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# When n liters of fuel was added to a tank that was already 1/3 full

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Manager
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20 Apr 2012, 05:55
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When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. $$\frac{10}{9} n$$

B. $$\frac{4}{3} n$$

C. $$\frac{3}{2} n$$

D. $$\frac{9}{4} n$$

E. $$\frac{7}{3}n$$
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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20 Apr 2012, 07:03
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naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

Say the capacity of the tank is 9 liters;

So, there are already 3 liters (1/3*9=3) of fuel and after adding n liters there are 7 liters (7/9*9=7) --> 3+n=7 --> n=4 --> capacity=9=n*9/4.

Or just plug n=4 in the answer choices to see which option yields 9, answer choice D fits: 9/4*4=9.

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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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20 Apr 2012, 06:06
9
3

To solve this problem, draw diagram or use algebra. I'm more comfortable with algebra.

Given
- tank was already 1/3 full.
- When n ltr added, it became 7/9

So 1/3 + n = 7/9
n = 7/9 - 3/9
n = 4/9

capacity of the tank is full fraction . i.e. 1 i.e. 9/9

so the question is 9/9 is how much times n
= 9/9 = 1 = xn

so x = 9/4

and total = 9/4n
##### General Discussion
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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20 Apr 2012, 07:15
1
Or you can also solve it another way, check for the integer, which is divisible by both the fractions, here we can take 18 liters as the capacity of the tank.

Then 1/3 of fuel is 6 liters, and 7/9 capacity will be 14 liters. From this we can get the n value as n = 14-6 = 8.
Try to substitute this value in the below options and only option 'D' get the value of 18 as the total capacity.
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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20 Apr 2012, 07:19
1
mission2009 wrote:
Or you can also solve it another way, check for the integer, which is divisible by both the fractions, here we can take 18 liters as the capacity of the tank.

Then 1/3 of fuel is 6 liters, and 7/9 capacity will be 14 liters. From this we can get the n value as n = 14-6 = 8.
Try to substitute this value in the below options and only option 'D' get the value of 18 as the total capacity.

The lowest value for the capacity for which 1/3*capacity and 7/9*capacity are integers is 9 (LCM of 3 and 9). Refer to the solution above.
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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20 Jul 2016, 12:14
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1
Here are a couple of video explanations for this question.

Algebra:

Value Substitution:

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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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20 Jul 2016, 14:08
1
let capacity=9/9
9/9-3/9-2/9=4/9=n
(9/9)/(4/9)=9/4
capacity=9/4 n
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 Jan 2017, 10:27
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Top Contributor
1
What if :
7/9-1-3 = n
=>, 4/9 capacity = n
so full capacity = 9n/4
Ans. D
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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20 Feb 2017, 17:15
1
2
Also, we can answer it this way,

1/3*c+n=7/9*c
c/3+n=7c/9
n=7c/9-c/3
n=4c/9

The question asked is what is the capacity of the tank, in liters? so here as we have already considered C as the capacity of the tank.
C=9/4*n which is the option D.
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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26 Jan 2019, 14:39
1
naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

N liters added to a tank 1/3 full, equals 7/9 of its capacity, which translates to:

n + 1/3c = 7/9c
n + 3/9c = 7/9c
n = 7/9c - 3/9c
n = 4/9c

To make in terms of n, multiple both sides by 9/4.
c = 9/4n

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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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26 Jan 2019, 14:44
naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

When you see variables in the answer choices, use smart numbers.

Suppose that the capacity of the tank is 27 liters. (I chose 27 because it's divisible by the other numbers in the problem). In that case, the tank already contained 9 liters, and when we added a certain amount, it was filled to 7/9(27), or 21 liters. That means n = 21-9 = 12.

So, n = 12, and the capacity is 27. Try plugging 12 into the answer choices, and see whether you end up with 27.

