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705-805 Level|   Geometry|                     
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Chitra657
moonwalking
A triangle has side lengths of a, b, and c centimeters. Does each angle in the triangle measure less than 90 degrees?

(1) The 3 semicircles whose diameters are the sides of the triangle have areas that are equal to 3 \(cm^2\), 4 \(cm^2\), and 6 \(cm^2\), respectively.

(2) c < a + b < c + 2

I didnt know how to go about solving it, so I made a quick guess.
I reasoned that since stat 1 gives us areas, we can find the length of the diameter, and thus the lengths of all three sides. So now the triangle has fixed length sides. I assumed that if we make one angle obtuse, the length of the opposite side will change. Thus, we cant really change the shape of the triangle. It is sort of locked. Thus, there's a good chance that the angles will be locked in too. SO A is suff

For stat 2 I tested values, c=2 then a=2 and b=1 or c=3 then a=2 and b=2
Thus, the lengths of the sides cannot be locked into one particular length, SO, there's a good chance that B is insuff.

Now, does this all make sense, or I just got really lucky?

VeritasKarishma Bunuel MathRevolution egmat


Chitra657 - I am good with your statement 1 analysis. We know that we can find the exact length of all 3 sides. There is a unique triangle associated with 3 side lengths. The angles are all defined. Hence, knowing the side lengths, we know that the data is enough to answer the question. Whether our answer is "yes" or "no" is irrelevant. The point is that we can answer with a definite yes or no. Hence statement 1 is sufficient.

But for statement 2, though the sides are not uniquely defined, it is still possible that the given constraint leads to a unique answer.
Since acute angles have a^2 + b^2 > c^2, if the sides are constrained in a way that a^2 + b^2 > c^2, you will know that they represent an acute triangle. You don't need to know each side uniquely.
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moonwalking
A triangle has side lengths of a, b, and c centimeters. Does each angle in the triangle measure less than 90 degrees?

(1) The 3 semicircles whose diameters are the sides of the triangle have areas that are equal to 3 \(cm^2\), 4 \(cm^2\), and 6 \(cm^2\), respectively.

(2) c < a + b < c + 2

Statement 1: It effectively gives us measures of 3 sides. We can build a triangle with the sides and find out if any angle is greater than 90. So sufficient.
Statement 2: c < a + b stands for all triangles. a + b < c + 2 just says that sum of 2 sides is less than 3rd side +2. Not helpful as well. So not sufficient.

Therefore, Ans- A
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A triangle has side lengths of a, b, and c centimeters. Does each angle in the triangle measure less than 90 degrees?

(1) The 3 semicircles whose diameters are the sides of the triangle have areas that are equal to 3 cm^2, 4 cm^2, and 6
[ltr]cm^2, respectively.

\(S(semicircle) = 1/2[color=#202122]π{r^2}
\)

\(a^2 = 6/[color=#0f0f0f]π
\)
\(b^2 = 8/π\)
\(c^2 = 12/π\)
[/color][/color][/ltr]

[color=#202122]\(c^2 < a^2 + b^2\) —> acute triangle [/color]
Sufficient

(2) \(c < a + b < c + 2\)
\(c^2 < (a + b)^2 < (c + 2)^2\)
\(c^2 < a^2 + 2ab + b^2 < c^2 +4c + 4\)
Insufficient

Answer: A
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A triangle has side lengths of a, b, and c centimeters. Does each angle in the triangle measure less than 90 degrees?

A triangle is acute if the square of the longest side is less than the sum of the squares of two smaller sides.

(1) The 3 semicircles whose diameters are the sides of the triangle have areas that are equal to 3 \(cm^2\), 4 \(cm^2\), and 6 \(cm^2\), respectively.

Area of the semicircle with a cm as diameter \(= \pi a^2/8 = 3\)
Area of the semicircle with b cm as diameter \(= \pi b^2/8 = 4\)
Area of the semicircle with c cm as diameter \(= \pi c^2/8 = 6\)

Square of the longest side =\( c^2 = 48/\pi < a^2 + b^2 = 24/pi + 32/pi = 56\pi\)
The triangle is acute, i.e.each angle in the triangle measure less than 90 degrees
SUFFICIENT

(2) c < a + b < c + 2
a+b > c is always true
a+b<c+2
Case 1: a=2; b=3; c= 4; a^2 + b^2 = 2^2 + 3^2 = 13 < c^2 = 16; Triangle is NOT acute
Case 2: a=1; b=2; c=2; a^2 + b^2 = 1^2 + 2^2 = 5 > c^2 = 4; Triangle is acute.
NOT SUFFICIENT

IMO A
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