Bunuel wrote:
GMAT Club Tests' FRESH Question:
What is the value of x?
(1) \(x = \frac{1}{x^2}\)
(2) \(|x| = \frac{1}{x}\)
as x is in the denominator \(x\neq{0}\)
(1) \(x = \frac{1}{x^2}\)..
\(x = \frac{1}{x^2}..................x^3=1..........x=1\).
we could cross multiply as x^2 > 0sufficient
(2) \(|x| = \frac{1}{x}\)
since |x|>0....\(\frac{1}{x}>0..........x>0\)...
so \(x^2=1......x=1\)
suff
D
I think we can multiply easily because it is equality. even if the denominator is negative it is multiplied without problem,
close
58% (01:11) correct 