(A) 10/9(12) isn't an integer!
(B) 4/3(12) = 16 - too small
(C) 3/2(12) = 18 - too small
(D) 9/4(12) = 27 - perfect!
(E) 7/3(12) = 28 - too big
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 03:09
naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

Hello Experts,
EMPOWERgmatRichC, VeritasKarishma, IanStewart, chetan2u, ArvindCrackVerbal, GMATGuruNY, GMATinsight
Can I say the 'numerator' has to be 'factor' or 'multiple' of 9 (if 9 is considered as total capacity of anything) in the correct choices?
Also, in the choices A, B, and C says: the capacity is a bit greater than that we add (n), but in choices D and E says: the capacity is a bit more than double that we add (n). Could you explain a bit what's going on the answer choices?
Thanks__
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 03:34
naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

Hello Experts,
EMPOWERgmatRichC, VeritasKarishma, IanStewart, chetan2u, ArvindCrackVerbal, GMATGuruNY, GMATinsight
Can I say the 'numerator' has to be 'factor' or 'multiple' of 9 (if 9 is considered as total capacity of anything) in the correct choices?
Also, in the choices A, B, and C says: the capacity is a bit greater than that we add (n), but in choices D and E says: the capacity is a bit more than double that we add (n). Could you explain a bit what's going on the answer choices?
Thanks__

I don't find anything wrong with the option choices.

1) No, we can NOT say that numerator has to be a multiple of 9 because question doesn't mention that n is an Integer

2) when n is added to it when it was 1/3rd full confirms that the n is less than 2/3rd the capacity so all that we can conclude here is that n < (2/3) capacity i.e. capacity > 1.5n and using this we can eliminate Options A B and C. But to arrive at correct answer, we need to solve it as needed and that's not difficult in this question.

I hope this help
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 03:43
1
1
naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

Hello Experts,
EMPOWERgmatRichC, VeritasKarishma, IanStewart, chetan2u, ArvindCrackVerbal, GMATGuruNY, GMATinsight
Can I say the 'numerator' has to be 'factor' or 'multiple' of 9 (if 9 is considered as total capacity of anything) in the correct choices?
Also, in the choices A, B, and C says: the capacity is a bit greater than that we add (n), but in choices D and E says: the capacity is a bit more than double that we add (n). Could you explain a bit what's going on the answer choices?
Thanks__

Hi,
As GMATinsight has also written, you cannot take the numerator to be 9.
Every capacity will have 7/9 of itself, even if it is fraction. This is different from saying 7/9 of an integer gives you another integer. Yes, here n will be multiple of 9.

Having said that, 1/3 should immediately tell you that it looks a bit like 7/9, so convert 1/3 to 3/9.
Now after adding n litres 3/9 goes to 7/9 or a jump of 4/9 of capacity.
That is n=(4/9) of capacity. Capacity=9n/4
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 04:25
chetan2u wrote:
naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

Hello Experts,
EMPOWERgmatRichC, VeritasKarishma, IanStewart, chetan2u, ArvindCrackVerbal, GMATGuruNY, GMATinsight
Can I say the 'numerator' has to be 'factor' or 'multiple' of 9 (if 9 is considered as total capacity of anything) in the correct choices?
Also, in the choices A, B, and C says: the capacity is a bit greater than that we add (n), but in choices D and E says: the capacity is a bit more than double that we add (n). Could you explain a bit what's going on the answer choices?
Thanks__

Hi,
As GMATinsight has also written, you cannot take the numerator to be 9.
Every capacity will have 7/9 of itself, even if it is fraction. This is different from saying 7/9 of an integer gives you another integer. Yes, here n will be multiple of 9.

Having said that, 1/3 should immediately tell you that it looks a bit like 7/9, so convert 1/3 to 3/9.
Now after adding n litres 3/9 goes to 7/9 or a jump of 4/9 of capacity.
That is n=(4/9) of capacity. Capacity=9n/4

Thanks for the feedback.
But, if we let the capacity is 9, then we can think of n+3=7 which says that n=4 (here n is not multiple of 9 ). Can you clarify where I've missed?
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 04:45
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Can I say the 'numerator' has to be 'factor' or 'multiple' of 9 (if 9 is considered as total capacity of anything) in the correct choices?

'Factor' and 'multiple' mean opposite things. 7 is a 'factor' of 35, while 35 is a 'multiple' of 7. You can't use those words interchangeably.

Yes, in this question, the number in the numerator of the right answer must be a factor of 9 (the above replies aren't correct on that point, or are answering a different question) but you need to solve almost the whole problem to see that, so I'm not sure there's any great advantage to the observation.

