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Director  V
Joined: 18 Feb 2019
Posts: 582
Location: India
GMAT 1: 460 Q42 V13 GPA: 3.6
A four-digit number is formed using the digits 3,4,6 and 7 without rep  [#permalink]

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Difficulty:   85% (hard)

Question Stats: 40% (02:36) correct 60% (02:19) wrong based on 48 sessions

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A four-digit number is formed using the digits 3,4,6 and 7 without repetition. All the possible numbers so formed are added and the sum is equal to P. Which of the following is the value of P?

A. 133200
B. 123320
C. 133220
D. 133320
E. None of these
Intern  B
Joined: 24 Jun 2018
Posts: 35
Re: A four-digit number is formed using the digits 3,4,6 and 7 without rep  [#permalink]

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1
We have four digits ie. 3, 4, 6 and 7.

The four digits can be arranged(without repetition) in 4! ways ie. 24 ways.

Now, just to make the solution more comprehensive, let's write down a few of these numbers.

First lets fix the first digit as 3. Possible numbers are:

3467
3476
3647
3674
3746
3764

We can see that each digit repeats twice in unit's place, twice in ten's place and twice in hundred's place.
When we change the first digit from 3 to 4, 6 and 7, a similar pattern is observed.

Hence when 3 is fixed 4, 6 and 7 repeat twice at each location.
When 4 is fixed, 3,6 and 7 repeat twice.
When 6 is fixed, 3,4 and 7 repeat twice
When 7 is fixed, 3,4 and 6 repeat twice.

All in all, all digits are repeated six times.

Hence 3x6+4x6+6x6+7x6=120 --->(1)

Imagine, all possible combinations lined up vertically to be added.

Starting at unit's place, we leave 0 and carry over 12 to tens place (from (1) we know we get 120)

At tens place, since the same digits have been repeated, we get 120 + 12 from carryover. Hence 132.
We leave 2 and carry over 13.

At hundreds place, again we get 120 + 13. Hence 133.
Leave 3 and carry over 13.

At thousands place, we get 120 + 13. Hence 133.
Since we dont need to carry over any further, we have arrived at our number.

Ans: 133320
Veritas Prep GMAT Instructor V
Joined: 16 Oct 2010
Posts: 9701
Location: Pune, India
Re: A four-digit number is formed using the digits 3,4,6 and 7 without rep  [#permalink]

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kiran120680 wrote:
A four-digit number is formed using the digits 3,4,6 and 7 without repetition. All the possible numbers so formed are added and the sum is equal to P. Which of the following is the value of P?

A. 133200
B. 123320
C. 133220
D. 133320
E. None of these

Using digits 3, 4, 6 and 7, you can make 4! = 24 numbers without repetition.
Since the probability of each digit in any place is the same as the probability of any other digit in that place, we will have 6 numbers with 3 in units place, 6 numbers with 4 in units place, 6 numbers with 6 in units place and 6 numbers with 7 in units place.
Same for tens place, hundreds place and thousands place.

4673
4763
...
6734
7634
...
...

Sum = 3*6 + 4*6 + 6*6 + 7*6 + 10*(3*6 + 4*6 + 6*6 + 7*6) + 100*(3*6 + 4*6 + 6*6 + 7*6) + 1000*(3*6 + 4*6 + 6*6 + 7*6)
Sum = 6*20 *(1 + 10 + 100 + 1000) = 120 * 1111
Sum = 133,320

_________________
Karishma
Veritas Prep GMAT Instructor

Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options > Re: A four-digit number is formed using the digits 3,4,6 and 7 without rep   [#permalink] 28 Feb 2019, 03:41
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