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Re: A boy working alone at 50 percent of his normal speed took 3 more days [#permalink]
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Kudos
pretty complex question.

I have an alternative solution. let m be speed of man and b be speed of boy. we need to how much time it takes to produce 2n units in 75% speed => 2n/(3b/4) = 8n/3b . so we need to use the given info to eliminate m and find n/b ratio

from 3n units case, we get 9m + 15b = 3n . that is 3m+5b = n
from n units case, we get 2b(t+3) = 3m(t) . rearranging, this gives 1 + (t/3) = 3m/2b . now place t = 4n/3m (considering man's equation alone) and we get 1 + (9m/4n) = 3m/2b

using previous eqaution, work towards eliminating m and we get a equation in n^2, b^2 and nb. divide by b^2. we get a quadratic in (n/b). solve the quadratic and we get 2 values for n/b - 30/4 and 1. 1 doesnt make sense, so its 30/4. thus final answer is 8/3*(30/4) = 20.
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Re: A boy working alone at 50 percent of his normal speed took 3 more days [#permalink]
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