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# X is a set containing 7 different numbers. Y is a set containing 6 dif

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X is a set containing 7 different numbers. Y is the set containing 6  [#permalink]

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05 Jul 2017, 09:57
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Difficulty:

85% (hard)

Question Stats:

45% (01:50) correct 55% (01:47) wrong based on 73 sessions

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X is a set containing 7 different numbers. Y is the set containing 6 different positive numbers all of which are members of set X. Is the mean of X equal to the mean of Y?

a) Range of X is greater than range of Y
b) Sum of all the numbers in set X< Sum of all the numbers in set Y

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Posts: 7686
X is a set containing 7 different numbers. Y is a set containing 6 dif  [#permalink]

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05 Jul 2017, 10:36
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2
anurag16 wrote:
X is a set containing 7 different numbers. Y is the set containing 6 different positive numbers all of which are members of set X. Is the mean of X equal to the mean of Y?

a) Range of X is greater than range of Y
b) Sum of all the numbers in set X< Sum of all the numbers in set Y

Hi..
If all 7 numbers are different and 6 of them have a certain MEAN, M..
This would be EQUAL to mean of 7 numbers ONLY when 7th number itself is EQUAL to M
...

Let's see the statements...

a) Range of X is greater than range of Y
This means the 7th number is either greater than or less than the 6 numbers in set Y..
So the 7 number cannot be EQUAL to mean of 6 numbers..
Ans is NO

Sufficient

b) Sum of all the numbers in set X< Sum of all the numbers in set Y
Clearly a lower number /7 will be less than greater number/6..
Clearly mean of Y>mean of X..
Ans is again NO

Sufficient

D
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X is a set containing 7 different numbers. Y is a set containing 6 dif  [#permalink]

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30 Sep 2017, 21:25
X is a set containing 7 different numbers. Y is a set containing 6 different positive numbers, all of which are members of set X. Is the mean of X equal to the mean of Y ?

A. Range of X is greater than range of Y.

B. (Sum of all the numbers in set X) < (Sum of all numbers in set Y).
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Posts: 7686
Re: X is a set containing 7 different numbers. Y is a set containing 6 dif  [#permalink]

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30 Sep 2017, 22:26
1
Kamlesh44 wrote:
X is a set containing 7 different numbers. Y is a set containing 6 different positive numbers, all of which are members of set X. Is the mean of X equal to the mean of Y ?

A. Range of X is greater than range of Y.

B. (Sum of all the numbers in set X) < (Sum of all numbers in set Y).

Pl search before posting a new Q.
refer to discussion above
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Re: X is a set containing 7 different numbers. Y is a set containing 6 dif  [#permalink]

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06 Apr 2019, 04:29

range of x is greater than that of y , we can infer that the sum of numbers in x can never be equal to the sum of numbers in y... right? hence sufficient ??
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Re: X is a set containing 7 different numbers. Y is a set containing 6 dif  [#permalink]

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07 Apr 2019, 03:07
How /7 is smaller than /6 ?
kindly explain
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Re: X is a set containing 7 different numbers. Y is a set containing 6 dif  [#permalink]

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07 Apr 2019, 03:48
GGMU wrote:
X is a set containing 7 different numbers. Y is the set containing 6 different positive numbers all of which are members of set X. Is the mean of X equal to the mean of Y?

a) Range of X is greater than range of Y
b) Sum of all the numbers in set X< Sum of all the numbers in set Y

How can the sum of the numbers in X be less than the sum of the numbers in Y when all the numbers of Y are from X?
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Re: X is a set containing 7 different numbers. Y is a set containing 6 dif   [#permalink] 07 Apr 2019, 03:48
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# X is a set containing 7 different numbers. Y is a set containing 6 dif

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