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a+b+c=500 ...(1)

10a+9b+7c=4180 ...(2)

(2)-10*(1)

=>b+3c=820

c>b

rej options for b which are multiple of 3

b=100, c=140 (ok)
b=190, c=210 (ok)
b=250 onwards, c<b
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parkhydel
­
­A certain theater has 500 seats. Some are on the main floor and sell for $50 each; some are in the first balcony and sell for $45 each; and the rest are in the second balcony and sell for $35 each. When all of the seats are sold for a performance, the gross revenue for that performance is $20,900. Of the three seating areas, the second balcony has the most seats.

Select for First balcony a number of seats in this theater’s first balcony and select for Second balcony a number of seats in this theater’s second balcony such that the selections are jointly consistent with the information provided. Make only two selections, one in each column.
Here is what we know:

a + b + c = 500 (Total number of seats)

50a + 45b + 35c = 20,900

We have 3 unknowns and 2 equations. We will get many solutions. The question is interested in first balcony and second balcony seats so we should eliminate "a".

50 (500 - b - c) + 45b + 35c = 20,900
b + 3c = 820

Since c is greater than both a and b, we know it must be greater than 166 (1/3rd of 500).
If b and c were equal, c would be 205 (1/4th of 820). Hence c must be greater than 205.

Try c = 210
b = 190
Both options are available in table. Hence select 190 and 210. ANSWER ­
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I have just changed the variables e.g for me 35(500-x-y) is the second balcony but I am not getting the correct answer, the equation is

3x+2y=680
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­50M + 45F + 35S = 20900
10M + 9F + 7S = 4180 (1)

M + F + S = 500
10M + 10F + 10S = 5000 (2)

(2) - (1)
=> F + 3S = 820

820 leaves a remaind of 1 when being divided by 3
3S is divisible by 3
=> F leaves a remaind of 1 when being divided by 3
=> F is either 100, 190 or 250 
F cannot be 250 because S has the most seats

=> F is either 100 or 190

F = 100 => \(S = \frac{820 - 100}{3} = 240\)
F = 190 => \(S = \frac{820 - 190}{3} = 210\)

F = 190; S = 210

 ­
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@ KarishmaB In GMAT-speak, 'most' or 'majority' implies more than 50% (or more than half) - why is the same not applicable here?
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AugmentAdInf
In GMAT-speak, 'most' or 'majority' implies more than 50% (or more than half) - why is the same not applicable here?
In this case, the wording is not "the second balcony has most seats."

The wording is "the second balcony has THE most seats."

With the word "the" before "most," the statement conveys that, among the three balconies, the second balcony has the greatest number of seats.
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to do it faster should go for non 3 multiples as first flor then only to option to equate .

chetan2u
­A certain theater has 500 seats. Some are on the main floor and sell for $50 each; some are in the first balcony and sell for $45 each; and the rest are in the second balcony and sell for $35 each. When all of the seats are sold for a performance, the gross revenue for that performance is $20,900. Of the three seating areas, the second balcony has the most seats.

Select for First balcony a number of seats in this theater’s first balcony and select for Second balcony a number of seats in this theater’s second balcony such that the selections are jointly consistent with the information provided. Make only two selections, one in each column.­

ID: 700232­
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