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A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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08 Mar 2018, 21:19
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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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08 Mar 2018, 21:21



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Mar 2018, 01:21
Bunuel wrote: A number of ties are individually packaged in unmarked boxes. What is the maximum number of boxes that must be opened if boxes are opened at random until there are three open boxes containing ties of the same color?
(1) There are five distinct colors of ties.
(2) There are 25 boxes. Question: How many boxes need to be opened to get three ties of same color?To answer the question we need 1) The number of colors available 2) How many boxes of each color 3) How many boxes in total Statement 1: There are five distinct colors of ties.As per the three points mentioned above we have no information about point 2 and 3 hence NOT SUFFICIENT Statement 2: There are 25 boxesAs per the three points mentioned above we have no information about point 1 and 2 hence NOT SUFFICIENT COmbining the two statementsWe still don't know if each color has equal number of boxes hence NOT SUFFICIENT Answer: option E
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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Mar 2018, 01:51
Bunuel wrote: A number of ties are individually packaged in unmarked boxes. What is the maximum number of boxes that must be opened if boxes are opened at random until there are three open boxes containing ties of the same color?
(1) There are five distinct colors of ties.
(2) There are 25 boxes. A) 5 distinct colors but it can be just 5 boxes only , so we can never find 3 of same color insuff B) 25 boxes but if all have same color then 3 boxes will do work and if there are 25 colors then its impossible insuff If 5 colors are there in 25 boxes So , let us say colors r R,B,G,Y,P R has 10 box B has 11 box Y has 2 box G and P has 1 box so answer will be different for each color Insuff E answer



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Jun 2018, 06:33
Hi, I found this question in Veritas Prep question bank. They chose option 1: That choice A is sufficient. The reason given is: Statement (1) gives that there are five distinct colors of ties. Some students may feel that this is insufficient if they are thinking about this in terms of probability. However, if you think about it in terms of scenarios, it should be clear that this is sufficient. If there are five different colors of ties, consider the worst case scenario. You open one of each color (for a total of five). Then you open a second of each color (for a total of ten). You then only need to open one more box in order to be guaranteed to have a third of any color. It doesn’t matter what that color is – you have two of each color already. So by opening the 11th box you are guaranteed to have three samecolored ties. Notice that even though there are other numbers of boxes that could yield three ties of the same color (you could, for example, open three in a row that are of the same color), that because the question is asking for a “worst case scenario”, this means that you can be done. Statement (1) is sufficient. Eliminate (B), (C), and (E). Do you think this is right?



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Jun 2018, 06:34
GMATinsight wrote: Bunuel wrote: A number of ties are individually packaged in unmarked boxes. What is the maximum number of boxes that must be opened if boxes are opened at random until there are three open boxes containing ties of the same color?
(1) There are five distinct colors of ties.
(2) There are 25 boxes. Question: How many boxes need to be opened to get three ties of same color?To answer the question we need 1) The number of colors available 2) How many boxes of each color 3) How many boxes in total Statement 1: There are five distinct colors of ties.As per the three points mentioned above we have no information about point 2 and 3 hence NOT SUFFICIENT Statement 2: There are 25 boxesAs per the three points mentioned above we have no information about point 1 and 2 hence NOT SUFFICIENT COmbining the two statementsWe still don't know if each color has equal number of boxes hence NOT SUFFICIENT Answer: option E Hi, I found this question in Veritas Prep question bank. They chose option 1: That choice A is sufficient. The reason given is: Statement (1) gives that there are five distinct colors of ties. Some students may feel that this is insufficient if they are thinking about this in terms of probability. However, if you think about it in terms of scenarios, it should be clear that this is sufficient. If there are five different colors of ties, consider the worst case scenario. You open one of each color (for a total of five). Then you open a second of each color (for a total of ten). You then only need to open one more box in order to be guaranteed to have a third of any color. It doesn’t matter what that color is – you have two of each color already. So by opening the 11th box you are guaranteed to have three samecolored ties. Notice that even though there are other numbers of boxes that could yield three ties of the same color (you could, for example, open three in a row that are of the same color), that because the question is asking for a “worst case scenario”, this means that you can be done. Statement (1) is sufficient. Eliminate (B), (C), and (E). Do you think this is right?



