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jwin125
When a class of n students is divided into groups of 6 students each, 2 students are left without a group. When the class is divided into groups of 8 students each, 4 students are left without a group. What is the smallest number of students that can be added to or removed from the class so that the resulting number of students can be equally divided into groups of 12 students each?

(A) 2
(B) 4
(C) 8
(D) 10
(E) 12


Usually these questions follow a simple pattern and life would be easier if you follow them .
n=6a+2 => so the number would be 2,8,14,20
n=8b+4 => so the numbers could be 4,12,20

Since 20 is the first common number, n will be 20 .
Add 4 to make it divisible by 12.
so the answer is 4 i.e. (B)
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jwin125
When a class of n students is divided into groups of 6 students each, 2 students are left without a group. When the class is divided into groups of 8 students each, 4 students are left without a group. What is the smallest number of students that can be added to or removed from the class so that the resulting number of students can be equally divided into groups of 12 students each?

(A) 2
(B) 4
(C) 8
(D) 10
(E) 12

n=6q+2
n=8p+4
→3q-4p=1
least values of q and p are 3 and 2 respectively
n=20
(2*12)-20=4
B
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jwin125
When a class of n students is divided into groups of 6 students each, 2 students are left without a group. When the class is divided into groups of 8 students each, 4 students are left without a group. What is the smallest number of students that can be added to or removed from the class so that the resulting number of students can be equally divided into groups of 12 students each?

(A) 2
(B) 4
(C) 8
(D) 10
(E) 12

k=6q+2
k=8n+4

So what are the multiples of 6 which has 2 remainder when devided by 6 ?
they are 8, 14, 20

What are the multiples of 8 which has 4 remainder when devided by 8?
they are 12, 20, 28

As you can see 20 is the same in both cases, so let's consider k as a 20

So, what is lowest value that should be added/minused so that it can be divided by 12

of course 4, becuase 20+4=24 and it can be divided by twelve.

answer 4
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