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# What is the value of x + y? (1) x + 2 = 5 - y (2) (x + y)^2 = 9

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Math Expert
Joined: 02 Sep 2009
Posts: 47946
What is the value of x + y? (1) x + 2 = 5 - y (2) (x + y)^2 = 9  [#permalink]

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10 Jul 2018, 22:05
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Difficulty:

25% (medium)

Question Stats:

73% (00:24) correct 27% (00:51) wrong based on 33 sessions

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What is the value of x + y?

(1) x + 2 = 5 - y

(2) (x + y)^2 = 9

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What is the value of x + y? (1) x + 2 = 5 - y (2) (x + y)^2 = 9  [#permalink]

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10 Jul 2018, 22:14
1
To find the value of x + y

Statement 1

$$x + 2 = 5 - y$$

=> $$x + y = 5 - 2$$

=> $$x + y = 3$$

Statement 1 sufficient

Statement 2

$$(x+y)^{2} = 9$$

=> $$x + y = 3$$ or $$x + y = -3$$

Statement 2 not sufficient

Hence option A
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Re: What is the value of x + y? (1) x + 2 = 5 - y (2) (x + y)^2 = 9  [#permalink]

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10 Jul 2018, 22:22
Bunuel wrote:
What is the value of x + y?

(1) x + 2 = 5 - y

(2) (x + y)^2 = 9

St1 yields only one value of (x+y), so sufficient.

In st2, (x+y) is a square term, so (x+y) has two values. So, insufficient.

Ans.(A)
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Re: What is the value of x + y? (1) x + 2 = 5 - y (2) (x + y)^2 = 9  [#permalink]

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11 Jul 2018, 20:31
From statement 1:

x+2=5−y

=> x+y=5−2

=> x+y=3

Sufficient

From statement 2:

(x+y)^2=9

=> x+y=3 or x+y=-3
not sufficient

Hence A

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Re: What is the value of x + y? (1) x + 2 = 5 - y (2) (x + y)^2 = 9 &nbs [#permalink] 11 Jul 2018, 20:31
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