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A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow

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A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow  [#permalink]

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New post 16 Aug 2016, 06:02
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

70% (01:22) correct 30% (01:05) wrong based on 47 sessions

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A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow jellybeans; these jellybeans are the only items in the bag. If a person reaches into the bag and picks out only purple jellybeans, how many jellybeans would the person have to pick out in order to double the probability that a jellybean picked out of the bag at random would be a green jellybean?

A. 5
B. 15
C. 19
D. 24
E. 25

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Re: A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow  [#permalink]

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New post 16 Aug 2016, 08:10
Bunuel wrote:
A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow jellybeans; these jellybeans are the only items in the bag. If a person reaches into the bag and picks out only purple jellybeans, how many jellybeans would the person have to pick out in order to double the probability that a jellybean picked out of the bag at random would be a green jellybean?

A. 5
B. 15
C. 19
D. 24
E. 25

Chances of picking a green at present = 15 / (26 + 15 + 9) = 15/50 = 3/10
So required is double that chance = 2 * 3/10 = 3/5

since only purple are removed, the new count be x, 3/5 = 15 (x + 15 + 9)
solving for x gives x = 1.
So 26 -1 = 25 purple jellybeans needs to be removed.
Answer is E


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Re: A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow  [#permalink]

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New post 15 Apr 2018, 12:01
+1 for option E. The required probability is #G/Total. We need to double probability. Current probability is 15/50. We need the probability to become 15/25 by removing only Purple jellybeans. G+Y = 24 jellybeans ; 1 more jellybean ; 25 purple jellybeans need to be taken out.
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Re: A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow &nbs [#permalink] 15 Apr 2018, 12:01
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