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Which of the following inequalities has a solution set that, when

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Which of the following inequalities has a solution set that, when graphed on the number line, is a single line segment of finite length?


A. \(x^4 \geq 1\)

B. \(x^3 \leq 27\)

C. \(x^2\geq 16\)

D. \(2 \leq |x| \leq 5\)

E. \(2 \leq 3x+4 \leq 6\)

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Which of the following inequalities has a solution set that, when  [#permalink]

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New post 03 Jan 2011, 07:41
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Which of the following inequalities has a solution set that, when graphed on the number line, is a single line segment of finite length?

A. \(x^4 \geq 1\)

B. \(x^3 \leq 27\)

C. \(x^2\geq 16\)

D. \(2 \leq |x| \leq 5\)

E. \(2 \leq 3x+4 \leq 6\)

The key words in the stem are: "a single line segment of finite length"

Now, answer choices A, B, and C cannot be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus cannot be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have that absolute value of x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.

Answer: E.


Just to demonstrate:

A. \(x^4 \geq 1\) --> \(x\leq{-1}\) or \(x\geq{1}\): two infinite ranges;

B. \(x^3 \leq 27\) --> \(x\leq{3}\): one infinite range;

C. \(x^2\geq 16\) --> \(x\leq{-4}\) or \(x\geq{4}\): two infinite ranges;

D. \(2 \leq |x| \leq 5\) --> \(-5\leq{x}\leq{-2}\) or \(2\leq{x}\leq{5}\): two finite ranges;

E. \(2 \leq 3x+4 \leq 6\) --> \(-2\leq{3x}\leq{2}\) --> \(-\frac{2}{3}\leq{x}\leq{\frac{2}{3}}\): one finite range.

Answer: E.

Hope it's clear.
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 11 Jun 2011, 22:36
It is good question,
It was obvious that A,B , C are incorrect as these are exponent of X but I couldn't figure out which one between d & e is better, so attempted D on GMAT Prep test
Later, During review of the question I found that X was actually |X| - absolute value , Hence two lines,
So correct is E
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 13 Jul 2014, 08:34
Bunuel wrote:
anilnandyala wrote:
which of the following inequalities has a solution that , when graphed on the number line is a straight line of finite length?


Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?

The key words in the stem are: "a single line segment of finite length"

Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have that absolute value of x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.

Answer: E.

Just to demonstrate:

A. x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\): two infinite ranges;

B. x^3 <= 27 --> \(x\leq{3}\): one infinite range;
C. x^2 >= 16 --> \(x\leq{-4}\) or \(x\geq{4}\): two infinite ranges;

D. 2 <= |x| <= 5 --> \(-5\leq{x}\leq{-2}\) or \(2\leq{x}\leq{5}\): two finite ranges;

E. 2 <= 3x+4 <= 6 --> \(-2\leq{3x}\leq{2}\) --> \(-\frac{2}{3}\leq{x}\leq{\frac{2}{3}}\): one finite range.

Answer: E.

Hope it's clear.


Hi Bunuel, for option B, why isn't it a finite range?

x^3<=27
-3<=x<=3
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 13 Jul 2014, 08:36
russ9 wrote:
Bunuel wrote:
anilnandyala wrote:
which of the following inequalities has a solution that , when graphed on the number line is a straight line of finite length?


Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?

The key words in the stem are: "a single line segment of finite length"

Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have that absolute value of x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.

Answer: E.

Just to demonstrate:

A. x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\): two infinite ranges;

B. x^3 <= 27 --> \(x\leq{3}\): one infinite range;
C. x^2 >= 16 --> \(x\leq{-4}\) or \(x\geq{4}\): two infinite ranges;

D. 2 <= |x| <= 5 --> \(-5\leq{x}\leq{-2}\) or \(2\leq{x}\leq{5}\): two finite ranges;

E. 2 <= 3x+4 <= 6 --> \(-2\leq{3x}\leq{2}\) --> \(-\frac{2}{3}\leq{x}\leq{\frac{2}{3}}\): one finite range.

Answer: E.

Hope it's clear.


Hi Bunuel, for option B, why isn't it a finite range?

x^3<=27
-3<=x<=3


x^3<=27 --> \(x\leq{3}\).
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 18 Feb 2015, 05:35
Bunuel wrote:
anilnandyala wrote:
which of the following inequalities has a solution that , when graphed on the number line is a straight line of finite length?


Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?

The key words in the stem are: "a single line segment of finite length"

Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have that absolute value of x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.

Answer: E.

Just to demonstrate:

A. x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\): two infinite ranges;

B. x^3 <= 27 --> \(x\leq{3}\): one infinite range;

C. x^2 >= 16 --> \(x\leq{-4}\) or \(x\geq{4}\): two infinite ranges;

D. 2 <= |x| <= 5 --> \(-5\leq{x}\leq{-2}\) or \(2\leq{x}\leq{5}\): two finite ranges;

E. 2 <= 3x+4 <= 6 --> \(-2\leq{3x}\leq{2}\) --> \(-\frac{2}{3}\leq{x}\leq{\frac{2}{3}}\): one finite range.

Answer: E.