I don't understand your question about the answer choices: some answers (A, B and C) suggest n is more than half a tank, some (D and E) suggest n is less than half a tank. If you can see from the fractions in the question that n represents less than half a tank, you can get down to D or E, but seeing that takes about as much time as just solving the problem, and then you don't need to guess at all.
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 05:39
IanStewart wrote:
Yes, in this question, the number in the numerator of the right answer must be a factor of 9 (the above replies aren't correct on that point, or are answering a different question) but you need to solve almost the whole problem to see that, so I'm not sure there's any great advantage to the observation.

Yes, I am just talking about THIS specific question. My observation could not be correct in all cases, probably.
IanStewart wrote:
I don't understand your question about the answer choices: some answers (A, B and C) suggest n is more than half a tank, some (D and E) suggest n is less than half a tank.

So far I know that GMAC does not make any any answer options randomly-they definitely have logic how they make answer option.
Choices D (9/4=2.something) and E (7/3=2.something) are more than 2 (apart from the value of n), but in choices A (10/9=1.something), B (4/3=1.something) and C (3/2=1.something). I've just curiosity why three answer options are a bit greater than 1 and the remaining two are greater than 2.

IanStewart wrote:
If you can see from the fractions in the question that n represents less than half a tank, you can get down to D or E, but seeing that takes about as much time as just solving the problem, and then you don't need to guess at all

Yes, get it....
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 05:50
naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

let total capacity of tank be 27
so when n liters was added tank was already 1/3rd full ; ie 9 liters
and tank was filled to 7/9 * 27 ; 21 liters
so value of n is 21-9 ; 12 liters
with option D we get ; 9/4 * 12 = 27 ( total capacity of tank)
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 05:54
chetan2u wrote:
naveenhv wrote:
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?

A. 10/9 n
B. 4/3 n
C. 3/2 n
D. 9/4 n
E. 7/3n

Hello Experts,
EMPOWERgmatRichC, VeritasKarishma, IanStewart, chetan2u, ArvindCrackVerbal, GMATGuruNY, GMATinsight
Can I say the 'numerator' has to be 'factor' or 'multiple' of 9 (if 9 is considered as total capacity of anything) in the correct choices?
Also, in the choices A, B, and C says: the capacity is a bit greater than that we add (n), but in choices D and E says: the capacity is a bit more than double that we add (n). Could you explain a bit what's going on the answer choices?
Thanks__

Hi,
As GMATinsight has also written, you cannot take the numerator to be 9.
Every capacity will have 7/9 of itself, even if it is fraction. This is different from saying 7/9 of an integer gives you another integer. Yes, here n will be multiple of 9.

Having said that, 1/3 should immediately tell you that it looks a bit like 7/9, so convert 1/3 to 3/9.
Now after adding n litres 3/9 goes to 7/9 or a jump of 4/9 of capacity.
That is n=(4/9) of capacity. Capacity=9n/4

Thanks for the feedback.
But, if we let the capacity is 9, then we can think of n+3=7 which says that n=4 (here n is not multiple of 9 ). Can you clarify where I've missed?

But why should n be a multiple of 9? You are taking the capacity to be 9, so how can anything less than 9 be a multiple of 9. n will of course be less than total capacity that is 9.

You are mixing up n and the capacity
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Re: When n liters of fuel was added to a tank that was already 1/3 full  [#permalink]

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08 May 2020, 06:04
chetan2u wrote:
chetan2u wrote:

Hi,
As GMATinsight has also written, you cannot take the numerator to be 9.
Every capacity will have 7/9 of itself, even if it is fraction. This is different from saying 7/9 of an integer gives you another integer. Yes, here n will be multiple of 9.

Having said that, 1/3 should immediately tell you that it looks a bit like 7/9, so convert 1/3 to 3/9.
Now after adding n litres 3/9 goes to 7/9 or a jump of 4/9 of capacity.
That is n=(4/9) of capacity. Capacity=9n/4

Thanks for the feedback.
But, if we let the capacity is 9, then we can think of n+3=7 which says that n=4 (here n is not multiple of 9 ). Can you clarify where I've missed?

But why should n be a multiple of 9? You are taking the capacity to be 9, so how can anything less than 9 be a multiple of 9. n will of course be less than total capacity that is 9.

You are mixing up n and the capacity

Actually i raised this question for the highlighted part. You said Yes, here n will be multiple of 9.. I don't know why did you say Yes, here n will be multiple of 9. It gets me confused
Thanks chetan2u
Re: When n liters of fuel was added to a tank that was already 1/3 full   [#permalink] 08 May 2020, 06:04

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