Step 1: Understanding the problem
There are four grades:
G1 ,G2 ,G3, G4
, where
G1 <G2 <G3 <G4
These grades are consecutive multiples of 5:
G1 ,G2 =G1 +5,G3 =G1 +10,G4 =G1 +15.
The number of comic books assigned to each grade is as follows:
3 comic books received G1
5 comic books received G2
4 comic books received G3
x comic books received G4
The formula for the standard deviation is:
σ= ∑fi(Gi −μ)^2 / N
,
where:
fi : frequency of grade
Gi: grade
μ: mean of the grades,
N: total number of comic books.
Step 2: Analyze each statement.
Statement (1):
x=2
If x=2, the total number of comic books is:
N=3+5+4+2=14.
However, the values of the grades
G1 ,G2 ,G3 , G4 are not given. Without knowing the specific grades, we cannot calculate the mean (μ) or the deviations (Gi−μ).
Thus, Statement (1) is insufficient.
Statement (2): The lowest grade assigned to the comic books was G1=35.
From this, the grades are:
G1=35, G2 =40, G3=45, G4 =50.
However, the value of x (the number of comic books that received G4 ) is not given.
Without x, we cannot determine the total number of comic books N or compute the mean (μ).
Thus, Statement (2) is insufficient.
Step 3: Combine Statements (1) and (2).
From Statement (2), the grades are
35,40,45, and 50.
From Statement (1),
x=2, so the frequencies are:
f1=3,f2=5,f3=4 ,f4 =2.
The total number of comic books is:N=3+5+4+2=14.
The mean (μ) is:
μ= {∑fi * Gi}/N = {(3×35)+(5×40)+(4×45)+(2×50)}/14
μ= (105+200+180+100)/14 = 585/14
μ =41.7857(approximately).
The variance (σ^2) is:
σ^2 = {∑ fi (Gi −μ)^2} / N
Substitute
Gi , fi , and μ to compute σ^2
, then take the square root to find σ.
Both statements together provide all necessary information to calculate the standard deviation.
Final Answer: C (Both statements together are sufficient).