Hope it's clear.



Could someone explain Option A in detail?
I understand upon taking 4th root on both sides it becomes: x>= +-1
But, I don't understand how it gets simplified further as its been explained as: x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\)
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 18 Feb 2015, 05:40
connectvinoth wrote:
Bunuel wrote:
anilnandyala wrote:
which of the following inequalities has a solution that , when graphed on the number line is a straight line of finite length?


Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?

The key words in the stem are: "a single line segment of finite length"

Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have that absolute value of x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.

Answer: E.

Just to demonstrate:

A. x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\): two infinite ranges;

B. x^3 <= 27 --> \(x\leq{3}\): one infinite range;

C. x^2 >= 16 --> \(x\leq{-4}\) or \(x\geq{4}\): two infinite ranges;

D. 2 <= |x| <= 5 --> \(-5\leq{x}\leq{-2}\) or \(2\leq{x}\leq{5}\): two finite ranges;

E. 2 <= 3x+4 <= 6 --> \(-2\leq{3x}\leq{2}\) --> \(-\frac{2}{3}\leq{x}\leq{\frac{2}{3}}\): one finite range.

Answer: E.

Hope it's clear.



Could someone explain Option A in detail?
I understand upon taking 4th root on both sides it becomes: x>= +-1
But, I don't understand how it gets simplified further as its been explained as: x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\)


x >= +/- 1 does not make any sense.

When taking 4th root from both sides we'll get \(|x| \geq{1}\), which is the same as \(x\leq{-1}\) or \(x\geq{1}\).


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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 18 Apr 2015, 09:52
Bunuel , Could you please elaborate on how to solve
2 <= |x| <= 5 --> −5≤x≤−2 or 2≤x≤5

in steps..?
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New post 05 Sep 2016, 18:23
Ralphcuisak wrote:
Bunuel , Could you please elaborate on how to solve
2 <= |x| <= 5 --> −5≤x≤−2 or 2≤x≤5

in steps..?


The absolute value of X is between 2 and 5.
X = 2 through 5
X = -2 through -5

On the number line in bold:

--|---|--0--|---|--
---2--5--0--2---5--

2 separate finite line segments.
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 09 Aug 2017, 11:32
Bunuel wrote:
anilnandyala wrote:
which of the following inequalities has a solution that , when graphed on the number line is a straight line of finite length?


Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?

The key words in the stem are: "a single line segment of finite length"

Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have that absolute value of x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.

Answer: E.

Just to demonstrate:

A. x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\): two infinite ranges;

B. x^3 <= 27 --> \(x\leq{3}\): one infinite range;

C. x^2 >= 16 --> \(x\leq{-4}\) or \(x\geq{4}\): two infinite ranges;

D. 2 <= |x| <= 5 --> \(-5\leq{x}\leq{-2}\) or \(2\leq{x}\leq{5}\): two finite ranges;

E. 2 <= 3x+4 <= 6 --> \(-2\leq{3x}\leq{2}\) --> \(-\frac{2}{3}\leq{x}\leq{\frac{2}{3}}\): one finite range.

Answer: E.

Hope it's clear.


Hi,

I think I am unable to understand the question here. I was between B and E and chose B because it gave one value which is 3.

I failed to understand what "a single line segment of finite length" means. Can you explain this and what we actually need to find here?
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 09 Aug 2017, 23:31
3
pra1785 wrote:
Bunuel wrote:
anilnandyala wrote:
which of the following inequalities has a solution that , when graphed on the number line is a straight line of finite length?


Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?

The key words in the stem are: "a single line segment of finite length"

Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have that absolute value of x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.

Answer: E.

Just to demonstrate:

A. x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\): two infinite ranges;

B. x^3 <= 27 --> \(x\leq{3}\): one infinite range;

C. x^2 >= 16 --> \(x\leq{-4}\) or \(x\geq{4}\): two infinite ranges;

D. 2 <= |x| <= 5 --> \(-5\leq{x}\leq{-2}\) or \(2\leq{x}\leq{5}\): two finite ranges;


E. 2 <= 3x+4 <= 6 --> \(-2\leq{3x}\leq{2}\) --> \(-\frac{2}{3}\leq{x}\leq{\frac{2}{3}}\): one finite range.

Answer: E.

Hope it's clear.


Hi,

I think I am unable to understand the question here. I was between B and E and chose B because it gave one value which is 3.

I failed to understand what "a single line segment of finite length" means. Can you explain this and what we actually need to find here?


\(x^3 \leq 27\) gives \(x\leq{3}\), not x = 3.

