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When positive integer n is divided by 3, the remainder is 2; and when

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When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15 ?

(1) n - 2 is divisible by 5.
(2) t is divisible by 3.

Originally posted by priyankur_saha@ml.com on 16 Mar 2009, 22:28.
Last edited by Bunuel on 20 Oct 2019, 01:25, edited 4 times in total.
Renamed the topic and edited the question.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 01 Nov 2009, 13:07
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When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

(1) n-2 is divisible by 5.
(2) t is divisible by 3.

From the stem: \(n=3p+2\) and \(t=5q+3\).
\(nt=15pq+9p+10q+6\), we should find the remainder when this expression is divided by 15.

(1) \(n-2=5m\) --> \(n=5m+2=3p+2\) --> \(5m=3p\), \(15m=9p\) --> \(nt=15pq+9p+10q+6=15pq+15m+10q+6\). Clearly \(15pq\) and \(15m\) are divisible by 15, so remainder by dividing these components will be 0. But we still know nothing about \(10q+6\). Not sufficient.

(2) t is divisible by 3 means that \(5q+3\) is divisible by 3 --> 5q is divisible by 3 or q is divisible by 3 --> \(5q=5*3z=15z\) --> \(10q=30z\) --> \(nt=15pq+9p+10q+6=15pq+9p+30z+6\). \(15pq\) and \(30z\) are divisible by 15. Know nothing about \(9p+6\). Not sufficient.

(1)+(2) \(9p=15m\) and \(10q=30z\) --> \(nt=15pq+9p+10q+6=15pq+15m+30z+6\). Remainder when this expression is divided by 15 is 6. Sufficient.

Answer: C.

OR:

From the stem: \(n=3p+2\) and \(t=5q+3\).

(1) n-2 is divisible by 5 --> \(n-2=5m\) --> \(n=5m+2\) and \(n=3p+2\) --> general formula for \(n\) would be \(n=15k+2\) (about deriving general formula for such problems at: good-problem-90442.html#p723049 and manhattan-remainder-problem-93752.html#p721341) --> \(nt=(15k+2)(5q+3)=15*5kq+15*3k+10q+6\) --> first two terms are divisible by 15 (\(15*5kq+15*3k\)) but we don't know about the last two terms (\(10q+6\)). Not sufficient.

(2) t is divisible by 3 --> \(t=3r\) and \(t=5q+3\) --> general formula for \(t\) would be \(t=15x+3\) --> \(nt=(3p+2)(15x+3)=15*3px+9p+15*2x+6\). Not sufficient.

(1)+(2) \(nt=(15k+2)(15x+3)=15*15kx+15*3k+15*2x+6\) this expression divided by 15 yields remainder of 6. Sufficient.

Answer: C.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 01 Oct 2009, 00:06
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This solution is only detailed for better understanding. Hope it helps....

n = 3a + 2
t = 5b + 3
What is the remainder when nt/15?

1) n-2 is divisible by 5
2) t is divisible by 3

1) n - 2 is divisible by 5.

n = 3a + 2
n - 2 = 3a
3a is divisible by 5 and therefore by 15

nt = 3a(5b + 3) + 2(5b + 3)
=15ab + 9a + 10b + 6
15ab and 9a are divisible by 15,
10b: no info from (1)
INSUFFICIENT

2) t = 5b + 3,
so 5b is divisible by 3 and therefore, by 15.

nt = 15ab + 9a + 10b + 6
10b is divisible by 15
15ab and 9a: no info from (2)
INSUFFICIENT

When you combine (1) and (2)...
15ab, 9a, and 10b are divisible by 15.
Therefore, nt = 15ab + 9a + 10b + 6
=15(x) + 6

C.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 01 Oct 2009, 08:06
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Here is one other way of solving the problem.

It is given in the question stem -

n when divided by 3 leaves a remainder 2 ==> n-2 is divisible by 3.
t when divided by 5 leaves a remainder 3 ==> t-3 is divisible by 5.

Question being asked is what is the remainder when nt is divided by 15.

Clue 1 ==> it is given n-2 is divisible by 5 and from given information, we know n-2 is also divisible by 2 ==> n-2 is divisible by 15. But nothing is mentioned abt t. Hence insufficient clue.

Clue 2 ==> it is given t is divisible by 3, we can derive that t-3 is also divisible by 3. From the given information, we know t-3 is divisble by 5 ==> t-3 is divisible by 3 and 5 ==> t-3 is divisible by 15. Nothing is mentioned abt n. Hence insufficient clue.

