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e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 2942
A set of 51 different integers has a median of 30 and a range of 60.  [#permalink]

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Difficulty:   55% (hard)

Question Stats: 58% (02:09) correct 42% (01:55) wrong based on 152 sessions

### HideShow timer Statistics Solve any Median and Range question in a minute- Exercise Question #3

A set of 51 different integers has a median of 30 and a range of 60. What is the value of the least possible integer in this set?

Options

a) -10
b) -6
c) -5
d) 5
e) 10

To solve question 4: Question 4

To read the article: Solve any Median and Range question in a minute

_________________

Originally posted by EgmatQuantExpert on 11 Jul 2018, 08:02.
Last edited by EgmatQuantExpert on 13 Aug 2018, 00:54, edited 2 times in total.
MBA Section Director V
Affiliations: GMATClub
Joined: 22 May 2017
Posts: 2555
GPA: 4
WE: Engineering (Computer Software)
Re: A set of 51 different integers has a median of 30 and a range of 60.  [#permalink]

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6
To find the least possible integer in the set of 51 different integers

The median of the set is 30

=> If the numbers are arranged in ascending order, the 26th integer is 30

We know that all the integers to the right of the median are $$\geq$$ median.

Since the set consists of all different integers, the integers to the right of the median are $$>$$ median

Lets make the integers to the right of the median greater than median by least possible value i.e 1

=> value at 27th place will be 31(27+4)
=> value at 28th place will be 32(28+4)
...... => value at 51st place will be 55(51+4)

Given range = 60

=> max_possible_integer - lowest_possible_integer = 60

=> 55 - lowest_possible_integer = 60

=> lowest_possible_integer = 55 - 60 = -5

Hence option C
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VP  D
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Re: A set of 51 different integers has a median of 30 and a range of 60.  [#permalink]

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1
1
EgmatQuantExpert wrote:
Solve any Median and Range question in a minute- Exercise Question #3

A set of 51 different integers has a median of 30 and a range of 60. What is the value of the least possible integer in this set?

Options

a) -10
b) -6
c) -5
d) 5
e) 10

To read the article: Solve any Median and Range question in a minute

Given set, Say
X={$$x_{min}$$,.....(25 members including $$x_{min}$$)......,30,.......(25 members including $$x_{max}$$).....,$$x_{max}$$}
---------------------------------------------------(26th term Median) --------------------------------- $$(51^{th} term)$$
Given, $$x_{max} - x_{min}=60$$ ----(1)
Since number of members after median is 25, hence x(max)=30+25=55 (Note:- all terms of the set are different as given)
So, substituting in (1), we have
$$55-x_{min}=60$$
Or, $$x_{min}=-5$$

Therefore, the value of the least possible integer in this set is -5.

Ans. (C)
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Regards,

PKN

Rise above the storm, you will find the sunshine

Originally posted by PKN on 11 Jul 2018, 13:21.
Last edited by PKN on 11 Jul 2018, 21:59, edited 1 time in total.
MBA Section Director V
Affiliations: GMATClub
Joined: 22 May 2017
Posts: 2555
GPA: 4
WE: Engineering (Computer Software)
Re: A set of 51 different integers has a median of 30 and a range of 60.  [#permalink]

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PKN wrote:
Therefore, the value of the least possible integer in this set is -5.

Ans. (B)

PKN

-5 corresponds to option C and not option B
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Intern  B
Joined: 24 May 2014
Posts: 1
Re: A set of 51 different integers has a median of 30 and a range of 60.  [#permalink]

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Median is 30...thus there are 25 digits above 30...the smallest number 25 digits above 30 is 55.....the range is 60....therefore the smallest number possible has to be -5...option c for me
Manager  G
Joined: 19 Nov 2017
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Schools: ISB
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Re: A set of 51 different integers has a median of 30 and a range of 60.  [#permalink]

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median is 30 which is the 26th number in the series.
In order to minimize the lowest number, we need to minimize the maximum number.
Because,
(X)(smallest highest number) - (Y)(least negative number) = 60 (to minimize Y)

the smallest highest number possible for this series is 55. Because $$30+25 = 55$$. 25 different integers ahead of the median.

Therefore,

$$55 - x = 60$$
$$x=-5$$
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Vaibhav

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~GMAC
e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 2942
Re: A set of 51 different integers has a median of 30 and a range of 60.  [#permalink]

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1
1

Solution

Given:
• 51 different integers have a median 30 and range 60.

To find:
• The value of least possible integer.

Approach and Working:
We will get the value of least possible integer if then the highest element of the set is equal to the median.
However, all the elements of the set are different.
So, highest element must be as small as possible.
Now, we know, median will be 51+1/2=1= 26 element.
• Hence, minimum value of the highest element= 30+25= 55
• Thus, highest element – lowest element= 60
o 55- Lowest element= 60
o Lowest element= -5

Hence, the correct answer is option C.

_________________ Re: A set of 51 different integers has a median of 30 and a range of 60.   [#permalink] 15 Jul 2018, 07:05
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