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A recent lunch meeting at a certain club was attended by members and

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Joined: 25 Apr 2018
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A recent lunch meeting at a certain club was attended by members and  [#permalink]

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New post Updated on: 06 Oct 2018, 03:51
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  15% (low)

Question Stats:

86% (01:11) correct 14% (01:13) wrong based on 50 sessions

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A recent lunch meeting at a certain club was attended by members and guests. Each member paid $4 for the lunch and each guest paid $8 for the lunch. How many of the people attending the meeting were members


(1) A total of 20 people attended the meeting.

(2) A total of $92 was paid for the lunch

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Originally posted by gmat1393 on 06 Oct 2018, 03:47.
Last edited by Bunuel on 06 Oct 2018, 03:51, edited 1 time in total.
Renamed the topic and edited the question.
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Joined: 07 Dec 2017
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Re: A recent lunch meeting at a certain club was attended by members and  [#permalink]

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New post 06 Oct 2018, 04:18
gmat1393 wrote:
A recent lunch meeting at a certain club was attended by members and guests. Each member paid $4 for the lunch and each guest paid $8 for the lunch. How many of the people attending the meeting were members


(1) A total of 20 people attended the meeting.

(2) A total of $92 was paid for the lunch


The given question translates into 4m+8g = total. To find the value for m we need to know the value for 'g' and that for 'total' or to see that there is exactly one solution.
We'll look for this information, a Logical approach.

(1) this gives m+g=20. Without information on the total we cannot solve these equations.
Insufficient.

(2) This gives 4m+8g=92 which simplifies to m+2g=23. This has many solutions, for example m = 1,g=11 and m=3,g=10.
Insufficient.

Together, we have two equations with two variables which has only one solution (m=17,g=3)
Sufficient.

(C) is our answer.
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Re: A recent lunch meeting at a certain club was attended by members and &nbs [#permalink] 06 Oct 2018, 04:18
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