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28 Apr 2020, 05:24
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
64% (02:51) correct
36%
(03:01)
wrong
based on 152
sessions
History
Date
Time
Result
Not Attempted Yet
A and B undertake to do a piece of work for Rs. 480. A alone can do it in 75 days while B alone can do it in 40 days. With the help of C, they finish the work in 25 days. How much Rs should C get for his work?
A. 20
B. 40
C. 60
D. 80
E. 120
A. 20
B. 40
C. 60
D. 80
E. 120
28 Apr 2020, 05:50
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GMATBusters
Let work = Multiple of (75 and 70) = 300 units
A does 600 unit work in 75 days i.e. work done per day = 8 units
A does 600 unit work in 40 days i.e. work done per day = 15 units
A and B work together then work done in one day = 8+15 = 23 units
A, B and C together can finish work in 25 days i.e. their combined work units per day = 600/25 = 24 units
i.e. C work per day = 24-23 = 1 unit work
C's share = (1/24)*480 = Rs.20
Answer: Option A
22 Nov 2020, 07:09
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Work done in 1 day by A = \(\frac{1}{75}\)
Work done in 1 day by B = \(\frac{1}{40}\)
Work done in 1 day by C = \(\frac{1}{C}\)
Work done in 1 day by A + B + C = \(\frac{1}{75} + \frac{1}{45} + \frac{1}{C} = \frac{1}{25}\)
Therefore \(\frac{1}{C} = \frac{1}{25} - \frac{1}{75} - \frac{1}{40} = \frac{24 - 8 - 15}{600} = \frac{1}{600}\)
Ratio of work = \(\frac{1}{75} : \frac{1}{40} : \frac{1}{600}\). Bringing them to a common base of 600, the ratio = 8 : 15 : 1
The Amount C gets = \(\frac{1}{24} * 480 = 20\)
Option A
Arun Kumar
Work done in 1 day by B = \(\frac{1}{40}\)
Work done in 1 day by C = \(\frac{1}{C}\)
Work done in 1 day by A + B + C = \(\frac{1}{75} + \frac{1}{45} + \frac{1}{C} = \frac{1}{25}\)
Therefore \(\frac{1}{C} = \frac{1}{25} - \frac{1}{75} - \frac{1}{40} = \frac{24 - 8 - 15}{600} = \frac{1}{600}\)
Ratio of work = \(\frac{1}{75} : \frac{1}{40} : \frac{1}{600}\). Bringing them to a common base of 600, the ratio = 8 : 15 : 1
The Amount C gets = \(\frac{1}{24} * 480 = 20\)
Option A
Arun Kumar
22 Nov 2020, 10:38
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GMATBusters
Let the total work be 600 units (LCM of 75 , 40 & 25 )
So, Efficiency of A is 8 , Efficiency of B is 15 & Efficiency of A + B + C is 24
Thus, Efficiency of C is Efficiency of ( A + B + C ) - Efficiency of A - Efficiency of B = 24 - 8 - 15
Thus, Efficiency of C is 1 and C gets 1/24*480 = 20 , Answer must be (A)
