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My approach is bit simple.

given -10, 3, 5, x, y.
St 1: the list has two modes that means X and Y can take any of the three values from the list but not an outside number. In any case the least no will remain -10 and highest number will remain 5. So, range will be the same. Hence, Sufficient. Possible Ans A or D
St 2: X !=Y Clearly insufficient.
So Answer is A
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could some one provide me an explanation for the answer ? i got the answer as E.
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OFFICIAL EXPLANATION By Veritas

The correct answer is A. In order for this list of numbers to have exactly two modes (as statement 1 states), when the given information includes three, unique, known values and two variables, x and y must each match a different known number. That would mean that each of two known values appears exactly twice, making those two values the modes.

If x and y were each unique values that did not match a value already known, there would be no mode to the set. If x equaled y but neither matched a value already known, then that x and y would form the single mode, and there would not be a second.

So in order for statement 1 to be true, x and y must match already known values. Bringing that back to the exact question, that would mean that the list only includes the values -10, 3, and 5 (with duplicates of two of those three), so the range would have to be 5 - (-10) = 15.

Statement 2 is not sufficient: leaving out the information from statement 1, statement 2 still allows x and y to be any value (as long as they don't match each other), so you cannot put a limit on the least or greatest value, and the range still has infinite potential values.
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FullSizeRender (10).jpg [ 89.76 KiB | Viewed 7734 times ]

A
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The correct answer is A. In order for this list of numbers to have exactly two modes (as statement 1 states), when the given information includes three, unique, known values and two variables, x and y must each match a different known number. That would mean that each of two known values appears exactly twice, making those two values the modes.

If x and y were each unique values that did not match a value already known, there would be no mode to the set. If x equaled y but neither matched a value already known, then that x and y would form the single mode, and there would not be a second.

Quote:
So in order for statement 1 to be true, x and y must match already known values. Bringing that back to the exact question, that would mean that the list only includes the values -10, 3, and 5 (with duplicates of two of those three), so the range would have to be 5 - (-10) = 15.

Quote:
Statement 2 is not sufficient: leaving out the information from statement 1, statement 2 still allows x and y to be any value (as long as they don't match each other), so you cannot put a limit on the least or greatest value, and the range still has infinite potential values.
Quote:
Take Away: Adding the same value to the set never changes the range
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Is it a given fact that x and y cannot be equal here? Since the answer won't be A without this assumption.
Bunuel
-10, 3, 5, x, y

For the list of numbers above, what is the range?


(1) The list of numbers has exactly two modes.

(2) x does not equal y
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sdas80923
Is it a given fact that x and y cannot be equal here? Since the answer won't be A without this assumption.
Bunuel
-10, 3, 5, x, y

For the list of numbers above, what is the range?


(1) The list of numbers has exactly two modes.

(2) x does not equal y

x = y is not possible under statement (1), because in that case the list cannot have exactly two modes. If x = y, the list would have only one mode, not two.
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