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Bunuel
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(1) The price of the mix was $135 per pound.
Mixing 10 portions of the first variety(costing 120$), 2 portions of second variety(costing 135$),
and 6 portions of third variety(costing 160$), will yield a mix priced at 135$ - The ratio is 10:2:6(5:1:3)
Mixing 10 portions of the first variety(costing 120$), 4 portions of second variety(costing 135$),
and 6 portions of third variety(costing 160$), will yield a mix priced at 135$ - The ratio is 10:4:6(5:2:3) - Insufficient

(2) Only 3 pounds of the variety priced at $135 per pound was used.
How many pounds of variety priced at $135 was used does not give the ratio in which the three varieties were mixed Insufficient

On combining the information from both the statements, we still cannot find out a unique ratio
Mixing 10 portions of the first variety(costing 120$), 3 portions of second variety(costing 135$),
and 6 portions of third variety(costing 160$), will yield a mix priced at 135$ - The ratio is 10:3:6
Mixing 20 portions of the first variety(costing 120$), 3 portions of second variety(costing 135$),
and 12 portions of third variety(costing 160$), will yield a mix priced at 135$ - The ratio is 20:3:12 (Insufficient - Option E)
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Bunuel
A person mixed three varieties of tea priced at $120 per pound, $135 per pound and $160 per pound. In what ratio did he mix the three varieties of tea?

(1) The price of the mix was $135 per pound.
(2) Only 3 pounds of the variety priced at $135 per pound was used.

(1) New, but insufficient information
(2) New, but insufficient information

(1) and (2)
2 new information, left with 2 unrelated variables and a constant. Hence insufficient and E.
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Bunuel
A person mixed three varieties of tea priced at $120 per pound, $135 per pound and $160 per pound. In what ratio did he mix the three varieties of tea?

(1) The price of the mix was $135 per pound.
(2) Only 3 pounds of the variety priced at $135 per pound was used.

Tea A = $120 per round
Tea B = $135 per round
Tea C = $160 per round
Tea N = A + B + C
A:B:C = ?

1) Price of Tea N = $135
(120a+135b+160c)/(a+b+c)= 135
Insufficient. Multiple values possible.

2) B = 3 pounds
No relation to A or C. Insufficient.

(1+2)
(120a+405+160c) / (a+3+c) = 135
a:c = 5:3 but we do not know the relationship with B.
Insufficient.
Hence should be E.
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Bunuel
A person mixed three varieties of tea priced at $120 per pound, $135 per pound and $160 per pound. In what ratio did he mix the three varieties of tea?

(1) The price of the mix was $135 per pound.
(2) Only 3 pounds of the variety priced at $135 per pound was used.

Tea A = x pounds
Tea B = y pounds
Tea C = z pounds

We need to find x:y:z

(1) ((120*x + 135*y + 160*z) / (x+y+z) ) = 135
Insufficient

(2) z=3
Insufficient

(1) + (2)
Put z=3 in the weighted average formula above.
Insufficient

Ans. E
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Hi Bunuel,

I have one question, as per statement 1, The price of the mix was $135 per pound. should we assume the person will sell at weighted price of three mixtures. or can we also assume the person might markup the weighted price and sell?

Please clarify

Thanks
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hellosanthosh2k2
Hi Bunuel,

I have one question, as per statement 1, The price of the mix was $135 per pound. should we assume the person will sell at weighted price of three mixtures. or can we also assume the person might markup the weighted price and sell?

Please clarify

Thanks

From (1) is follows that the mix was selling at $135 per pound.
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Got it wrong.. but only cz it was from bunuel and i thought 1+2 would be sme kind of uniq although the equation (straight forward as it was) said otherwise :mad: :cry:
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