hi guys, first post

i have a problem in understanding this question and why my logic is wrong, this is how i try to solve the problem:

i use the formula n!/(n-k)!*k!

so first n=3 and k=1 because we have 3 managers to choose from and can choose one

3!/(2!*1!)

second n=3 and k=2 because we have 3 managers to choose from and can choose two

3!/(2!*1!)

third n=8 and k=1 because we have 8 non-managers to choose from and can choose one

8!/(7!*1!)

fourth n=8 and k=2 because we have 8 non-managers to choose from and can choose two

8!/(6!*2!)

then i multiply all the parts= 3*3*8*28=2016

can someone please help me

thank you