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Sub 505 (Easy)|   Fractions and Ratios|                                 
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When n liters of fuel was added to a tank that was already 1/3 full 07 May 2021, 11:44
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naveenhv
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?


A. \(\frac{10}{9} n\)

B. \(\frac{4}{3} n\)

C. \(\frac{3}{2} n\)

D. \(\frac{9}{4} n\)

E. \(\frac{7}{3}n\)
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Solution:

We can let the full capacity of the tank be C liters and create the equation:

1/3 C + n = 7/9 C

3/9 C + n = 7/9 C

n = 4/9 C

9/4 n = C

Answer: D
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When n liters of fuel was added to a tank that was already 1/3 full 07 May 2021, 21:59
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naveenhv
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?


A. \(\frac{10}{9} n\)

B. \(\frac{4}{3} n\)

C. \(\frac{3}{2} n\)

D. \(\frac{9}{4} n\)

E. \(\frac{7}{3}n\)
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Answer: Option D

Video solution by GMATinsight

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When n liters of fuel was added to a tank that was already 1/3 full 28 May 2021, 06:02
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Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
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When n liters of fuel was added to a tank that was already 1/3 full 24 Jun 2022, 05:15
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Let the capacity of the tank be x.

Thus, 1/3*x + n = 7/9*x
n = 7/9*x - 1/3*x
n = 4/9*x
Thus, x = 9/4*n

The correct option is D.
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When n liters of fuel was added to a tank that was already 1/3 full 26 Feb 2026, 19:10
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Is this because when you multiply 9/4 * 4, the 4s cancel out and you're left with the standalone 9?
Bunuel


Say the capacity of the tank is 9 liters;

So, there are already 3 liters (1/3*9=3) of fuel and after adding n liters there are 7 liters (7/9*9=7) --> 3+n=7 --> n=4 --> capacity=9=n*9/4.

Or just plug n=4 in the answer choices to see which option yields 9, answer choice D fits: 9/4*4=9.

Answer: D.
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When n liters of fuel was added to a tank that was already 1/3 full 26 Feb 2026, 21:46
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WB332026
Is this because when you multiply 9/4 * 4, the 4s cancel out and you're left with the standalone 9?

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Yes. The 4s cancel, leaving 9.
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