Maybe images could help:

A. x^4 >= 1 --> \(x\leq{-1}\) or \(x\geq{1}\): two infinite ranges;
Image


B. x^3 <= 27 --> \(x\leq{3}\): one infinite range;
Image


C. x^2 >= 16 --> \(x\leq{-4}\) or \(x\geq{4}\): two infinite ranges;
Image


D. 2 <= |x| <= 5 --> \(-5\leq{x}\leq{-2}\) or \(2\leq{x}\leq{5}\): two finite ranges;
Image


E. 2 <= 3x+4 <= 6 --> \(-2\leq{3x}\leq{2}\) --> \(-\frac{2}{3}\leq{x}\leq{\frac{2}{3}}\): one finite range.
Image


Similar questions:
https://gmatclub.com/forum/which-of-the ... 27820.html (GMAT Prep).
https://gmatclub.com/forum/which-of-the ... 30666.html (Knewton).

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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 15 Aug 2017, 11:00
anilnandyala wrote:
Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?

A. x^4 >= 1
B. x^3 <= 27
C. x^2 >= 16
D. 2 <= |x| <= 5
E. 2 <= 3x+4 <= 6


We must determine from our answer choices which inequality is a single line segment of finite length when graphed on the number line.

A) x^4 ≥ 1

∜(x^4) ≥ ∜1

|x| ≥ 1

x ≥ 1 or x ≤ -1

Since the solution set from answer choice A produces two rays of infinite length, answer choice A is not correct.

B) x^3 ≤ 27

∛(x^3) ≤ ∛27

x ≤ 3

Since the solution set from answer choice B produces one ray of infinite length, answer choice B is not correct.

C) x^4 ≥ 16

∜(x^4) ≥ ∜16

|x| ≥ 2

x ≥ 2 or x ≤ -2

Since the solution set from answer choice C produces two rays of infinite length, answer choice C is not correct.

D) 2 ≤ |x| ≤ 5

We must solve for when x is positive and for when x is negative.

When x is positive:

2 ≤ x ≤ 5

When x is negative:

2 ≤ -x ≤ 5

-1(2 ≤ -x ≤ 5)

-2 ≥ x ≥ -5

Since the solution set from answer choice D produces two line segments of finite length, answer choice D is not correct.

Since answers A, B, C, and D are not correct, E must be the correct answer. However, for practice, we can solve it anyway.

E) 2 ≤ 3x + 4 ≤ 6

-2 ≤ 3x ≤ 2

-2/3 ≤ x ≤ 2/3

Since the solution set from answer choice E produces one line segment of finite length, answer choice E is correct.

Answer: E
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 15 Aug 2017, 13:34
2
1
Hi,
Since question is saying single line of finite length,
Graph is going to be a straight line is equation is a linear equation. Linear equation is equation with highest power of variable being one. For higher powers, graph is going to be a curve.
Option A has highest power of x as 4, so it is curve
Option B has highest power of x as 3, so it is also curve
Option C has highest power of x as 2, so it is also curve
Option D has absolute function. An absolute function is combination of two functions, so it is going to give two lines.
Thus option E
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 06 Feb 2018, 15:35
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anilnandyala wrote:
Which of the following inequalities has a solution set that, when graphed on the number line, is a single line segment of finite length?


A. \(x^4 \geq 1\)

B. \(x^3 \leq 27\)

C. \(x^2\geq 16\)

D. \(2 \leq |x| \leq 5\)

E. \(2 \leq 3x+4 \leq 6\)

Attachment:
Untitled.pdf


IMPORTANT
This is one of those questions that require us to check/test the answer choices. In these situations, always check the answer choices from E to A, because the correct answer is typically closer to the bottom than to the top.

E) 2 ≤ 3x + 4 ≤ 6
Subtract 4 from all sides to get: -2 ≤ 3x ≤ 2
Divide all sides by 3 to get: -2/3 ≤ x ≤ 2/3
So, x can have any value from -2/3 to 2/3
So, if we were to graph the possible values of x, the line segment would have a FINITE length.

Answer: E

Cheers,
Brent
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Re: Which of the following inequalities has a solution set that, when  [#permalink]

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New post 17 Mar 2018, 12:43
Hi All,

The equations in this question can be physically drawn or handled as a Number Property concept:

Note that the question asks for a SINGLE SEGMENT of FINITE LENGTH. This means that the group of numbers that make up the solution set would be consecutive and limited (as opposed to non-consecutive and/or infinite).

Here are the Number Properties:

A: X^4 >= 1

X can be 1, 2, 3, etc. or -1, -2, -3, etc. This group of answers is infinite and non-consecutive. Eliminate A.

B: X^3 <= 27

X can be 3, 2, 1, 0, -1, etc. This group is infinite. Eliminate B.

C: X^2 >= 16

X can be 4, 5, 6, etc. or -4, -5, -6, etc. This group is infinite and non-consecutive. Eliminate C.

D: 2 <= |X| <= 5

X can be 2, 3, 4, 5 or -2, -3, -4, -5, This group is finite BUT non-consecutive. Eliminate D.

E: 2 <= 3X + 4 <= 6

Let's simplify with algebra…

-2 <= 3X <= 2

-2/3 <= X <= 2/3

X is a finite set of answers and the answers are consecutive. This is a MATCH to what we're looking for.

Final Answer:

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Re: Which of the following inequalities has a solution set that, when &nbs [#permalink] 17 Mar 2018, 12:43
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