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20 Jun 2020, 22:57
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
43% (01:19) correct
57%
(01:11)
wrong
based on 99
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of x?
(1) \(6-2x=|x-6|\)
(2) \(x(x-1)=0\)
New question !!
(1) \(6-2x=|x-6|\)
(2) \(x(x-1)=0\)
New question !!
(1) Either, 6-2x = x-6; Here x = 4, but this is not valid as 6-2x>=0
Therefore, 6-2x = -(x-6); Here x = 0
Sufficient
(2) x=0, or 1
Insufficient
(1) + (2)
x=0
Sufficient
Answer: A
*Edited, thanks uchihaitachi you are right!
Therefore, 6-2x = -(x-6); Here x = 0
Sufficient
(2) x=0, or 1
Insufficient
(1) + (2)
x=0
Sufficient
Answer: A
*Edited, thanks uchihaitachi you are right!
21 Jun 2020, 00:39
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Statement B:
\(x(x-1)=0\)
x = 0 or x = 1
Insufficient
Statement A:
Since we have a modulus, so there will be two cases.
Case 1 x < 6
\(6 - 2x = -(x-6)\)
\(6-2x = -x + 6\)
\(3x = 0\)
\(x=0\) Since x should be < 6. This satisfies.
Case 1 x > 6
\(6 - 2x = (x-6)\)
\(6-2x = x - 6\)
\(3x = 12\)
\(x=4\) Since x should be greater than 6 This does not satisfy.
Sufficient
OA, A
\(x(x-1)=0\)
x = 0 or x = 1
Insufficient
Statement A:
Since we have a modulus, so there will be two cases.
Case 1 x < 6
\(6 - 2x = -(x-6)\)
\(6-2x = -x + 6\)
\(3x = 0\)
\(x=0\) Since x should be < 6. This satisfies.
Case 1 x > 6
\(6 - 2x = (x-6)\)
\(6-2x = x - 6\)
\(3x = 12\)
\(x=4\) Since x should be greater than 6 This does not satisfy.
Sufficient
OA, A
chetan2u