Combine both the clues

n-2 = 15a ==> n = 15a + 2
t-3 = 15b ==> t = 15b + 3

nt = (15a + 2)(15b + 3) ==> 15.15.a.b + 15.3.a + 15.2.b + 6

Clearly first 3 terms are divisible by 15. So the remainder should be 6.

Hence both the clues are sufficient to say the remainder of nt.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 01 Dec 2009, 18:44
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I think plugging numbers is the easiest way to do this.

This question is about pattern recognition.
By listing out the possible solutions for each, you can see a definite pattern.

Possible Solutions for n given stem- 2, 5,8,11,14,17,20,23,26,29,32,35,38,41...
Possible solutions for t given stem- 3,8,13,18,23,28,33,38,43,48,53,58...

I. Using n-2 is divisble by 5, you get n=17,32,47..., notice the difference is 15, meaning each remainder will be the same when multiplying (Note that it is important that they specify integers)
However this gives us no indication as to the remainder of t - Insuff

II Using t is divisible by 3, you get t=3,18,33,48... again, the difference is 15, meaning each remainder will be the same.
No indication of n- insuff

You know that each remainder will be the same (in this case 6), C is suff since each individual number when divided by 15 will give the same remainder.

Thoughts?
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 28 Nov 2010, 17:36
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hogwarts wrote:
Saw this question on a GMATPrep test, and I can't figure out how to get to the correct answer. Can anyone help? :-) Thanks!

When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

(1) n-2 is divisible by 5.
(2) t is divisible by 3.

The correct answer is (C) - both statements together are sufficient, but neither statement alone is sufficient. Can anybody out there help explain to me how to get to this answer though? Thanks!


This is how I would approach this question.

When positive integer n is divided by 3, the remainder is 2;
I say n = 3a + 2 ( a is a non negative integer)

and when positive integer t is divided by 5, the remainder is 3.
So t = 5b + 3 (b is a non negative integer.)

What is the remainder when the product nt is divided by 15?
So nt = (3a + 2)(5b + 3) = 15ab + 9a + 10b + 6
15ab is divisible by 15. But I don't know anything about (9a + 10b + 6) yet.

Stmnt 1: n-2 is divisible by 5.
From above, n - 2 is just 3a. If n - 2 is divisible by 5, then 'a' must be divisible by 5. So I get that 9a is divisible by 15. I still don't know anything about b. If b = 1, remainder of nt is 1. If b = 2, remainder of nt is 11 and so on... Not sufficient.

Stmnt 2: t is divisible by 3.
If t is divisible by 3, then (5b + 3) is divisible by 3. Therefore, b must be divisible by 3. (If this is unclear, think: 15 + 3 will be divisible by 3 but 20 + 3 will not be. If the second term is 3, the first term must also be divisible by 3 to make the whole expression divisible by 3). So 10b is divisible by 15 but we do not know anything about a. If a = 1, remainder of nt is 0, if a = 2, remainder of nt is 9. Not sufficient.

Using both statements together, we know 9a and 10b are divisible by 15. So remainder must be 6. Sufficient.

Answer (C).
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 15 Mar 2011, 23:55
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Bunuel wrote:
When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

(1) n-2 is divisible by 5.
(2) t is divisible by 3.

Answer: C.


I have another approach to this ds, plz correct me if i'm wrong.
n=3x + 2
t = 5y + 3
Clearly we cannot solve the problem with either n or t. We need both information concerning n and t because we need to figure out the remaining of n*t. => left with C or E

(1): n-2 is divisible by 5 & n=3x + 2 => x is multiple of 5.
(2): t is divisible by 3. & t = 5y + 3 => y is multiple of 3
(1)& (2) => n*t = (3x+2) (5y+3) = (3x*5y) + (9x) + (10y) + 6
we know that: x is multiple of 5, y is multiple of 3 so:
(3x*5y) + (9x) + (10y) + 6 will have remaining of 6 because: each (3x*5y); (9x); (10y) is all multiple of 15.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 16 Mar 2011, 23:34
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I tried plugging numbers:

n = 3k + 2 = 2,5,8,11,14,17

t = 5m + 3 = 3,8,13,18,23,28




(1) n - 2 = 5l

=> n = 5l + 2 = 2,7,12,17

So n = 15k + 2 = 2,17,32,47


But n* t = 6 (2*3), 16(2*8) so n/15 can have rem 1 or 6

Hence (1) is not enough


(2) t = 3p = 3,6,12,15,18,21


So t = 15q + 3 = 3,18,33,48


But n*t = 6, 15, so rem can be 6, 0 etc.


