A useful formula for 3 overlapping groups:
T = A + B + C - (AB + AC + BC) - 2(ABC)
The big idea with overlapping group problems is to SUBTRACT THE OVERLAPS.
When we add together everyone in A, everyone in B, and everyone in C:
Those in exactly 2 of the groups (AB+AC+BC) are counted twice, so they need to be subtracted from the total ONCE.
Those in all 3 groups (ABC) are counted 3 times, so they need to be subtracted from the total TWICE.
By subtracting the overlaps, we ensure that no one is overcounted.
In the problem above:
Let T = 120.
Obese = (1/3)(120) = 40.
White fur = (3/4)(120) = 90.
Elongated mandible = (1/2)(120) = 60.
Exactly 2 of the groups = OW + OE + WE.
All 3 groups = OWE.
Plugging these values into the formula, we get:
120 = 40 + 90 + 60 - (OW + OE + WE) - 2(OWE)
-70 = - (OW + OE + WE) - 2(OWE)
(OW + OE + WE) + 2(OWE) = 70.
Since the least possible value for (OW + OE + WE) is 0, the greatest possible value for OWE is 35.
Statement 1:
Of the 120 rats in the experiment, 40 had white fur and an elongated mandible.
Case 1: Of these 40 rats, 5 have all 3 traits (OWE=5), implying that 35 have only white fur and an elongated mandible (WE=35).
Case 2: Of these 40 rats, 10 have all 3 traits (OWE=10), implying that 30 have only white fur and an elongated mandible (WE=30).
Since OWE can be different values, INSUFFICIENT.
Statement 2:
Of the 120 rats in the experiment, 40 had exactly two of the traits.
Substituting (OW + OE + WE) = 40 into (OW + OE + WE) + 2(OWE) = 70, we get:
40 + 2(OWE) = 70.
2(OWE) = 30
OWE = 15.
SUFFICIENT.
The correct answer is B.