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When a class of n students is divided into groups of 6 students each,

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When a class of n students is divided into groups of 6 students each, [#permalink]

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New post Updated on: 15 Mar 2018, 08:39
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When a class of n students is divided into groups of 6 students each, 2 students are left without a group. When the class is divided into groups of 8 students each, 4 students are left without a group. What is the smallest number of students that can be added to or removed from the class so that the resulting number of students can be equally divided into groups of 12 students each?

(A) 2
(B) 4
(C) 8
(D) 10
(E) 12
[Reveal] Spoiler: OA

Originally posted by jwin125 on 14 Mar 2018, 18:54.
Last edited by Bunuel on 15 Mar 2018, 08:39, edited 3 times in total.
added choices and OA
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Re: When a class of n students is divided into groups of 6 students each, [#permalink]

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jwin125 wrote:
When a class of n students is divided into groups of 6 students each, 2 students are left without a group. When the class is divided into groups of 8 students each, 4 students are left without a group. What is the smallest number of students that can be added to or removed from the class so that the resulting number of students can be equally divided into groups of 12 students each?



Please follow the rules and so not miss out on giving choices..

Our requirement is that the final number has to be MULTIPLE of 3 and 4

Given..
\(n=6x+2\)... so n is a multiple of 2 but not of 3... Example 2,8,14,20,26,32,38,44,50
\(n=8y+4\)... n is surely a multiple of 4.. example 4,12,20,28,36,44,52

So numbers are \(20+24a...\)
Also we can get this from (FIRSTCommon Number+LCM of 6,8)

When you divide (20+24a) by 12, 24a is div by 12 and 20 gives a remainder of 8..
So we can add 4 or remove 8 to get n div by 12..
Least is 4..
Ans is 4
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Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html


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Re: When a class of n students is divided into groups of 6 students each,   [#permalink] 14 Mar 2018, 19:22
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