Combining (1) and (2), it can be seen that nt = 15 * an integer + 6, so remainder is 6, answer is C.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post Updated on: 16 Oct 2011, 11:59
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Here's more of a plain English explanation, for those who like that sort of thing. :)

An important principle here is that you can multiply remainders. For instance, 10/7 = 1 r2 and 9/7 = 1 r3. 10*9/7 = 12 r6. See? Remainder 2 * remainder 3 = remainder 6.

Notice that if the resulting remainder is greater than the divisor, it wraps around again. 10/4=2 r 2 and 15/4=3 r 3. 10*15/4 should be remainder 6, but since 4 goes into 6, there is only 2 left. The actual result is 17 r2.

So, back to our problem. Using the prompt and statement 1, we know that both n/3 and n/5 have remainders of 2. We also know that t/5 has a remainder of 3.

So, if we just wanted to know the remainder when nt is divided by 5, we could multiply our remainders: 2 for n and 3 for t = 6. Since 5 goes into 6, we would be left with a remainder of 1.

However, since we’re dealing with 15, it’s more complicated. We know the remainder when n is divided by 15. Since n must be 2 more than a multiple of 3 and 2 more than a multiple of 5, it will also be 2 more than a multiple of 15:
17, 32, 47 . . .

We don’t know about t, though, unless we bring in statement 2. Once we do, we know that it is not only 3 more than a multiple of 5, but also an exact multiple of 3.

Out of our original list (3, 8, 13, 18, 23, 28, 33 . . .basically, every number that ends in 8 or 3), this leaves 3, 18, 33, 48 . . . i.e., 3 more than a multiple of 15.

Now we can multiply our remainders. n/15 has a remainder of 2 and t/15 has a remainder of 3, so nt/15 has a remainder of 6.
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Originally posted by DmitryFarber on 04 Sep 2011, 22:35.
Last edited by DmitryFarber on 16 Oct 2011, 11:59, edited 1 time in total.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 19 Oct 2013, 07:00
VeritasPrepKarishma wrote:
hogwarts wrote:
Saw this question on a GMATPrep test, and I can't figure out how to get to the correct answer. Can anyone help? :-) Thanks!

When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

(1) n-2 is divisible by 5.
(2) t is divisible by 3.

The correct answer is (C) - both statements together are sufficient, but neither statement alone is sufficient. Can anybody out there help explain to me how to get to this answer though? Thanks!


This is how I would approach this question.

When positive integer n is divided by 3, the remainder is 2;
I say n = 3a + 2 ( a is a non negative integer)

and when positive integer t is divided by 5, the remainder is 3.
So t = 5b + 3 (b is a non negative integer.)

What is the remainder when the product nt is divided by 15?
So nt = (3a + 2)(5b + 3) = 15ab + 9a + 10b + 6
15ab is divisible by 15. But I don't know anything about (9a + 10b + 6) yet.

Stmnt 1: n-2 is divisible by 5.
From above, n - 2 is just 3a. If n - 2 is divisible by 5, then 'a' must be divisible by 5. So I get that 9a is divisible by 15. I still don't know anything about b. If b = 1, remainder of nt is 1. If b = 2, remainder of nt is 11 and so on... Not sufficient.

Stmnt 2: t is divisible by 3.
If t is divisible by 3, then (5b + 3) is divisible by 3. Therefore, b must be divisible by 3. (If this is unclear, think: 15 + 3 will be divisible by 3 but 20 + 3 will not be. If the second term is 3, the first term must also be divisible by 3 to make the whole expression divisible by 3). So 10b is divisible by 15 but we do not know anything about a. If a = 1, remainder of nt is 0, if a = 2, remainder of nt is 9. Not sufficient.

Using both statements together, we know 9a and 10b are divisible by 15. So remainder must be 6. Sufficient.

Answer (C).

so from statement 1 we got 10b+6 if b=1 we get 16 then rem =1
if b=2 we got 106 so remainder =1
if b=3 we get 1006 so remainder =1 ..............................so i think a is sufficient .............what am i doing wrong
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 20 Oct 2013, 04:38
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tyagigar wrote:
VeritasPrepKarishma wrote:
hogwarts wrote:
Saw this question on a GMATPrep test, and I can't figure out how to get to the correct answer. Can anyone help? :-) Thanks!

When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

(1) n-2 is divisible by 5.
(2) t is divisible by 3.

