Last visit was: 18 Jan 2025, 20:47 It is currently 18 Jan 2025, 20:47
Home
GMAT
Messages
Tests
Schools
Reviews
Social
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
pushpitkc
User avatar
Joined: 26 Feb 2016
Last visit: 24 Apr 2024
Posts: 2,847
Own Kudos:
5,648
 [2]
Given Kudos: 47
Location: India
GPA: 3.12
Posts: 2,847
Kudos: 5,648
 [2]
A metallic cubical box was hammered and moulded into a rectangular box 14 Apr 2019, 02:47
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

65% (hard)

Question Stats:

58% (02:18) correct 42% (01:55) wrong based on 81 sessions

History

Date
Time
Result
Not Attempted Yet
A metallic cubical box was hammered and moulded into a rectangular box such that the only change was that the breadth got tripled. What was the percentage change in total surface area?

A. 33.33%
B. 66.67%
C. 100%
D. 133.33%
E. 200%

Source: Experts Global

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
ShowHide Answer
Official Answer
D
User avatar
saukrit
User avatar
Joined: 05 Jul 2018
Last visit: 02 Sep 2024
Posts: 378
Own Kudos:
410
 [2]
Given Kudos: 325
Status:Current student at IIMB
Affiliations: IIM Bangalore
Location: India
Concentration: General Management, Technology
Schools: IIMB EPGP'22 (A)
GMAT 1: 600 Q47 V26
GRE 1: Q162 V149
GPA: 3.6
WE:Information Technology (Consulting)
Products:
My Reviews
Schools: IIMB EPGP'22 (A)
GMAT 1: 600 Q47 V26
GRE 1: Q162 V149
Posts: 378
Kudos: 410
 [2]
A metallic cubical box was hammered and moulded into a rectangular box Updated on: 16 Apr 2019, 01:36
Originally posted by saukrit on 14 Apr 2019, 03:06.
Last edited by saukrit on 16 Apr 2019, 01:36, edited 1 time in total.
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Although the scenario is too hypothetical to think of, wherein just one side of the new cuboid has tripled after hammering and everything else remains unchanged, yet considering the hypothesis to be real the answer goes as below.

Tripling one side of the cuboid the surface area becomes 14x of the original surface area 6x.

Percent Change in Volume=\(\frac{8x}{6x}*100\) = 133.33%

Hence, the answer is D
User avatar
Sanjeetgujrall
User avatar
Joined: 04 Sep 2016
Last visit: 26 Apr 2024
Posts: 50
Own Kudos:
57
 [2]
Given Kudos: 66
Location: Germany
GPA: 3
Posts: 50
Kudos: 57
 [2]
A metallic cubical box was hammered and moulded into a rectangular box 15 Apr 2019, 02:10
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
themindful
Although the scenario is too hypothetical to think of, wherein just one side of the new cuboid has tripled after hammering and everything else remains unchanged, yet considering the hypothesis to be real the answer goes as below.

Tripling one side of the cuboid the volume become 3x of the original volume x.

Change in Volume=\(\frac{(3x-x)}{x}*100\) = 200%

Hence, the answer is E

I think the answer is D. They have asked change in surface area and not volume

Posted from my mobile device
avatar
SantoshSukumaran
avatar
Joined: 13 Jul 2018
Last visit: 27 Jul 2021
Posts: 22
Own Kudos:
6
Given Kudos: 20
Location: India
Schools: EDHEC
GPA: 2.49
Schools: EDHEC
Posts: 22
Kudos: 6
A metallic cubical box was hammered and moulded into a rectangular box 15 Apr 2019, 12:28
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi the question stem asks % change in surface area.

