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A school has a total enrollment of 90 students. There are 30 students
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19 May 2017, 01:25
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53% (01:40) correct 47% (01:52) wrong based on 94 sessions
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A school has a total enrollment of 90 students. There are 30 students taking physics, 25 taking English, and 13 taking both. What percentage of the students are taking either physics or English? (A) 30% (B) 36% (C) 47% (D) 51% (E) 58%
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Re: A school has a total enrollment of 90 students. There are 30 students
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19 May 2017, 02:26
Students taking physics = 30 (these 30 include those 13 that take both) Students taking english = 25 (these 25 also include those 13)
So those that take either physics or english or both = 30 + 25  13 = 42.
Required percentage = 42/90 * 100 = 47% approx
Hence answer is C



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Re: A school has a total enrollment of 90 students. There are 30 students
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22 May 2017, 17:47
rohan2345 wrote: A school has a total enrollment of 90 students. There are 30 students taking physics, 25 taking English, and 13 taking both. What percentage of the students are taking either physics or English?
(A) 30% (B) 36% (C) 47% (D) 51% (E) 58% Since we need to determine the number of students who are taking either physics or English, we can use the following formula: # of students who take physics or English = # who take English + # who take physics  # who take both Either = 30 + 25  13 = 42 Thus, the percentage of students who are taking either physics or English is 42/90 = 0.4667 = 47%. Answer: C
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Re: A school has a total enrollment of 90 students. There are 30 students
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25 May 2017, 04:11
rohan2345 wrote: A school has a total enrollment of 90 students. There are 30 students taking physics, 25 taking English, and 13 taking both. What percentage of the students are taking either physics or English?
(A) 30% (B) 36% (C) 47% (D) 51% (E) 58% If the questions asks for students who take EITHER physics OR English. Thus, if I pick a student who studies physics AND English, he studies both subject > so he doesn't study EITHER physics OR English. I focused on a) the people studying only physics but not English (3017 = 17) b) and on the people only studying English but not physics (2513 = 12) 17 physics students + 12 English students = 29/90 = 32,33% Happy to hear your thoughts. Thanks!



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A school has a total enrollment of 90 students. There are 30 students
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25 May 2017, 04:54
rohan2345 wrote: A school has a total enrollment of 90 students. There are 30 students taking physics, 25 taking English, and 13 taking both. What percentage of the students are taking either physics or English?
(A) 30% (B) 36% (C) 47% (D) 51% (E) 58% Total Students = 90 Students taking Both Physics and English = 13 Students taking Physics = 30 Students taking Only Physics = 30  13 = 17 Students taking English = 25 Students taking Only English = 25  13 = 12 Therefore Total Students taking Either Physics or English = 13 + 17 + 12 = 42 Percentage of the students are taking either physics or English = \(\frac{42}{90}\) x 100 = 46.666% = Approximately = 47% Answer C...



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Re: A school has a total enrollment of 90 students. There are 30 students
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25 May 2017, 05:25
sashiim20 wrote: Total Students = 90 Students taking Both Physics and English = 13 Students taking Physics = 30 Students taking Only Physics = 30  13 = 17 Students taking English = 25 Students taking Only English = 25  13 = 12
Therefore Total Students taking Either Physics or English = 13 + 17 + 12 = 42
Percentage of the students are taking either physics or English = \(\frac{42}{90}\) x 100 = 46.666% = Approximately = 47% Answer C... But if I add Students taking Only Physics (17), Students taking Only English (12) AND Students taking both (13), then I DON'T end up with students taking EITHER Physics OR English as the 13 students taking both subject have both subjects  and not Either English OR physics. Do u understand my point?



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Re: A school has a total enrollment of 90 students. There are 30 students
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25 May 2017, 09:58
guenthermat wrote: sashiim20 wrote: Total Students = 90 Students taking Both Physics and English = 13 Students taking Physics = 30 Students taking Only Physics = 30  13 = 17 Students taking English = 25 Students taking Only English = 25  13 = 12
Therefore Total Students taking Either Physics or English = 13 + 17 + 12 = 42
Percentage of the students are taking either physics or English = \(\frac{42}{90}\) x 100 = 46.666% = Approximately = 47% Answer C... But if I add Students taking Only Physics (17), Students taking Only English (12) AND Students taking both (13), then I DON'T end up with students taking EITHER Physics OR English as the 13 students taking both subject have both subjects  and not Either English OR physics. Do u understand my point? Hi In Mathematics, especially in questions of sets/probability etc, if you come across a phrase 'Either A or B' it automatically means 'Either A or B or both'. So if 5 people drink Only Pepsi, 7 people drink Only Coke, and 2 people drink both Pepsi and Coke, then it means (5+7+2) = 14 people are there who drink 'Either Pepsi or Coke'. (Both is automatically included in this). That's my understanding. Maybe Experts can confirm.



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Re: A school has a total enrollment of 90 students. There are 30 students
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25 May 2017, 14:36
amanvermagmat wrote: Hi
In Mathematics, especially in questions of sets/probability etc, if you come across a phrase 'Either A or B' it automatically means 'Either A or B or both'.
So if 5 people drink Only Pepsi, 7 people drink Only Coke, and 2 people drink both Pepsi and Coke, then it means (5+7+2) = 14 people are there who drink 'Either Pepsi or Coke'. (Both is automatically included in this).
That's my understanding. Maybe Experts can confirm.
This clarification helps a lot  thank you!



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Re: A school has a total enrollment of 90 students. There are 30 students
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13 Oct 2018, 01:17
amanvermagmat wrote: guenthermat wrote: sashiim20 wrote: Total Students = 90 Students taking Both Physics and English = 13 Students taking Physics = 30 Students taking Only Physics = 30  13 = 17 Students taking English = 25 Students taking Only English = 25  13 = 12
Therefore Total Students taking Either Physics or English = 13 + 17 + 12 = 42
Percentage of the students are taking either physics or English = \(\frac{42}{90}\) x 100 = 46.666% = Approximately = 47% Answer C... But if I add Students taking Only Physics (17), Students taking Only English (12) AND Students taking both (13), then I DON'T end up with students taking EITHER Physics OR English as the 13 students taking both subject have both subjects  and not Either English OR physics. Do u understand my point? Hi In Mathematics, especially in questions of sets/probability etc, if you come across a phrase 'Either A or B' it automatically means 'Either A or B or both'. So if 5 people drink Only Pepsi, 7 people drink Only Coke, and 2 people drink both Pepsi and Coke, then it means (5+7+2) = 14 people are there who drink 'Either Pepsi or Coke'. (Both is automatically included in this). That's my understanding. Maybe Experts can confirm. Thank you for pointing this out, I also solved for students that attend only one of the respective classes. After reading the respective explanation it makes sense to me that 47% is the right answer though.
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Re: A school has a total enrollment of 90 students. There are 30 students
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