The correct answer is (C) - both statements together are sufficient, but neither statement alone is sufficient. Can anybody out there help explain to me how to get to this answer though? Thanks!


This is how I would approach this question.

When positive integer n is divided by 3, the remainder is 2;
I say n = 3a + 2 ( a is a non negative integer)

and when positive integer t is divided by 5, the remainder is 3.
So t = 5b + 3 (b is a non negative integer.)

What is the remainder when the product nt is divided by 15?
So nt = (3a + 2)(5b + 3) = 15ab + 9a + 10b + 6
15ab is divisible by 15. But I don't know anything about (9a + 10b + 6) yet.

Stmnt 1: n-2 is divisible by 5.
From above, n - 2 is just 3a. If n - 2 is divisible by 5, then 'a' must be divisible by 5. So I get that 9a is divisible by 15. I still don't know anything about b. If b = 1, remainder of nt is 1. If b = 2, remainder of nt is 11 and so on... Not sufficient.

Stmnt 2: t is divisible by 3.
If t is divisible by 3, then (5b + 3) is divisible by 3. Therefore, b must be divisible by 3. (If this is unclear, think: 15 + 3 will be divisible by 3 but 20 + 3 will not be. If the second term is 3, the first term must also be divisible by 3 to make the whole expression divisible by 3). So 10b is divisible by 15 but we do not know anything about a. If a = 1, remainder of nt is 0, if a = 2, remainder of nt is 9. Not sufficient.

Using both statements together, we know 9a and 10b are divisible by 15. So remainder must be 6. Sufficient.

Answer (C).

so from statement 1 we got 10b+6 if b=1 we get 16 then rem =1
if b=2 we got 106 so remainder =1
if b=3 we get 1006 so remainder =1 ..............................so i think a is sufficient
.............what am i doing wrong


10b above means 10*b, 10 multiplied by b.

If b=2, then 10b+6=10*2+6=26 not 106;
If b=2, then 10b+6=10*3+6=36 not 1006.

Does this make sense?
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 11 Nov 2015, 19:57
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When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

n = 3a + 2, t = 5b + 3. Q: (3a + 2)(5b + 3)/15 = c + r/15. What is the value of r?

r is knowable only if it can be determined that each of 3a and 5b are divisible by 15, or in other words that a is divisible by 5 and b is divisible by 3, in which case the remainder would be the only remaining element that is clearly not divisible by 15.

nt = (3a +2)(5b +3) = 3a x 5b + 3a x3 + 10b + 6

if the first three elements of this equation are divisible by 15 the remainder would be 6. If divisibility of any of the variable-containing elements of this equation cannot be determined then the remainder cannot be determined.



St1: n-2 is divisible by 5.

n = 3a + 2
3a = n-2

if n-2 divisible by 5, then 3a is divisible by 5 (at least one factor of a = 5), and therefore 3a is divisible by 15.

However, divisibility of 5b by 15 cannot be determined, and therefore the value of r cannot be determined.

INSUFF.

(2) t is divisible by 3.

t = 5b + 3
5b + 3 is divisible by 3, therefore 5b is divisible by 3(at least one factor of b is 3) and 5b is divisible by 15.

However, divisibility of 3a by 15 cannot be determined, and therefore the value of r cannot be determined.

INSUFF.


Combined: 3a, and 5b are both divisible by 15, and therefore, all variable-containing elements of the equation nt = (3a +2)(5b +3) = 3a x 5b + 3a x3 + 10b + 6 are divisible by 15 and the remainder is 6.

SUFF.

Answer is C.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 10 Jun 2016, 11:09
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kt00381n wrote:
When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

(1) n-2 is divisible by 5.
(2) t is divisible by 3.


n=3a+2 AND t=5b+3

nt = 15ab + 10b + 9a + 6 ---- divide it by 15

Nt/15 = ab + (2/3)b + (3/5)a + 6/15. We see if we know both b and a are divisible by 3 and 5 respectively then we remainder is 6 else remainder would be something else depending on the value of a and b.

Stmt-1:
As we know n=3a+2 then n-2 = 3a.

Stmt-1 says n-2 is divisible by 5 that is3a is divisible by 5. Hence a is divisible by 5. BUT what about b? INSUFF.

Stmt-2:

As we know t=5b+3

Stmt-2 says t is divisible by 3 that is b is divisible by 3. BUT what about a? INSUFF.

Combining stmt-1 and stmt-2 we know a and b are divisible by 5 and 3 respectively. This is what we required to know as mentioned above. Sufficient.

