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Bunuel
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Bunuel
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My answer is C.
(1) if y = 1 or 2 => can't determine z
(2) nothing to determine z

(1) + (2): y > 3 & y : (y-1) always has reminder 1
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Stmt 1 is not sufficient as r=1 when y= 3,4,5 and r=0 when y = 2
Stmt 2 is not suff
Combine Answer C
as y=!2 hence r is always = 1
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Answer A.

It leaves remainder 1.
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Option C.
Since y-1 is positive.. y has to be atleast 2. now for any y>2, y/y-1 will give 1 as remainder but for Y=2 remainder is 0.
however y is not prime.. so can not be 2. hence we know remainder will be 1 from above.
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Bunuel

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What is the value of integer \(z\)?

(1) \(z\) is the remainder when positive integer y is divided by positive integer \((y - 1)\)

(2) \(y\) is not a prime number

Ans: A

Z = 1

y-1 and y are two consecutive numbers. When divided it will give remainder 1
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A is sufficient as remainder will always be one when we divide two consecutive integers with the higher one as numerator.

B. doesn't lead us to any solution as what is z is not mentioned.
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Ans is C
Statement1:
for ex y=2
2/1 then remainder =0
if y=3
3/2 then remainder=1
Not sufficient
Statement2: y can be 1,4,6 ---Not sufficent
By combining both
y cannot be 2,so in all cases remainder will be 1
Hence sufficient
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Bunuel

Veritas Prep 10 Year Anniversary Promo Question #7


One quant and one verbal question will be posted each day starting on Monday Sept 17th at 10 AM PST/1 PM EST and the first person to correctly answer the question and show how they arrived at the answer will win a free Veritas Prep GMAT course ($1,650 value). Winners will be selected and notified by a GMAT Club moderator. For more questions and details please check here: veritas-prep-10-year-anniversary-giveaway-138806.html

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What is the value of integer \(z\)?

(1) \(z\) is the remainder when positive integer y is divided by positive integer \((y - 1)\)

(2) \(y\) is not a prime number


(E)
(1) INSUFF because values will be diffrent if y is even or odd so z will vary
(2) insufficient to answer the given question
together also, not possible to figure out z
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Option A.
Since y-1 is positive.. y has to be atleast 2. now for any y>=2, y/y-1 will give 1 as remainder
I had to click submit button atleast 3 times to post.. some problem with quick reply option?
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What is the value of integer ?

(1) is the remainder when positive integer y is divided by positive integer

(2) is not a prime number

the answer is E
y and y-1 is consequetive integers
so y divided by y-1 results remainder of 1 which is unknown
INSUFFICIENT
2 is clearly INSUFFICIENT
together is also INSUFFICIENT to say the value of z because when y is 1 y-1 will be 0 which cannot be the case and 1 is not a prime
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My Ans IS E-

Statement 1-z is the remainder when positive integer y is divided by positive integer (y - 1)- not sufficient the nos can vary
Statement 2- By itself also not sufficient to find Z
Together also not sufficient.
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Answer is A

(1)y/(y-1)=1+1/(y-1); since z is integer so (y-1) must be 1 or -1. But y-1>0. Then,(y-1) must be 1 => z=1=>(1)Sufficient
(2)y is not prime number is not Sufficient.
So A
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What is the value of integer ?

(1) is the remainder when positive integer y is divided by positive integer

(2) is not a prime number
_________________

Statement 1 is sufficient - Y is a positive number so 1, 2,3,......... and Y-1 is also a Positive number, therefore minimum value of Y can be either 2, 3, 4, etc.
... and remainder always be 1, So value of Z is 1
statement 2- Y is not a prime number, Since it is a positive number so it will again the number can be 4, 6 , 8, 9, 10 etc. and Y-1 will always result in 1 less than the number itself... So Remainder will be 1

And Answer is D, both are sufficient
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How can (A)??

(i) what will happen if y=1 ; y/(y-1) = 1/(1-1) = infinity
Z=infinity

(ii) no sufficient data

together also, not possible to find out z
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What is the value of integer z?

(1) z is the remainder when positive integer y is divided by positive integer (y - 1)
(2) y is not a prime number
Answer is C
1 insufficient as remainder can be 1, 2
2) insufficient
3) both sufficient


How remainder can be 2 in statement1...Obviously not possible
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My answer is C.
(1) if y = 1 or 2 => can't determine z
(2) nothing to determine z

(1) + (2): y > 3 & y : (y-1) always has reminder 1


If y=1,then y-1=0, which cannot be a postive integer
Hence u contradicted the st1
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Numbers of the form (y,y-1) are called coprimes because they have only 1 common factor and that is 1. The only scenario when y divided by y-1 will give a remainder 0 is when y is 2 but since statement says that, y cannot be a prime number. So both the statements together are sufficient to answer the question.
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