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What is the value of (2-1/3)(1+1/4)^(-1)(1+2/5)?

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What is the value of (2-1/3)(1+1/4)^(-1)(1+2/5)?  [#permalink]

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New post 03 Mar 2019, 13:16
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D
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Question Stats:

100% (00:59) correct 0% (00:00) wrong based on 19 sessions

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GMATH practice exercise (Quant Class 1)

What is the value of \(\left( {2 - {1 \over 3}} \right){\left( {1 + {1 \over 4}} \right)^{ - 1}}\left( {1 + {2 \over 5}} \right)\,\,\) ?

\(\eqalign{
& \left( A \right)\,\,{{15} \over {28}} \cr
& \left( B \right)\,\,{3 \over 5} \cr
& \left( C \right)\,\,{5 \over 4} \cr
& \left( D \right)\,\,{{28} \over {15}} \cr
& \left( E \right)\,\,{5 \over 3} \cr}\)

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Re: What is the value of (2-1/3)(1+1/4)^(-1)(1+2/5)?  [#permalink]

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New post 03 Mar 2019, 13:50
It was fairly simple....

The efficient way is to solve quickly so that you can concentrate more and dedicate more time on difficult question...

Never solve it completely (what I mean is do not multiply all the numerators and denominators..instead look to simplify the expression)

the above equation is equal to

(5/3) * (5/4)^-1 * (7/5)
eventually cancelling 5 we get.... 28/15

If you liked my post do not forget to give kudos. Cheers!!! Happy Learning !!!
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Re: What is the value of (2-1/3)(1+1/4)^(-1)(1+2/5)?  [#permalink]

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New post 03 Mar 2019, 15:27
fskilnik wrote:
GMATH practice exercise (Quant Class 1)

What is the value of \(\left( {2 - {1 \over 3}} \right){\left( {1 + {1 \over 4}} \right)^{ - 1}}\left( {1 + {2 \over 5}} \right)\,\,\) ?

\(\eqalign{
& \left( A \right)\,\,{{15} \over {28}} \cr
& \left( B \right)\,\,{3 \over 5} \cr
& \left( C \right)\,\,{5 \over 4} \cr
& \left( D \right)\,\,{{28} \over {15}} \cr
& \left( E \right)\,\,{5 \over 3} \cr}\)


\(\left( {2 - {1 \over 3}} \right){\left( {1 + {1 \over 4}} \right)^{ - 1}}\left( {1 + {2 \over 5}} \right)\,\,\)

\((\frac{6-1}{3})(\frac{4+1}{4})^{-1}(\frac{5+2}{5})\)

\((\frac{5}{3})(\frac{5}{4})^{-1}(\frac{7}{5})\)

\((\frac{5}{3})(\frac{4}{5})(\frac{7}{5})\)

\((\frac{4}{3})(\frac{7}{5})\)

\(\frac{28}{15}\)

Answer D
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Re: What is the value of (2-1/3)(1+1/4)^(-1)(1+2/5)?  [#permalink]

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New post 03 Mar 2019, 16:50
fskilnik wrote:
GMATH practice exercise (Quant Class 1)

What is the value of \(\left( {2 - {1 \over 3}} \right){\left( {1 + {1 \over 4}} \right)^{ - 1}}\left( {1 + {2 \over 5}} \right)\,\,\) ?

\(\eqalign{
& \left( A \right)\,\,{{15} \over {28}} \cr
& \left( B \right)\,\,{3 \over 5} \cr
& \left( C \right)\,\,{5 \over 4} \cr
& \left( D \right)\,\,{{28} \over {15}} \cr
& \left( E \right)\,\,{5 \over 3} \cr}\)

\(\,? = \left( {2 - {1 \over 3}} \right){\left( {1 + {1 \over 4}} \right)^{ - 1}}\left( {1 + {2 \over 5}} \right)\,\,\)


\(\left. \matrix{
2 - {1 \over 3} = {{2 \cdot 3} \over 3} - {1 \over 3} = {5 \over 3} \hfill \cr
1 + {1 \over 4} = {5 \over 4}\,\,\,\,\, \Rightarrow \,\,\,\,\,{\left( {1 + {1 \over 4}} \right)^{ - 1}} = {4 \over 5}\,\,\, \hfill \cr
1 + {2 \over 5} = {7 \over 5} \hfill \cr} \right\}\,\,\,\,\, \Rightarrow \,\,\,\,\,? = {5 \over 3} \cdot {4 \over 5} \cdot {7 \over 5} = {{4 \cdot 7} \over {3 \cdot 5}}\)


The correct answer is (D).


We follow the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Fabio Skilnik :: GMATH method creator (Math for the GMAT)
Our high-level "quant" preparation starts here: https://gmath.net
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Re: What is the value of (2-1/3)(1+1/4)^(-1)(1+2/5)?   [#permalink] 03 Mar 2019, 16:50
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