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HoneyLemon
Updated on: 02 Oct 2023, 11:55
Originally posted by HoneyLemon on 06 Feb 2021, 00:06.
Last edited by BottomJee on 02 Oct 2023, 11:55, edited 8 times in total.
Last edited by BottomJee on 02 Oct 2023, 11:55, edited 8 times in total.
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x-coordinate: -5
y-coordinate : -3
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
46% (02:27) correct
54%
(02:46)
wrong
based on 383
sessions
History
Date
Time
Result
Not Attempted Yet
A square with area 25 has one vertex on point (-2, 1) in the coordinate plane. From the table below, select the x- and y-coordinates that could correspond to another vertex of this same square.
| x-coordinate | y-coordinate | --------------- |
| -9 | ||
| -7 | ||
| -5 | ||
| -3 | ||
| -1 |
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Official Answer
x-coordinate: -5
y-coordinate : -3
02 Mar 2022, 03:57
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Official Explanation
(-5, -3) is the only point that will work. From the answer choices you should see that the only available options are in Quadrant III, so that should help you to limit your search. You must go down on the y-coordinate and the only way to go to the right on the x is to go to -1. But since the sides of the square are equal to 5, you're looking for a point 5 spaces away from (-2, 1). That means that x = -7 is in play, but then you'd have three options for y: staying at 1 (not an option), moving up to 6 (not an option) or going down to -4 (also not an option). So your only choice here is to recognize another way to move exactly 5 spaces - keeping all values integers - in the coordinate plane: the 3-4-5 triangle. If you were to move 3 spaces left (to x = -5) and 4 spaces down (to -3), that is a point exactly 5 spaces away from the initial vertex, allowing point (-5, -3) to be another vertex.
Answer: (-5, -3)
(-5, -3) is the only point that will work. From the answer choices you should see that the only available options are in Quadrant III, so that should help you to limit your search. You must go down on the y-coordinate and the only way to go to the right on the x is to go to -1. But since the sides of the square are equal to 5, you're looking for a point 5 spaces away from (-2, 1). That means that x = -7 is in play, but then you'd have three options for y: staying at 1 (not an option), moving up to 6 (not an option) or going down to -4 (also not an option). So your only choice here is to recognize another way to move exactly 5 spaces - keeping all values integers - in the coordinate plane: the 3-4-5 triangle. If you were to move 3 spaces left (to x = -5) and 4 spaces down (to -3), that is a point exactly 5 spaces away from the initial vertex, allowing point (-5, -3) to be another vertex.
Answer: (-5, -3)
27 Dec 2023, 10:13
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I really think the answer is wrong. I tried plotting this graph on desmos and its not possible for it be a square with these coordinates
