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# Which of the following equals the average of x and 1/x ?

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Which of the following equals the average of x and 1/x ?  [#permalink]

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09 Apr 2019, 04:01
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15% (low)

Question Stats:

85% (00:57) correct 15% (02:08) wrong based on 39 sessions

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Which of the following equals the average of x and 1/x ?

(A) (x + 2)/x

(B) (x^2 + 1)/(2x)

(C) (x + 1)/x^2

(D) (2x^2 + 1)/x

(E) (x + 1)/x

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Which of the following equals the average of x and 1/x ?  [#permalink]

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09 Apr 2019, 04:08
Bunuel wrote:
Which of the following equals the average of x and 1/x ?

(A) (x + 2)/x

(B) (x^2 + 1)/(2x)

(C) (x + 1)/x^2

(D) (2x^2 + 1)/x

(E) (x + 1)/x

the average of x and 1/x $$= [x+(1/x)]/2 = \frac{{x^2 + 1}}{2x}$$

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Re: Which of the following equals the average of x and 1/x ?  [#permalink]

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09 Apr 2019, 04:34
$$\frac{x + \frac{1}{x}}{2}$$

$$\frac{x^2 + 1}{2x}$$

OPTION: B
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Re: Which of the following equals the average of x and 1/x ?  [#permalink]

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09 Apr 2019, 04:52
Bunuel wrote:
Which of the following equals the average of x and 1/x ?

(A) (x + 2)/x

(B) (x^2 + 1)/(2x)

(C) (x + 1)/x^2

(D) (2x^2 + 1)/x

(E) (x + 1)/x

the average of x and 1/x ==> $$(x+(1/x))/2$$ ===> $$(x^2 + 1)/(2x)$$

Hence B
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Re: Which of the following equals the average of x and 1/x ?  [#permalink]

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09 Apr 2019, 08:14
sum of terms = x+1/x = (x^2+1)/x

number of terms = 2

So average = 1/2*((x^2+1)/x )

IMO B
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Re: Which of the following equals the average of x and 1/x ?  [#permalink]

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10 Apr 2019, 18:18
Bunuel wrote:
Which of the following equals the average of x and 1/x ?

(A) (x + 2)/x

(B) (x^2 + 1)/(2x)

(C) (x + 1)/x^2

(D) (2x^2 + 1)/x

(E) (x + 1)/x

The average of x and 1/x is:

(x + 1/x)/2 = (x^2/x + 1/x)/2 = [(x^2 + 1)/x]/2 = (x^2 + 1)/(2x)

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Re: Which of the following equals the average of x and 1/x ?   [#permalink] 10 Apr 2019, 18:18
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