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Question Stats: 63% (02:24) correct 37% (02:37) wrong based on 272 sessions

### HideShow timer Statistics A 10-by-6 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?

A. The volume of the cylinder with height 10 is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the cylinder with height 6.

B. The volume of the cylinder with height 6 is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the cylinder with height 10.

C. The volume of the cylinder with height 10 is $$60\pi$$ cubic inches greater than the volume of the cylinder with height 6.

D. The volume of the cylinder with height 6 is $$60\pi$$ cubic inches greater than the volume of the cylinder with height 10.

E. The volume of the cylinder with height 6 is $$\frac{240}{\pi}$$ cubic inches greater than the volume of the cylinder with height 10.

Originally posted by ajit257 on 10 Jan 2011, 19:00.
Last edited by Bunuel on 02 Jan 2017, 04:55, edited 2 times in total.
Edited the question
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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vietnammba wrote:
HI Bunuel,

Can you pls explain how can i know its the circumference of the base? Thank you very much.

When you roll a paper into a cylinder one of the dimensions of the paper becomes the height of the cylinder and the another forms circumference of the base:
Attachments azn1.1.gif [ 5.23 KiB | Viewed 13400 times ]

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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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baker2145 wrote:
Here's the question:

A 10-by-6 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?

A The volume of the cylinder with height 10 is 60/pi cubic inches greater than the volume of the cylinder with height 6.

B The volume of the cylinder with height 6 is 60/pi cubic inches greater than the volume of the cylinder with height 10.

C The volume of the cylinder with height 10 is 60pi cubic inches greater than the volume of the cylinder with height 6.

D The volume of the cylinder with height 6 is 60pi cubic inches greater than the volume of the cylinder with height 10.

E The volume of the cylinder with height 6 is 240/pi cubic inches greater than the volume of the cylinder with height 10.

I am having difficulty with this one: Please help and explain, if answer if B or E, WHY it is (#/pi) and not #pi, considering pi(r-squared)(h) is the volume formula

Thanks,

Hopefully, you have some intuition about which of the possible cylinders is going to have the greater volume. Because the volume of a cylinder is directly proportional to the height and directly proportional to the square of the radius, the size of the radius has the greatest effect on the volume of the cylinder. Given this intuition we can eliminate A and C.

The answer given already is correct, but I'm going to provide some more details in term of calculation

Cylinder with height 10 and circumference 6:
$$2pi(r) = 6$$
$$r = \frac{3}{(pi)}$$
$$V = (pi)(\frac{3}{pi})^2(10)$$
$$V = \frac{90}{pi}$$

Cylinder with height 6 and circumference 10:
$$2pi(r) = 10$$
$$r = \frac{5}{(pi)}$$
$$V = (pi)(\frac{5}{pi})^2(6)$$
$$V = \frac{150}{pi}$$

150-90 = 60

So, B.
##### General Discussion
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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1
Simple math
2. Find volume (pi)*r^2*h of each
case a: 2(pi)r =10 and h = 6 --> (pi)r^2*h = (pi) [10/2*(pi)]^2 * 6 = 25*6/(pi) = 150/pi
case b: 2(pi)r =6 and h = 10 --> (pi)r^2*h = (pi) [6/2*(pi)]^2 * 10 = 9*10/(pi) = 90/pi
3. Difference is 60/pi
4. So [case a volume] when h = 6 is greater than [case b volume ] when h = 10, by 60/(pi)
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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baker2145 wrote:
Here's the question:

A 10-by-6 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?

A The volume of the cylinder with height 10 is 60/pi cubic inches greater than the volume of the cylinder with height 6.

B The volume of the cylinder with height 6 is 60/pi cubic inches greater than the volume of the cylinder with height 10.

C The volume of the cylinder with height 10 is 60pi cubic inches greater than the volume of the cylinder with height 6.

D The volume of the cylinder with height 6 is 60pi cubic inches greater than the volume of the cylinder with height 10.

E The volume of the cylinder with height 6 is 240/pi cubic inches greater than the volume of the cylinder with height 10.

I am having difficulty with this one: Please help and explain, if answer if B or E, WHY it is (#/pi) and not #pi, considering pi(r-squared)(h) is the volume formula

Thanks,

6 or 10 will be circumference ...so 2 * pi* r = 6 or 10 and hence r = #/pi....and difference would be 60/pi [applying the volume formula and taking the difference] ...would go with B
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when the paper is folded with the 10 as the height .. 6 will be the circumference not the radius.. so 2*pi*r = 6 -> r = 3/ pi.. then its pretty straightforward.. pi ( r1*r1*h1 - r2*r2*h)
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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Pretty straightforward. Plug in the values to compute the volume of the cylinder. Keep in mind 6 and 10 are the circumference of the base and not the radius. B is the right answer.
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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mun23 wrote:
A 10-by-6 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?

