A shopper spends $25 to purchase floppy disks at 50¢ each. The next

Question

A shopper spends $25 to purchase floppy disks at 50¢ each. The next day, the disks go on sale for 30¢ each and the shopper spends $45 to purchase more disks. What was the average price per disk purchased?

(A) 25¢

(B) 30¢

(C) 35¢

(D) 40¢

(E) 45¢

(A) 25¢

(B) 30¢

(C) 35¢

(D) 40¢

(E) 45¢

amanvermagmat · Answer

On the first day, number of disks purchased = $25/(50 cents) = 2500/50 = 50

On the next day, number of disks purchased = $45/(30 cents) = 4500/30 = 150

So the average price per disk = (Total price paid)/(total no of disks) 
= (2500+4500)/(50+150) = 7000/200 = 35 cents

Hence answer is  C

pushpitkc · Answer

On the first day, the shopper spends 25$ to purchase 50 disks 
Number of disks = 25*100¢/50¢(cost/disk)
Hence he buys 50 disks.
Similarly, on the second day, at 45$, he will purchase 150 disks at 30¢ each.
Number of disks = 45*100¢/30¢(cost/disk)
Here, he buys 150 disks.

Average price per disk = 70$ or 7000¢/Number of disks(200) = 35¢  (Option C)

Mo2men · Answer

First day he bought 25/0.5= 50 disk Second day he bought 45/0.3= 150 disk average price per disk = (70/ 200) = 7/20 for easy calculation 7/20 = 7/10 * 1/2 = 0.7 * 0.5 =0.35 Answer: C It seems this is an old question since floppy dist era :-D

sashiim20 · Answer

A shopper spends $25 to purchase floppy disks at 50¢ each. The next day, the disks go on sale for 30¢ each and the shopper spends $45 to purchase more disks. What was the average price per disk purchased?

Shopper spend $25 for floppy disks. Let the number of disks be X.
[Convert to same unit. (100 cents = 1 dollar)]
$25 = 2500 cents.
1 disk for 50 cents = $\frac{1}{50}$
Number of disks for 2500 cents = $\frac{X}{2500}$
Equating both equations;
$\frac{1}{50}$ = $\frac{X}{2500}$
X = $\frac{2500}{50}$ = 50 Disks

Disk go on sale for 30 cents.
Shopper spent $45 to purchase more disks. Let the extra number of disks be Y.
$45 = 4500 cents.
1 disk for 30 cents = $\frac{1}{30}$
Number of disks for 4500 cents = $\frac{Y}{4500}$
Equating both equations;
$\frac{1}{30}$ = $\frac{Y}{4500}$
Y = $\frac{4500}{30}$ = 150 Disks

Therefore Total number of Disks purchased = X + Y = 50 + 150 = 200 Disks
Total price payed for disks = 2500 + 4500 = 7000 cents.

Average price per disk = Total Price / Total number = $\frac{7000}{200}$ = 35 cents.
Answer C...

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mohshu · Answer

On Day 1, the shopper spends 25$ to purchase 50 disks 
On Day 2 , he will purchase 150 disks at 30¢ each.

Average price per disk = 7000¢/200 = 35¢
Ans C

JeffTargetTestPrep · Answer

Since the shopper spent $25, or 2500¢, on the 50¢ disks, he purchased 2500/50 = 50 disks. On the second day, the shopper spent $45, or 4500¢, on the 30¢ disks, and thus he purchased 4500/30 = 150 disks.
 
Thus, the average price per disk is (2500 + 4500)/(50 + 150) = 7000/200 = 35 cents.
 
Answer: C

BrushMyQuant · Answer

Theory

➡ Average = Sum of all the Values / Total Number of Values 
 ➡ Sum of All the values = Average * Total Number of Values

A shopper spends $25 to purchase floppy disks at 50¢ ($0.5) each

Total Price Paid on First Day = $25
Total Disks Purchased on First Day = Total Price Paid / Price of each disk =  \frac{25}{0.5}  =  \frac{250}{5}  = 50

The next day, the disks go on sale for 30¢($0.3) each and the shopper spends $45 to purchase more disks

Total Price Paid on Second Day = $45
Total Disks Purchased on Second Day = Total Price Paid / Price of each disk =  \frac{45}{0.3}  =  \frac{450}{3}  = 150

The average price per disk purchased

Average = Sum of all the Values / Total Number of Values = Total Price Paid in both the days / Total number of disks purchased =  \frac{25 + 45}{ 50 + 150}  =  \frac{70}{200}  = $0.35 = 35¢

So,  Answer will be C .
Hope it helps!

Watch the following video to Learn the Basics of Statistics

https://www.youtube.com/watch?v=Cvy_HHw4KIs

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