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Director  Joined: 25 Apr 2012
Posts: 660
Location: India
GPA: 3.21
WE: Business Development (Other)
A firm's annual revenue grows twice as fast as its costs. In  [#permalink]

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A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009? A. 700 B. 1000 C. 1300 D. 1600 E. 2000 I found this problem quite difficult to be solved under 2 mins. Will be really keen to know if there are any shortcuts to handle such Questions. Would you rate this problem a 700 + ?? _________________ “If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.” Most Helpful Expert Reply Director  S Joined: 17 Dec 2012 Posts: 626 Location: India Re: A firm's annual revenue grows twice as fast as its costs. In [#permalink] Show Tags 5 1 1. Let the revenues and costs in 2007 be r1 and c1 respectively. We have r1-c1=-1000 2. Let revenues in 2008 be r2 and c2 respectively. We have r2-c2=0 3. Let revenues and costs in 2009 be r3 and c3 respectively. we have r3=1.44r1. 4. Since the growth rate of sales is constant, growth rate per year is 20%. growth rate of costs is half of that which is 10% 5. (2) can be written as 1.2 r1-1.1 c1=0 6. Solving for (1) and (5), we have c1=12000 andr1=11000 7. r3=1.44*11000= 15840 and c3=1.21*12000=14520 8. Therefore profit in 2009=15840-14520=1320 The answer should be$1320
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Intern  Joined: 29 Jan 2013
Posts: 21
Location: United States
Concentration: Strategy
GMAT 1: 710 Q50 V36 GPA: 3.4
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mridulparashar1 wrote:
A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009? A. 700 B. 1000 C. 1300 D. 1600 E. 2000 First solve for how much revenue is increasing each year: R2008 = R2007*(1+x) R2009 = R2007*(1+x)^2=1.44*R2007 (1+x)^2 = 1.44 1+x=1.2 x=0.2 aka revenue increases 20% each year and cost increases 10% annually Next solve for R2007 and C2007: R2007 = C2007 - 1000 1.2*R2007 - 1.1*C2007 = 0 1.2*[C2007 - 1000] - 1.1*C2007 = 0 0.1*C2007 = 1,200 C2007 = 12,000 R2007 = 11,000 Finally find 2009 profits: Profit2009 = 1.44*11,000 - 1.21*12,000 Profit2009 = 15,840 - 14,520 Profit2009 = 1320 Answer: C Senior Manager  Joined: 10 Jul 2013 Posts: 289 Re: A firm's annual revenue grows twice as fast as its costs. In [#permalink] Show Tags 2013gmat wrote: A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a$1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?

A $700 B$1000
C $1300 D$1600
E $2000 can anyone explain above question ? thanks By strict definitions, revenue can not be negative. But in the corrupt world of finance, revenue is a number between positive infinity and negative infinity depending on how the upper management instruct the finance people how to lie on the spreadsheets in their submissions to the Securities and exchange commission. _________________ Asif vai..... Manager  Joined: 21 Aug 2012 Posts: 100 Re: A firm's annual revenue grows twice as fast as its costs. In [#permalink] Show Tags 1 SravnaTestPrep wrote: 1. Let the revenues and costs in 2007 be r1 and c1 respectively. We have r1-c1=-1000 2. Let revenues in 2008 be r2 and c2 respectively. We have r2-c2=0 3. Let revenues and costs in 2009 be r3 and c3 respectively. we have r3=1.44r1. 4. Since the growth rate of sales is constant, growth rate per year is 20%. growth rate of costs is half of that which is 10% 5. (2) can be written as 1.2 r1-1.1 c1=0 6. Solving for (1) and (5), we have c1=12000 andr1=11000 7. r3=1.44*11000= 15840 and c3=1.21*12000=14520 8. Therefore profit in 2009=15840-14520=1320 The answer should be$1320

How did you deduce that "growth rate per year is 20%."????
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Director  S
Joined: 17 Dec 2012
Posts: 626
Location: India
Re: A firm's annual revenue grows twice as fast as its costs. In  [#permalink]

