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Bunuel
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What is the value of x? 27 Jan 2015, 07:35
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C
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58% (01:17) correct 42% (01:02) wrong based on 581 sessions

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What is the value of x?

(1) (x)(x + 1) = (2013)(2014)

(2) x is odd
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C
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Bunuel
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What is the value of x? 02 Feb 2015, 02:28
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Bunuel
What is the value of x?

(1) (x)(x + 1) = (2013)(2014)

(2) x is odd

Kudos for a correct solution.
Show more

VERITAS PREP OFFICIAL SOLUTION:

C. This problem is a classic example of the "Why Are You Here" strategy. Clearly statement 2 is not sufficient on its own, so why was it written?

In statement 1, the "obvious" answer for x is that x = 2013 and (x + 1) would then equal 2014. Which looks pretty sufficient. But there's one additional, not as obvious possibility: x = -2014 and (x + 1) = -2013. Since negative-times-negative is positive, that would give the same result. So statement 1 looks pretty sufficient but it is not. Statement 2 provides that little clue by emphatically stating that x is odd. That should get you thinking "how could x not be odd?" and of course that would be if x were -2014 and x + 1 were -2013. With both statements together, that negative-negative possibility is off the table, so the correct answer is C.
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What is the value of x? 27 Jan 2015, 09:59
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ans C....
1) statement one tells us that x is either -2014 or 2013....insfficient
2) statement 2 tells us that it is odd..insufficient
combined it tells us that it is 2013
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What is the value of x? 25 Feb 2016, 01:19
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Bunuel
What is the value of x?

(1) (x)(x + 1) = (2013)(2014)

(2) x is odd

Kudos for a correct solution.
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This is classic question in which you can be trapped easily.
The questions seems easy but there is a little catch involved here.

Statement 1: (x)(x + 1) = (2013)(2014)
If directly seems that the equation means x = 2013 and (x + 1) 2014
But x can be - 2014 and (x+1) can be - 2013
Hence x has two values.
INSUFFICIENT

Statement 2: x is odd.
This in itself does not tell us anything.

Combining statement 1 and 2:
We are left with just one value of x: 2013
SUFFICIENT

Option C
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What is the value of x? 28 Feb 2017, 00:14
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Bunuel
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What is the value of x?

(1) (x)(x + 1) = (2013)(2014)

(2) x is odd

Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

C. This problem is a classic example of the "Why Are You Here" strategy. Clearly statement 2 is not sufficient on its own, so why was it written?

In statement 1, the "obvious" answer for x is that x = 2013 and (x + 1) would then equal 2014. Which looks pretty sufficient. But there's one additional, not as obvious possibility: x = -2014 and (x + 1) = -2013. Since negative-times-negative is positive, that would give the same result. So statement 1 looks pretty sufficient but it is not. Statement 2 provides that little clue by emphatically stating that x is odd. That should get you thinking "how could x not be odd?" and of course that would be if x were -2014 and x + 1 were -2013. With both statements together, that negative-negative possibility is off the table, so the correct answer is C.
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This link help will help one understand the "Why Are You Here" strategy https://youtu.be/eY_MIpioA8M :)
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What is the value of x? 25 Jul 2020, 05:00
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Bunuel
What is the value of x?

(1) (x)(x + 1) = (2013)(2014)

(2) x is odd

Kudos for a correct solution.
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x = ?

(1) x(x + 1) = 2013.2014 <=> x^2 + x - 2013.2014 = 0 <=> (x + 2014)(x - 2013) = 0 --> x = -2014 or x = 2013. Insufficient.
(2) x is odd. x can be any odd number. Insufficient.

(1) + (2) --> x = 2013. Sufficient. Answer (C).
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What is the value of x? 29 Jul 2020, 11:37
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Bunuel
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What is the value of x?

(1) (x)(x + 1) = (2013)(2014)

(2) x is odd

Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

C. This problem is a classic example of the "Why Are You Here" strategy. Clearly statement 2 is not sufficient on its own, so why was it written?

In statement 1, the "obvious" answer for x is that x = 2013 and (x + 1) would then equal 2014. Which looks pretty sufficient. But there's one additional, not as obvious possibility: x = -2014 and (x + 1) = -2013. Since negative-times-negative is positive, that would give the same result. So statement 1 looks pretty sufficient but it is not. Statement 2 provides that little clue by emphatically stating that x is odd. That should get you thinking "how could x not be odd?" and of course that would be if x were -2014 and x + 1 were -2013. With both statements together, that negative-negative possibility is off the table, so the correct answer is C.
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Hi, what if I prime factorize 2013 = 3 x 671 and multiply either of the values in 2014, lets say 3.
Then it becomes, 671(2014x3 + 3),
= 671(6045)
= 671(60444 + 1)
Then, similarly with retaining 3 only as both are odd, will give 2 values of x.
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What is the value of x? 29 Jul 2020, 11:42
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Bunuel
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What is the value of x?

(1) (x)(x + 1) = (2013)(2014)

(2) x is odd

Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

C. This problem is a classic example of the "Why Are You Here" strategy. Clearly statement 2 is not sufficient on its own, so why was it written?

In statement 1, the "obvious" answer for x is that x = 2013 and (x + 1) would then equal 2014. Which looks pretty sufficient. But there's one additional, not as obvious possibility: x = -2014 and (x + 1) = -2013. Since negative-times-negative is positive, that would give the same result. So statement 1 looks pretty sufficient but it is not. Statement 2 provides that little clue by emphatically stating that x is odd. That should get you thinking "how could x not be odd?" and of course that would be if x were -2014 and x + 1 were -2013. With both statements together, that negative-negative possibility is off the table, so the correct answer is C.

Hi, what if I prime factorize 2013 = 3 x 671 and multiply either of the values in 2014, lets say 3.
Then it becomes, 671(2014x3 + 3),
= 671(6045)
= 671(60444 + 1)
Then, similarly with retaining 3 only as both are odd, will give 2 values of x.
Show more

What are two odd values of x which satisfy (x)(x + 1) = (2013)(2014)?

(x)(x + 1) = (2013)(2014) has two solutions for x, one is even (x = -2014) and another is odd (x = 2013).
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What is the value of x? 18 Dec 2021, 08:10
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Bunuel
What is the value of x?

(1) (x)(x + 1) = (2013)(2014)

(2) x is odd

Kudos for a correct solution.
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Target question: What is the value of x?

Statement 1: (x)(x + 1) = (2013)(2014)
At first glance, statement 1 looks sufficient. However, there are two possible values of x:
Case a: x = 2013 and x+1 = 2014. In this case, the answer to the target question is x = 2013
Case b: x = -2014 and x+1 = -2013. In this case, the answer to the target question is x = -2014
Since we can’t answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: x is odd
Definitely NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 indirectly tells us that EITHER x = 2013 OR x = -2014
Statement 2 tells us that x is odd
In order for both statements to be true, it must be the case that x = 2013
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer: C
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What is the value of x? 22 Apr 2025, 11:31
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