Answer is C.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 15 Jan 2017, 00:38
Hi everyone,

Thanks for all the explanations, it´s always extremely helpful.

I got the right answer but it took me 4min 44 sec. Any suggestions to get get the time down.

Thanks
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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lauramo wrote:
Hi everyone,

Thanks for all the explanations, it´s always extremely helpful.

I got the right answer but it took me 4min 44 sec. Any suggestions to get get the time down.

Thanks


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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 05 Oct 2018, 08:06
kt00381n wrote:
When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

(1) n-2 is divisible by 5.
(2) t is divisible by 3.

(The solution presented below is VERY similar to Karishma´s approach.)

Obs.: don´t be "frightened" by the many-integer-representing-letters below. The MEANING they provide is simple and far more important than the "heavy notation"!

\(n,t\,\, \ge \,\,1\,\,{\rm{ints}}\,\,\,\left( * \right)\)

\(n = 3M + 2\,\,\,\,\left( {{\mathop{\rm int}} \,\,M \ge 0\,\,{\rm{by}}\,\,\left( * \right)} \right)\)

\(t = 5K + 3\,\,\,\,\left( {{\mathop{\rm int}} \,\,K \ge 0\,\,{\rm{by}}\,\,\left( * \right)} \right)\)

\(nt = \underbrace {15MK}_{{\text{multiple}}\,{\text{of}}\,\,15} + 9M + 10K + 6\,\,\,\,\,\, \Rightarrow \,\,\,\,\boxed{\,\,?\,\,\,\,:\,\,\,\,{\text{remainder}}\,\,{\text{by}}\,\,15\,\,\,}\)


\(\left( 1 \right)\,\,n - 2 = 5J\,\,\,\left( {{\mathop{\rm int}} \,\,J \ge 0\,\,{\rm{by}}\,\,\left( * \right)} \right)\,\,\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,\left( {n,t} \right) = \left( {2,3} \right)\,\,\,\, \Rightarrow \,\,\,\,\left( {M,K} \right) = \left( {0,0} \right)\,\,\,\, \Rightarrow \,\,\,{\rm{?}}\,\,{\rm{ = }}\,\,{\rm{6}}\,\, \hfill \cr
\,{\rm{Take}}\,\,\left( {n,t} \right) = \left( {2,8} \right)\,\,\,\, \Rightarrow \,\,\,\,\left( {M,K} \right) = \left( {0,1} \right)\,\,\,\, \Rightarrow \,\,\,{\rm{?}}\,\,{\rm{ = }}\,\,{\rm{1}}\,\, \hfill \cr} \right.\)


\(\left( 2 \right)\,\,t = 3G\,\,\,\left( {{\mathop{\rm int}} \,\,G \ge 1\,\,{\rm{by}}\,\,\left( * \right)} \right)\,\,\,\,\,\left\{ \matrix{
\,\left( {{\rm{Re}}} \right){\rm{Take}}\,\,\left( {n,t} \right) = \left( {2,3} \right)\,\,\,\, \Rightarrow \,\,\,\,\left( {M,K} \right) = \left( {0,0} \right)\,\,\,\, \Rightarrow \,\,\,{\rm{?}}\,\,{\rm{ = }}\,\,{\rm{6}}\,\, \hfill \cr
\,{\rm{Take}}\,\,\left( {n,t} \right) = \left( {5,3} \right)\,\,\,\, \Rightarrow \,\,\,\,\left( {M,K} \right) = \left( {1,0} \right)\,\,\,\, \Rightarrow \,\,\,{\rm{?}}\,\,{\rm{ = }}\,\,{\rm{0}}\,\, \hfill \cr} \right.\)


\(\left( {1 + 2} \right)\,\,\)

\(\left\{ \matrix{
\,\,n - 2 = 3M \hfill \cr
\,\,n - 2 = 5J \hfill \cr} \right.\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,n - 2 = 15H\,\,\,\left( {{\mathop{\rm int}} \,\,H \ge 0\,\,{\rm{by}}\,\,\left( * \right)} \right)\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,n = 15H + 2\)

\(\left\{ \matrix{
\,\,t - 3 = 5K \hfill \cr
\,\,t = 3G\,\,\,\, \Rightarrow \,\,\,t - 3 = 3W \hfill \cr} \right.\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,t - 3 = 15D\,\,\,\left( {{\mathop{\rm int}} \,\,D \ge 0\,\,{\rm{by}}\,\,\left( * \right)} \right)\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,t = 15D + 3\)

\(\left\{ \matrix{
n = 15H + 2 \hfill \cr
t = 15D + 3 \hfill \cr} \right.\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,?\,\,\,:\,\,\,\,\,\,nt = 15\,\underbrace {\left[ {15HD + 3H + 2D} \right]}_{{\mathop{\rm int}} } + 6\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\,? = 6\,\,\,\,\, \Rightarrow \,\,\,\,\,{\rm{SUFF}}.\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 14 Mar 2019, 11:08
Hi,

Here are my two cents for this question.

