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26 Dec 2025, 23:18
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Let total number of books be B
Total pages be P
We are given P = B x 252.08
We know that number of pages cannot be in decimal. Therefore, simplifying the equation,
P = B x 25208/100 or P = 252B + (2B / 25)
From this we know 2B / 25 must be an integer. 2B must be divisible by 25 and B by 12.5
Therefore B can be 12.5, 25, 37.5, 50... But since it cannot be in decimal B has to be divisible by multiples of 25.
Analysing the statements:
1. Each shelf contain between 2 and 7 books which means minimum of 14 (2 books on each shelf) to maximum of 49 (7 books on each shelf)
Since, only 25 is a multiple of 25 which lies in this range, total number of books must be 25.
Hence, 1 alone is sufficient.
2. P < 10000 which means B x 252.08 < 10000
i.e. B < 10000/252.08
Since 10000/250 = 40, we know this will give B < 39. something decimal value
Only multiple of 25 less than 39.something value is 25 only.
Hence, B = 25
2 alone is sufficient.
Since both statement alone are sufficient. Answer Option D
Total pages be P
We are given P = B x 252.08
We know that number of pages cannot be in decimal. Therefore, simplifying the equation,
P = B x 25208/100 or P = 252B + (2B / 25)
From this we know 2B / 25 must be an integer. 2B must be divisible by 25 and B by 12.5
Therefore B can be 12.5, 25, 37.5, 50... But since it cannot be in decimal B has to be divisible by multiples of 25.
Analysing the statements:
1. Each shelf contain between 2 and 7 books which means minimum of 14 (2 books on each shelf) to maximum of 49 (7 books on each shelf)
Since, only 25 is a multiple of 25 which lies in this range, total number of books must be 25.
Hence, 1 alone is sufficient.
2. P < 10000 which means B x 252.08 < 10000
i.e. B < 10000/252.08
Since 10000/250 = 40, we know this will give B < 39. something decimal value
Only multiple of 25 less than 39.something value is 25 only.
Hence, B = 25
2 alone is sufficient.
Since both statement alone are sufficient. Answer Option D
26 Dec 2025, 23:19
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So in this Question!
The average given of total pages is 252.08
Now we know that total page must be integer
so if we solve this and reduce to the lowest fraction then it will be 6302/25
Means books should be in multiple of 25 for the pages to be integer.
Now go into statement
Statement 1:
shelves have book inclusive of 2 and 7 and between them
So minimum possible books according to this is 14 and maximum could be 49
And multiple of 25 is only 25 books possible hence we can answer from this hence sufficient
Statement 2:
Now given total pages less than 10K means we know that for only 25 books the pages is 6302 is the possibility otherwise it will be more than 10K
Hence we can say that this is also sufficient.
Hence both are sufficient
Hence (D) answer
The average given of total pages is 252.08
Now we know that total page must be integer
so if we solve this and reduce to the lowest fraction then it will be 6302/25
Means books should be in multiple of 25 for the pages to be integer.
Now go into statement
Statement 1:
shelves have book inclusive of 2 and 7 and between them
So minimum possible books according to this is 14 and maximum could be 49
And multiple of 25 is only 25 books possible hence we can answer from this hence sufficient
Statement 2:
Now given total pages less than 10K means we know that for only 25 books the pages is 6302 is the possibility otherwise it will be more than 10K
Hence we can say that this is also sufficient.
Hence both are sufficient
Hence (D) answer
27 Dec 2025, 01:11
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Average = 252.08
Sum/n = 252.08
sum = 252.08 * n
= (6302/25) * n, now since the sum is definitely an integer, as it is the sum of the number of pages, n must be a multiple of 25.
(1) Minimum books = 7*2 = 14, maximum books = 7*7 = 49. We have only one multiple of 25 in this range, which is 25 itself. Sufficient.
(2) sum < 10000, which means (6302/25) * n < 10000. Simplifying it, we get approximately n < 39. Again, only one multiple of 25 here. Sufficient.
Option D.
Sum/n = 252.08
sum = 252.08 * n
= (6302/25) * n, now since the sum is definitely an integer, as it is the sum of the number of pages, n must be a multiple of 25.
(1) Minimum books = 7*2 = 14, maximum books = 7*7 = 49. We have only one multiple of 25 in this range, which is 25 itself. Sufficient.
(2) sum < 10000, which means (6302/25) * n < 10000. Simplifying it, we get approximately n < 39. Again, only one multiple of 25 here. Sufficient.
Option D.
Bunuel