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Jun 2018, 06:58
nitishatomar wrote: Hi, I found this question in Veritas Prep question bank. They chose option 1: That choice A is sufficient. The reason given is: Statement (1) gives that there are five distinct colors of ties. Some students may feel that this is insufficient if they are thinking about this in terms of probability. However, if you think about it in terms of scenarios, it should be clear that this is sufficient. If there are five different colors of ties, consider the worst case scenario. You open one of each color (for a total of five). Then you open a second of each color (for a total of ten). You then only need to open one more box in order to be guaranteed to have a third of any color. It doesn’t matter what that color is – you have two of each color already. So by opening the 11th box you are guaranteed to have three samecolored ties. Notice that even though there are other numbers of boxes that could yield three ties of the same color (you could, for example, open three in a row that are of the same color), that because the question is asking for a “worst case scenario”, this means that you can be done. Statement (1) is sufficient. Eliminate (B), (C), and (E). Do you think this is right? This is right. We have five distinct colors and they are asking to open boxes till we have 3 boxes of same color then definitely we have atleast 15 boxes to open at least. And the maximum number of boxes we can open will never exceed 11. Hence (A) Sent from my XT1562 using GMAT Club Forum mobile app



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Jun 2018, 07:10
Akash720 wrote: nitishatomar wrote: Hi, I found this question in Veritas Prep question bank. They chose option 1: That choice A is sufficient. The reason given is: Statement (1) gives that there are five distinct colors of ties. Some students may feel that this is insufficient if they are thinking about this in terms of probability. However, if you think about it in terms of scenarios, it should be clear that this is sufficient. If there are five different colors of ties, consider the worst case scenario. You open one of each color (for a total of five). Then you open a second of each color (for a total of ten). You then only need to open one more box in order to be guaranteed to have a third of any color. It doesn’t matter what that color is – you have two of each color already. So by opening the 11th box you are guaranteed to have three samecolored ties. Notice that even though there are other numbers of boxes that could yield three ties of the same color (you could, for example, open three in a row that are of the same color), that because the question is asking for a “worst case scenario”, this means that you can be done. Statement (1) is sufficient. Eliminate (B), (C), and (E). Do you think this is right? This is right. We have five distinct colors and they are asking to open boxes till we have 3 boxes of same color then definitely we have atleast 15 boxes to open at least. And the maximum number of boxes we can open will never exceed 11. Hence (A) Ok, but the 'expert's answer on this thread has been 'E'. Also, my reasoning which goes against option A can be structured as: If we take only option A, I.E., we only know that there are 5 distinct colors and not about the number of boxes in total, then, let's say that the ties can be grouped into T1, T2, T3, T4 and T5 (on the basis of color) Now, suppose I start opening the boxes and find that I have opened 11 boxes in succession with ties from the color group  T1. This is because I CAN ASSUME that there might be infinite number of boxes to open and the ratio of the groups hasn't been provided. For e.g. it could be T1  11, T2  1 , T3 4, T45, T51 or one of the innumerable other combinations. I'm unable to understand why 11 HAS to be the maximum.



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Jun 2018, 07:11
Akash720 wrote: nitishatomar wrote: Hi, I found this question in Veritas Prep question bank. They chose option 1: That choice A is sufficient. The reason given is: Statement (1) gives that there are five distinct colors of ties. Some students may feel that this is insufficient if they are thinking about this in terms of probability. However, if you think about it in terms of scenarios, it should be clear that this is sufficient. If there are five different colors of ties, consider the worst case scenario. You open one of each color (for a total of five). Then you open a second of each color (for a total of ten). You then only need to open one more box in order to be guaranteed to have a third of any color. It doesn’t matter what that color is – you have two of each color already. So by opening the 11th box you are guaranteed to have three samecolored ties. Notice that even though there are other numbers of boxes that could yield three ties of the same color (you could, for example, open three in a row that are of the same color), that because the question is asking for a “worst case scenario”, this means that you can be done. Statement (1) is sufficient. Eliminate (B), (C), and (E). Do you think this is right? This is right. We have five distinct colors and they are asking to open boxes till we have 3 boxes of same color then definitely we have atleast 15 boxes to open at least. And the maximum number of boxes we can open will never exceed 11. Hence (A) Ok, but the 'expert's answer on this thread has been 'E'. Also, my reasoning which goes against option A can be structured as: If we take only option A, I.E., we only know that there are 5 distinct colors and not about the number of boxes in total, then, let's say that the ties can be grouped into T1, T2, T3, T4 and T5 (on the basis of color) Now, suppose I start opening the boxes and find that I have opened 11 boxes in succession with ties from the color group  T1. This is because I CAN ASSUME that there might be infinite number of boxes to open and the ratio of the groups hasn't been provided. For e.g. it could be T1  11, T2  1 , T3 4, T45, T51 or one of the innumerable other combinations. I'm unable to understand why 11 HAS to be the maximum.