First I would like to summarize the concept of General Numbers here.

Concept of General number

(A) if the reminders are same

Say n is divided by 3 reminder is 2 and when n is divided by 5 reminder is 2.

What would be the general number n = 15M+2. where M>0 for M=1 , n=17, M=2 , n=32.

How to derive general number

Say n when divided by 5 gives remainder 2, we can represent this algebraically n= 5P+2 -------(I)

Now if n is divided by 3 reminder is 2 which means \(\frac{5P+2 }{3}\)

we can rewrite \(\frac{5P+2 }{3}\) as \(\frac{3P+2P+2 }{3}\)= \(\frac{3P}{3}\)+\(\frac{2P+2}{3}\)

Now since weare given that when n is divided by 3 we get reaminder as 2 so this part \(\frac{2P+2}{3}\) yields a reminder 2.

for what value of P will the reminder be 2 Say P = 3M then the part\(\frac{2P+2}{3}\) become \(\frac{2(3M)+2}{3}\) which gives us reminder as 2

So we can write equations (I) as
n= 5(3M)+2
n=15M+2

(B) if the reminders are different

Say when n is divided by 11 the reminder is 7 and when n is divided by 13 reminder is 12

lets say n= 13T+12-----------(II)

when we divide this number by 11 we have reminder as 7

so which means \(\frac{13T+12 }{11}\) leaves us with reminder 7

we can rewrite \(\frac{13T+12 }{11}\) as \(\frac{11T+2T+11+1 }{7}\)= \(\frac{11(T+1)}{11}\)+\(\frac{(2T+1)}{11}\)

Now since we are given that when n is divided by 11 we get remainder as 7 so this part \(\frac{(2T+1)}{11}\) yields a reminder 7.

for what value of T will the reminder be 7

recall that if \(\frac{x}{y}\) reminder r is 0\(\leqslant\)r<y,
Also if in case x<y then reminder is x

Which means if 2T+1 = 7 then we can say that \(\frac{(2T+1)}{11}\) yields a reminder 7
So for what smallest positive value of T will 2T+1 = 7 Say T = 3 then the part\(\frac{2T+1}{11}\) become \(\frac{2(3)+1}{11}\) which gives us reminder as 7

So we can write equations (II) as
n= 13(3)+12
n=51
So Smallest value of n which when divided by 11 leaves remainder 7 and when divided by 13 leaves remainder 12 is 51

From this we can say that the general number n= 11*13K+51 which when divided by 11 leaves reminder 7 and when divided by 13 leaves remainder 12


Now getting back to question.
n = 3K+2 and t= 5R+3. Now the product of nt would be = 15KR+9K+10R+6. We need to find the remainder when nt is divided by 15.

So here if know when n is divided by 5 and when t is divided by 3 what would be the reminder then we could certainly say what would the reminder if nt is divided by 15

Statement 1 Tells us that when n-2 is divided by 5 reminder is 0
so n-2= 5Q or n=5Q+2 and we have from stem that n=3K+2,
which tells us that n is in the form of 15V+2
But without any information about T we cannot determine the remainder of "nt"
So Insufficient

Statement 2 Says that t is divisible by 3 so t= 3F and from Stem we have t= 5R+3., so general form of t=15W+3, which when divided by 3 leaves reminder 0 and when divided by 5 leaves reminder 3
Now in absence of any information about 'n' we can tell what would be the remainder when "nt" is divided by 15

hence insufficient.

Now combining statements 1 and 2 we have
n=15V+2
t=15W+3,

we can infer from that when "nt" is divided by 15 we will have some reminder .

Hence Both Statements are necessary for us to answer the Question.


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Re: When positive integer n is divided by 3, the remainder is 2; and when  [#permalink]

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New post 20 Oct 2019, 01:16
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Re: When positive integer n is divided by 3, the remainder is 2; and when   [#permalink] 20 Oct 2019, 01:16

When positive integer n is divided by 3, the remainder is 2; and when

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