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jaituteja wrote:
SravnaTestPrep wrote:
1. Let the revenues and costs in 2007 be r1 and c1 respectively. We have r1-c1=-1000
2. Let revenues in 2008 be r2 and c2 respectively. We have r2-c2=0
3. Let revenues and costs in 2009 be r3 and c3 respectively. we have r3=1.44r1.
4. Since the growth rate of sales is constant, growth rate per year is 20%. growth rate of costs is half of that which is 10%
5. (2) can be written as 1.2 r1-1.1 c1=0
6. Solving for (1) and (5), we have c1=12000 andr1=11000
7. r3=1.44*11000= 15840 and c3=1.21*12000=14520
8. Therefore profit in 2009=15840-14520=1320

The answer should be $1320 How did you deduce that "growth rate per year is 20%."???? The rate can be calculated from the formula (1+r/100) ^2 = 1.44 , which will give r=20 _________________ Srinivasan Vaidyaraman Sravna Test Prep http://www.sravnatestprep.com Holistic and Systematic Approach Manager  Joined: 20 Jul 2012 Posts: 112 Location: India WE: Information Technology (Computer Software) A firm's annual revenue grows twice as fast as its costs. [#permalink] Show Tags A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a$1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?
a)$700 b)$1000
c)$1300 d)$1600
e)$2000 Also whats the level of this question ? Math Expert V Joined: 02 Sep 2009 Posts: 58402 Re: A firm's annual revenue grows twice as fast as its costs. [#permalink] Show Tags akankshasoneja wrote: A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a$1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?
a)$700 b)$1000
c)$1300 d)$1600
e)$2000 Also whats the level of this question ? Merging similar topics. Please refer to the solutions above. As for the difficulty level, I'd say it's ~650-700. _________________ Manager  Joined: 04 Jan 2014 Posts: 94 Re: A firm's annual revenue grows twice as fast as its costs. In [#permalink] Show Tags I am lost. Can't solve it. Retired Moderator Joined: 20 Dec 2013 Posts: 166 Location: United States (NY) GMAT 1: 640 Q44 V34 GMAT 2: 710 Q48 V40 GMAT 3: 720 Q49 V40 GPA: 3.16 WE: Consulting (Venture Capital) Re: A firm's annual revenue grows twice as fast as its costs. In [#permalink] Show Tags tough one for sure. 3rd year revenue going up by 44% = 1st year revenue * (12^2/10^2) so 2nd year revenue is 1st year revenue * (12/10) --> 1st year revenue + 1st year revenue (2/10) so growth rate of revenue is 20% and costs is 10% _________________ Senior Manager  Joined: 08 Apr 2012 Posts: 327 Re: A firm's annual revenue grows twice as fast as its costs. In [#permalink] Show Tags SravnaTestPrep wrote: 1. Let the revenues and costs in 2007 be r1 and c1 respectively. We have r1-c1=-1000 2. Let revenues in 2008 be r2 and c2 respectively. We have r2-c2=0 3. Let revenues and costs in 2009 be r3 and c3 respectively. we have r3=1.44r1. 4. Since the growth rate of sales is constant, growth rate per year is 20%. growth rate of costs is half of that which is 10% 5. (2) can be written as 1.2 r1-1.1 c1=0 6. Solving for (1) and (5), we have c1=12000 andr1=11000 7. r3=1.44*11000= 15840 and c3=1.21*12000=14520 8. Therefore profit in 2009=15840-14520=1320 The answer should be$1320

Something is messing up my calculations.
I substituted the amount by which C and R go up with X.
This meant that at 2009 we needed to find out : R*x^4 - C*X^2.
Since X^4 = 1.44 -> X^2 = 1.2
And that's why I multiplied C by 1.2 and not 1.21.
Why is this wrong?
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Joined: 16 Oct 2010
Posts: 9705
Location: Pune, India
Re: A firm's annual revenue grows twice as fast as its costs. In  [#permalink]

