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((a^2)^6)^(1/3) = ?

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((a^2)^6)^(1/3) = ?  [#permalink]

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New post 02 Jul 2020, 01:44
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

94% (00:25) correct 6% (00:33) wrong based on 36 sessions

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Re: ((a^2)^6)^(1/3) = ?  [#permalink]

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New post 02 Jul 2020, 01:47
(a^2)^(6/3)

(a^2)^2
a^4

Option : B

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Re: ((a^2)^6)^(1/3) = ?  [#permalink]

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New post 02 Jul 2020, 01:54
2
\(\sqrt [3] { (a^2)^6}= \sqrt [3] { a^{2 \times 6}} = \sqrt [3] { a^{12}} = a^{(12/3)} = a^4\)

OA, B

Bunuel wrote:
\(\sqrt [3] { (a^2)^6}=?\)


(A) \(a^2\)

(B) \(a^4\)

(C) \(a^5\)

(D) \(a^9\)

(E) \(a^{11}\)
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Re: ((a^2)^6)^(1/3) = ?  [#permalink]

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New post 02 Jul 2020, 01:57
Explanation:
= (a^2)^6/3
= (a^2)^2
= a^4

IMO-B
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Re: ((a^2)^6)^(1/3) = ?  [#permalink]

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New post 02 Jul 2020, 02:07
Bunuel wrote:
\(\sqrt [3] { (a^2)^6}=?\)


(A) \(a^2\)

(B) \(a^4\)

(C) \(a^5\)

(D) \(a^9\)

(E) \(a^{11}\)


Solution


    • \((a^2)^6 = a^{2*6} = a^{12}\)

    • Therefore, \(\sqrt[3]{(a^2)^6} = \sqrt[3]{a^{12}} = (a^{12})^{\frac{1}{3}} = a^{12* \frac{1}{3}} = a^4\)

Thus, the correct answer is Option B.
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Re: ((a^2)^6)^(1/3) = ?  [#permalink]

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New post 02 Jul 2020, 03:00
Bunuel wrote:
\(\sqrt [3] { (a^2)^6}=?\)


(A) \(a^2\)

(B) \(a^4\)

(C) \(a^5\)

(D) \(a^9\)

(E) \(a^{11}\)


\(\sqrt [3] { (a^2)^6}= a^{\frac{2*6}{3}} = a^4\)

IMO B
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Re: ((a^2)^6)^(1/3) = ?   [#permalink] 02 Jul 2020, 03:00

((a^2)^6)^(1/3) = ?

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