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Jun 2018, 07:15
GMATinsight wrote: Bunuel wrote: A number of ties are individually packaged in unmarked boxes. What is the maximum number of boxes that must be opened if boxes are opened at random until there are three open boxes containing ties of the same color?
(1) There are five distinct colors of ties.
(2) There are 25 boxes. Question: How many boxes need to be opened to get three ties of same color?To answer the question we need 1) The number of colors available 2) How many boxes of each color 3) How many boxes in total Statement 1: There are five distinct colors of ties.As per the three points mentioned above we have no information about point 2 and 3 hence NOT SUFFICIENT Statement 2: There are 25 boxesAs per the three points mentioned above we have no information about point 1 and 2 hence NOT SUFFICIENT COmbining the two statementsWe still don't know if each color has equal number of boxes hence NOT SUFFICIENT Answer: option E Hi, I found this question in Veritas Prep question bank. They chose option 1: That choice A is sufficient. The reason given is: Statement (1) gives that there are five distinct colors of ties. Some students may feel that this is insufficient if they are thinking about this in terms of probability. However, if you think about it in terms of scenarios, it should be clear that this is sufficient. If there are five different colors of ties, consider the worst case scenario. You open one of each color (for a total of five). Then you open a second of each color (for a total of ten). You then only need to open one more box in order to be guaranteed to have a third of any color. It doesn’t matter what that color is – you have two of each color already. So by opening the 11th box you are guaranteed to have three samecolored ties. Notice that even though there are other numbers of boxes that could yield three ties of the same color (you could, for example, open three in a row that are of the same color), that because the question is asking for a “worst case scenario”, this means that you can be done. Statement (1) is sufficient. Eliminate (B), (C), and (E). Do you think this is right?



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Jun 2018, 09:31
nititron wrote: Akash720 wrote: nitishatomar wrote: Hi, I found this question in Veritas Prep question bank. They chose option 1: That choice A is sufficient. The reason given is: Statement (1) gives that there are five distinct colors of ties. Some students may feel that this is insufficient if they are thinking about this in terms of probability. However, if you think about it in terms of scenarios, it should be clear that this is sufficient. If there are five different colors of ties, consider the worst case scenario. You open one of each color (for a total of five). Then you open a second of each color (for a total of ten). You then only need to open one more box in order to be guaranteed to have a third of any color. It doesn’t matter what that color is – you have two of each color already. So by opening the 11th box you are guaranteed to have three samecolored ties. Notice that even though there are other numbers of boxes that could yield three ties of the same color (you could, for example, open three in a row that are of the same color), that because the question is asking for a “worst case scenario”, this means that you can be done. Statement (1) is sufficient. Eliminate (B), (C), and (E). Do you think this is right? This is right. We have five distinct colors and they are asking to open boxes till we have 3 boxes of same color then definitely we have atleast 15 boxes to open at least. And the maximum number of boxes we can open will never exceed 11. Hence (A) Ok, but the 'expert's answer on this thread has been 'E'. Also, my reasoning which goes against option A can be structured as: If we take only option A, I.E., we only know that there are 5 distinct colors and not about the number of boxes in total, then, let's say that the ties can be grouped into T1, T2, T3, T4 and T5 (on the basis of color) Now, suppose I start opening the boxes and find that I have opened 11 boxes in succession with ties from the color group  T1. This is because I CAN ASSUME that there might be infinite number of boxes to open and the ratio of the groups hasn't been provided. For e.g. it could be T1  11, T2  1 , T3 4, T45, T51 or one of the innumerable other combinations. I'm unable to understand why 11 HAS to be the maximum. Question is how many maximum number of boxes can be opened till we have 3 open boxes of same color tie. Therefore if you open 3 boxes of same color T1(As mentioned by you) then we need to stop there as we have 3 boxes of same color tie in open and 3 is not the maximum number. Thanks, Akash



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Re: A number of ties are individually packaged in unmarked boxes. What is [#permalink]
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09 Jun 2018, 21:23
A number of ties are individually packaged in unmarked boxes. What is the maximum number of boxes that must be opened if boxes are opened at random until there are three open boxes containing ties of the same color?
(1) There are five distinct colors of ties.
(2) There are 25 boxes.
Statement 1:
Suppose there are 5 colors R, B, G, Y, P.
The maximum number is 11 because of the following 1st 5 opens : R, B, G, Y, P or any other order with out repeating any colors, 2nd 5 opens : R, B, G, Y, P or any other order with out repeating any colors, The 11th opening must be one of the 5 colors already opened twice and hence we have three boxes of the same color. (sufficient)
Statement 2: there is no information about number of colors.(not sufficient)
Hence answer is A




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