Posted from my mobile device
avatar
SantoshSukumaran
avatar
Joined: 13 Jul 2018
Last visit: 27 Jul 2021
Posts: 22
Own Kudos:
6
Given Kudos: 20
Location: India
Schools: EDHEC
GPA: 2.49
Schools: EDHEC
Posts: 22
Kudos: 6
A metallic cubical box was hammered and moulded into a rectangular box 15 Apr 2019, 12:30
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Will the answer be option D

Posted from my mobile device
User avatar
saukrit
User avatar
Joined: 05 Jul 2018
Last visit: 02 Sep 2024
Posts: 378
Own Kudos:
410
Given Kudos: 325
Status:Current student at IIMB
Affiliations: IIM Bangalore
Location: India
Concentration: General Management, Technology
Schools: IIMB EPGP'22 (A)
GMAT 1: 600 Q47 V26
GRE 1: Q162 V149
GPA: 3.6
WE:Information Technology (Consulting)
Products:
My Reviews
Schools: IIMB EPGP'22 (A)
GMAT 1: 600 Q47 V26
GRE 1: Q162 V149
Posts: 378
Kudos: 410
A metallic cubical box was hammered and moulded into a rectangular box 16 Apr 2019, 01:39
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sanjeetgujrall
themindful
Although the scenario is too hypothetical to think of, wherein just one side of the new cuboid has tripled after hammering and everything else remains unchanged, yet considering the hypothesis to be real the answer goes as below.

Tripling one side of the cuboid the volume become 3x of the original volume x.

Change in Volume=\(\frac{(3x-x)}{x}*100\) = 200%

Hence, the answer is E

I think the answer is D. They have asked change in surface area and not volume

Posted from my mobile device
Thanks for highlighting. Updated my response. My bad :)
User avatar
Maxximus
User avatar
Experts' Global Representative
Joined: 19 Feb 2010
Last visit: 03 Nov 2023
Posts: 261
Own Kudos:
233
Given Kudos: 90
Expert reply
Posts: 261
Kudos: 233
A metallic cubical box was hammered and moulded into a rectangular box 19 Jul 2019, 04:18
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Interestingly, some students wrote to us saying that if the width is changed, the volume also changed and that is not possible by hammering (as volume of the solid must remain constant). The mistake in that approach is that one is confusing volume of the "box" (not a solid, as such) with the volume of the "metal" (or solid). Imagine, the box is empty inside and practically, the volume of the box is the volume of the empty space and not the volume of the metal enclosing the empty space :-)
User avatar
Salman_Iqbal_Bappy
User avatar
Joined: 24 Aug 2017
Last visit: 12 Nov 2019
Posts: 6
Given Kudos: 11
Posts: 6
Kudos: 0
A metallic cubical box was hammered and moulded into a rectangular box 21 Jul 2019, 09:41
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Tripling one side of the cuboid the surface area becomes 14x of the original surface area 6x.
How??? Can you explain???

Posted from my mobile device
avatar
Saurabhminocha
avatar
Joined: 24 Oct 2017
Last visit: 20 Nov 2024
Posts: 36
Own Kudos:
63
 [1]
Given Kudos: 35
Location: India
Schools: Owen '22 (A$) Kelley '22 (A$) Kenan-Flagler '22 (WA) Georgia Tech '22 (II)
GMAT 1: 710 Q48 V39
GPA: 3.39
Schools: Owen '22 (A$) Kelley '22 (A$) Kenan-Flagler '22 (WA) Georgia Tech '22 (II)
GMAT 1: 710 Q48 V39
Posts: 36
Kudos: 63
 [1]
A metallic cubical box was hammered and moulded into a rectangular box 21 Jul 2019, 22:44
Kudos
Add Kudos
Bookmarks
Bookmark this Post
surface area = 2(Lw+wh+Lh)
original S.A. = 6a^2
new = 2(a*3a + 3a*a + a*a) = 14a^2

%change = (14a^2 - 6a^2)/ 6a^2 *100% = (8/6)*100 = 133.33% (D)
User avatar
Salman_Iqbal_Bappy
User avatar
Joined: 24 Aug 2017
Last visit: 12 Nov 2019
Posts: 6
Given Kudos: 11
Posts: 6
Kudos: 0
A metallic cubical box was hammered and moulded into a rectangular box 21 Jul 2019, 22:48
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Saurabhminocha
surface area = 2(Lw+wh+Lh)
original S.A. = 6a^2
new = 2(a*3a + 3a*a + a*a) = 14a^2

%change = (14a^2 - 6a^2)/ 6a^2 *100% = (8/6)*100 = 133.33% (D)
thanks a lot...I get it now.

Posted from my mobile device

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderators:
Bunuel
Math Expert
98773 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3106 posts