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ronr34 wrote:
SravnaTestPrep wrote:
1. Let the revenues and costs in 2007 be r1 and c1 respectively. We have r1-c1=-1000
2. Let revenues in 2008 be r2 and c2 respectively. We have r2-c2=0
3. Let revenues and costs in 2009 be r3 and c3 respectively. we have r3=1.44r1.
4. Since the growth rate of sales is constant, growth rate per year is 20%. growth rate of costs is half of that which is 10%
5. (2) can be written as 1.2 r1-1.1 c1=0
6. Solving for (1) and (5), we have c1=12000 andr1=11000
7. r3=1.44*11000= 15840 and c3=1.21*12000=14520
8. Therefore profit in 2009=15840-14520=1320

The answer should be $1320 Something is messing up my calculations. I substituted the amount by which C and R go up with X. This meant that at 2009 we needed to find out : R*x^4 - C*X^2. Since X^4 = 1.44 -> X^2 = 1.2 And that's why I multiplied C by 1.2 and not 1.21. Why is this wrong? C and R do not go up by the same rate X. You are given that revenue grows twice as fast as cost. So if rate of revenue growth is X, rate of cost growth is X/2. _________________ Karishma Veritas Prep GMAT Instructor Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options > Veritas Prep GMAT Instructor V Joined: 16 Oct 2010 Posts: 9705 Location: Pune, India Re: A firm's annual revenue grows twice as fast as its costs. In [#permalink] Show Tags 1 3 WoundedTiger wrote: A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a$1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?

A. 700
B. 1000
C. 1300
D. 1600
E. 2000

I found this problem quite difficult to be solved under 2 mins. Will be really keen to know if there are any shortcuts to handle such Questions.
Would you rate this problem a 700 + ??

Revenues increased by 44% in 2 years. Rate of revenue increase per year is the same. So

$$(1 + x)^2 = 1.44$$
$$x = 20%$$

So revenue increases by 20% per year and since cost increases at half the rate, cost increases by 10% every year.

Say 2007 revenue is R and 2007 cost is C.
We know C = R + 1000 ....(I)

In 2008, they break even.
So 1.1*C = 1.2R
Substituting from (I), 1.1*(R + 1000) = 1.2R
R = 11,000
C = 12,000

In 2009,
Profit = (1.2)^2*R - (1.1)^2C = 1.44*11,000 - 1.21*12000 = 1320
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Senior Manager  G
Joined: 03 Apr 2013
Posts: 264
Location: India
Concentration: Marketing, Finance
GMAT 1: 740 Q50 V41 GPA: 3
A firm's annual revenue grows twice as fast as its costs. In  [#permalink]

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WoundedTiger wrote:
A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a \$1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?

A. 700
B. 1000
C. 1300
D. 1600
E. 2000

I found this problem quite difficult to be solved under 2 mins. Will be really keen to know if there are any shortcuts to handle such Questions.
Would you rate this problem a 700 + ??

First of all..+1 for the question.
I got the right answer..but the only thing I felt eerie about this problem is that it has a lot of calculations to be done under the given timing constraints..Experts..please suggest something about the calculations this has. And what level would you classify this problem as..

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Concentration: Finance, Nonprofit
GMAT 1: 680 Q49 V33 GMAT 2: 690 Q51 V31 GMAT 3: 710 Q50 V36 GPA: 3.4
A firm's annual revenue grows twice as fast as its costs. In  [#permalink]

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Profit=Revenue-Cost

2007:
-1000=R1-C1

2008:
0=(1+2X%)R1-(1+X%)C1

2009:
P3=(1+2X%)^2*R1-(1+X%)^2*C1

we've already known that R3=1.44R1, so (1+2X%)^2=1.44, X=10

we put X=10 back to the equation of 2008:
0=1.2R1-1.1C1, and we have 1.2R1=1.1C1, which we could combine with the equation of 2007.
Then we have C1=12000, R1-11000

Finally, take C1 and R1 into the equation of 2009 and we got P3=15840-14520=1320

Thanks,
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Re: A firm's annual revenue grows twice as fast as its costs. In  [#permalink]

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