(A)The volume of the cylinder with height 10 is 60 / cubic inches greater than the volume of the cylinder with height 6.

(B)The volume of the cylinder with height 6 is 60 / cubic inches greater than the volume of the cylinder with height 10.

(C)The volume of the cylinder with height 10 is 60 cubic inches greater than the volume of the cylinder with height 6.

(D)The volume of the cylinder with height 6 is 60 cubic inches greater than the volume of the cylinder with height 10.

(E)The volume of the cylinder with height 6 is 240 / cubic inches greater than the volume of the cylinder with height 10.

Radius of 1 cylinder 6*10 (l*h) is 2pi r1 = 6
Radius of 2 cylinder 10*6 (l*h) is 2pi r2 = 10

Volume of cylinder is pi r square * h

Volume of 1 cylinder = 90/pi
volume of 2 = 150/pi
Difference = 60/pi
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Bunuel , can you please explain this problem. I am not able to understand the difference between Option B and D. According to me option D should be correct but its not.
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gauravsoni wrote:
Bunuel , can you please explain this problem. I am not able to understand the difference between Option B and D. According to me option D should be correct but its not.

The difference is that B says "$$\frac{60}{\pi}$$", while D says: "$$60\pi$$". Formatted the original post to make it clearer.

A 10-by-6 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?

A. The volume of the cylinder with height 10 is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the cylinder with height 6.

B. The volume of the cylinder with height 6 is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the cylinder with height 10.

C. The volume of the cylinder with height 10 is $$60\pi$$ cubic inches greater than the volume of the cylinder with height 6.

D. The volume of the cylinder with height 6 is $$60\pi$$ cubic inches greater than the volume of the cylinder with height 10.

E. The volume of the cylinder with height 6 is $$\frac{240}{\pi}$$ cubic inches greater than the volume of the cylinder with height 10.

We can make 2 cylinders:

With height of 6 and the radius of the base of $$r=\frac{5}{\pi}$$ (from $$2\pi{r}=10$$ --> $$r=\frac{5}{\pi}$$) --> $$volume=\pi{r^2}h=\frac{150}{\pi}$$.

With height of 10 and the radius of the base of $$r=\frac{3}{\pi}$$ (from $$2\pi{r}=6$$ --> $$r=\frac{3}{\pi}$$) --> $$volume=\pi{r^2}h=\frac{90}{\pi}$$.

The volume of the first one is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the second one.

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Bunuel wrote:
gauravsoni wrote:
Bunuel , can you please explain this problem. I am not able to understand the difference between Option B and D. According to me option D should be correct but its not.

The difference is that B says "$$\frac{60}{\pi}$$", while D says: "$$60\pi$$". Formatted the original post to make it clearer.

A 10-by-6 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?

A. The volume of the cylinder with height 10 is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the cylinder with height 6.

B. The volume of the cylinder with height 6 is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the cylinder with height 10.

C. The volume of the cylinder with height 10 is $$60\pi$$ cubic inches greater than the volume of the cylinder with height 6.

D. The volume of the cylinder with height 6 is $$60\pi$$ cubic inches greater than the volume of the cylinder with height 10.

E. The volume of the cylinder with height 6 is $$\frac{240}{\pi}$$ cubic inches greater than the volume of the cylinder with height 10.

We can make 2 cylinders:

With height of 6 and the radius of the base of $$r=\frac{5}{\pi}$$ (from $$2\pi{r}=10$$ --> $$r=\frac{5}{\pi}$$) --> $$volume=\pi{r^2}h=\frac{150}{\pi}$$.

With height of 10 and the radius of the base of $$r=\frac{3}{\pi}$$ (from $$2\pi{r}=6$$ --> $$r=\frac{3}{\pi}$$) --> $$volume=\pi{r^2}h=\frac{90}{\pi}$$.

The volume of the first one is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the second one.

Thanks Bunuel, I thought of using the width of the rectangle as the radius, now i see that its actually the circumference of the circular base. Thanks for the clarification.
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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HI Bunuel,

Can you pls explain how can i know its the circumference of the base? Thank you very much.
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I get it now, thank you Board of Directors P
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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we have 2 possible cylinders:
h=10, or h=6.
now, with radius, it is more tricky.
We know that Circumference is 2piR.
now, if h=10, then 2piR=6, or R=3/pi
if h=6, then 2piR=10, or 5/pi.

volume is pi*r^2*h.
1. h=10, r=3/pi. volume is 90/pi
2. h=6, r=5/pi. volume is 150/pi.

we can eliminate right away A, C, and E. - A, B because the cylinder with h=6 is greater. E because the difference is 60/pi and not 240/pi.
D is incorrect because it tells 60pi, when actually it is 60/pi.

