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Bunuel
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I choose option C:

Statement 1:
Since it is given that (Y -1) is positive integer, Y cannot be 1 or lesser than 1. Y >= 2

for Y = 2, Z = 0 as 2/1 => quotient 2 remainder 0
for Y >= 2 z = 1

Z=0, Z=1 insufficient.

Statement 2:
Statement does not say anything about Z.

insufficient.

Statement 1 & 2:
from 1
we have two scenario: if y = 2 than z = 0; if y >=2 z = 1
from 2
y not equal to 2

so y >2 and in this scenario z = 1.

Answer choice C.

OA please?
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Ans C.
statmnt 1: insufficient when y=2; however y cant be equal to 1 as y-1= 0 NOT a positive integer.
statmnt 2: Insuff.
combining together 1 & 2 we get z=1
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Answer is E

1)z is the remainder when positive integer y is divided by positive integer y-1
let y=2
so y = 1(2) + z or reminder 0
let y = 1
however if y = 1 then the denominator becomes 0 and thus Undefined or z need not be equal to 0
so INSUFFICIENT eliminate A,D

2)y is not a prime number

Says nothing about C


Insufficent eliminate B

Now both together again will give you the possiblity of Y having 1 or 4 or a grater non prime number
however any number greater than 1 gives reminder as 1 and the number 1 alone gives a undefined value
so both together also fails
eliminate C

so the Ans is E
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Bunuel

Veritas Prep 10 Year Anniversary Promo Question #7


One quant and one verbal question will be posted each day starting on Monday Sept 17th at 10 AM PST/1 PM EST and the first person to correctly answer the question and show how they arrived at the answer will win a free Veritas Prep GMAT course ($1,650 value). Winners will be selected and notified by a GMAT Club moderator. For more questions and details please check here: veritas-prep-10-year-anniversary-giveaway-138806.html

To participate, please make sure you provide the correct answer (A,B,C,D,E) and explanation that clearly shows how you arrived at it.
Winners will be announced the following day at 10 AM Pacific/1 PM Eastern Time.

What is the value of integer \(z\)?

(1) \(z\) is the remainder when positive integer y is divided by positive integer \((y - 1)\)

(2) \(y\) is not a prime number
----------------------------------------------------------------------------------------------------

The answer is A as y and z are two consec numbers and has to be 2 and 1. There are no two number which will give an integer as reminder when divided.
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statement 1 is sufficient - Y is a positive number so 1, 2,3,......... and Y-1 is also a Positive number, therefore minimum value of Y can be either 2, 3, 4, etc.
... and remainder always be 1, So value of Z is 1
statement 2- is not sufficient because there is no relation between Y an Z here.

Hence Answer will be A, Sorry for the previous answer....I just missed the the 2nd point.
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A is the answer as the statement 1 says. y and y-1 both are positive, if y is divided by y-1 then remainder is always 1. so z=1.
statement 2 is insufficient
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Ans - A

Remainder theorem-

when y /y-1
remainder = f(1)

f(y) = y
substituting the value of y =1

Therefore answer will always be 1.
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Answer: C

According to statement 1, y could be 2 or 4, which gives us different values of z; not sufficient
(2) No relation between z and y

1+2:

y should be greater than 3; therefore, y and y-1 will always have the remainder of 1.

Answer C
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What is the value of integer \(z\)?

(1) \(z\) is the remainder when positive integer y is divided by positive integer \((y - 1)\)

(2) \(y\) is not a prime number[/quote]

Lets take easier statement first.

Statement 2 just tells us that Y is not 2, 3, 5, or any other odd prime but it doesn't tell us anything about Z.

Stmt 1: Lets take Y to be 1, 2 or 3, Y-1 will be 0, 1 or 2. Y could be 0 also however since statement explicitly mentions that Y is positive integer and 0 is non negative integer, Y can not be 0.

1/0- Division by 0 is undefined in GMAT
2/1= 0 remainder
3/2= 1 remainder

Thus we have multiple answers, hence not sufficient.

Together: We know that Y is not prime, hence Y = 2 is ruled out and any other integer more then 2 divided by Int-1 will give a remainder of 1. Hence together sufficient. Answer is C.
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Answer A:

Since z is the remainder when positive integer y is divided by positive integer (y - 1), which is 1 short of y, therefore, z =1
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rajareena
What is the value of integer \(z\)?

(1) \(z\) is the remainder when positive integer y is divided by positive integer \((y - 1)\)

(2) \(y\) is not a prime number

Lets take easier statement first.

Statement 2 just tells us that Y is not 2, 3, 5, or any other odd prime but it doesn't tell us anything about Z.

Stmt 1: Lets take Y to be 1, 2 or 3, Y-1 will be 0, 1 or 2. Y could be 0 also however since statement explicitly mentions that Y is positive integer and 0 is non negative integer, Y can not be 0.

1/0- Division by 0 is undefined in GMAT
2/1= 0 remainder
3/2= 1 remainder

Thus we have multiple answers, hence not sufficient.

Together: We know that Y is not prime, hence Y = 2 is ruled out and any other integer more then 2 divided by Int-1 will give a remainder of 1. Hence together sufficient. Answer is C.[/quote]

Looking at statement 1 -

any number can be represented in the form of divisor and remainder as below:

A = K(y-1) +z .............for all the values of K
at k=1
A=y-1 +Z....................A=y hence z=1

As A=y K can never be more than 1
at y=1
1 =1-1+z...............z=1
2=2-1+z...............z=1
3=3-1+z...............z=1

Hence statement 1 is sufficient.
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We have a winner!



Winner:

AbhiJ

Official Explanation:

Answer is C

This question is a classic “Why Are You Here?” question. Statement 1 may look sufficient if you pick numbers (8 and 7; 15 and 14; 5 and 4 → the remainder is always 1). But what about 2 and 1? There’s no remainder there, so z would equal 0. This is why statement 2 is so important. Alone, it’s useless...so why is it there? Statement 2 tells us that (y - 1) cannot be 1, because y cannot be 2. This takes away that one flaw with statement 1, and means that both statements together are sufficient. But of more strategic importance, statement 2 should alert you to that problem with statement 1. Most test-takers miss that flaw when looking at statement 1 alone, but astute test-takers will reconsider once statement 2 is presented.
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Thanks a Bunch to Veritas Prep for being so generous , awarding prizes day after day.

Bb and Bunnel, you guys are doing some awesome work which makes this site a personalized experience - a GMAT-Club in true sense of the word.
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The most important thing in this problem is avoid to overlook that Y and Y-1 are consecutive non negative integer.
The division of 2 consecutive number is always 1 except in 1 case (2,1) - (1,0) non considered - therefore:
1 - Not suff. solution are 0 and 1
2 - Clearly Not suff.

1&2 Suff and Z=1
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Hello from the GMAT Club BumpBot!

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