B thus is the correct answer.
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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ajit257 wrote:
A 10-by-6 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?

A. The volume of the cylinder with height 10 is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the cylinder with height 6.

B. The volume of the cylinder with height 6 is $$\frac{60}{\pi}$$ cubic inches greater than the volume of the cylinder with height 10.

C. The volume of the cylinder with height 10 is $$60\pi$$ cubic inches greater than the volume of the cylinder with height 6.

D. The volume of the cylinder with height 6 is $$60\pi$$ cubic inches greater than the volume of the cylinder with height 10.

E. The volume of the cylinder with height 6 is $$\frac{240}{\pi}$$ cubic inches greater than the volume of the cylinder with height 10.

The trick of this problem is to realize that 6in or 10in, the given length and width, are not the radius of the folded piece of paper; they are the circumference. So you need to solve for the circumference of each (5/pi and 3/pi, respectively). Then you plug them into the volume formula (piR^2H) to arrive at 150/pi - 90/pi.
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A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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V = pi(5/pi)^2 x 6 = 150/pi. I'm confused as too why two pi turns into 150/pi.

V = pi(3/pi)^2 x 10 = 90/pi. I'm confused as too why two pi turns into 90/pi.

Can someone explain? Aren't we supposed to cross-cancel the pi out?

Originally posted by OCDianaOC on 10 Nov 2017, 19:25.
Last edited by OCDianaOC on 11 Nov 2017, 08:09, edited 1 time in total.
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OCDianaOC wrote:
V = pi(5/pi)*2 x 6 = 150/pi. I'm confused as too why two pi turns into 150/pi.

V = pi(3/pi)*2 x 10 = 90/pi. I'm confused as too why two pi turns into 90/pi.

Can someone explain? Aren't we supposed to cross-cancel the pi out?

The volume formula is $$volume=\pi{r^2}h$$. Notice that r there is squared not multiplied by 2.
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Bunuel wrote:
OCDianaOC wrote:
V = pi(5/pi)*2 x 6 = 150/pi. I'm confused as too why two pi turns into 150/pi.

V = pi(3/pi)*2 x 10 = 90/pi. I'm confused as too why two pi turns into 90/pi.

Can someone explain? Aren't we supposed to cross-cancel the pi out?

The volume formula is $$volume=\pi{r^2}h$$. Notice that r there is squared not multiplied by 2.

I'm aware of that. Sorry, I put "*" hoping to imply it meant squared since I couldn't find another symbol for that on my keyboard. Let me rephrase,

V = pi(5/pi)^2 x 6 = 150/pi. I'm confused as too why two pi turns into 150/pi.

V = pi(3/pi)^2 x 10 = 90/pi. I'm confused as too why two pi turns into 90/pi.

Can someone explain? Aren't we supposed to cross-cancel the pi out?
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Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a  [#permalink]

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OCDianaOC wrote:
Bunuel wrote:
OCDianaOC wrote:
V = pi(5/pi)*2 x 6 = 150/pi. I'm confused as too why two pi turns into 150/pi.

V = pi(3/pi)*2 x 10 = 90/pi. I'm confused as too why two pi turns into 90/pi.

Can someone explain? Aren't we supposed to cross-cancel the pi out?

The volume formula is $$volume=\pi{r^2}h$$. Notice that r there is squared not multiplied by 2.

I'm aware of that. Sorry, I put "*" hoping to imply it meant squared since I couldn't find another symbol for that on my keyboard. Let me rephrase,

V = pi(5/pi)^2 x 6 = 150/pi. I'm confused as too why two pi turns into 150/pi.

V = pi(3/pi)^2 x 10 = 90/pi. I'm confused as too why two pi turns into 90/pi.

Can someone explain? Aren't we supposed to cross-cancel the pi out?

$$\pi$$ there is also gets squared.

h = 6 and $$r=\frac{5}{\pi}$$:

$$volume=\pi{r^2}h=\pi*(\frac{5}{\pi})^2*6=\pi*\frac{25}{\pi^2}*6=\frac{150}{\pi}$$.
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Oh! That's what I was missing! Thanks Brunel... so we multiple out straight across (squaring num and denom) then cancel out the extra pi from numerator and denominator!  Re: A 10-by-6 inch piece of paper is used to form the lateral surface of a   [#permalink] 11 Nov 2017, 09:12

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