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Tough and Tricky questions: Work/Rate.

Adam and Brianna plan to install a new tile floor in a classroom. Adam works at a constant rate of 50 tiles per hour, and Brianna works at a constant rate of 55 tiles per hour. If the new floor consists of exactly 1400 tiles, how long will it take Adam and Brianna working together to complete the classroom floor?

A. 26 hrs. 44 mins. B. 26 hrs. 40 mins. C. 13 hrs. 20 mins. D. 13 hrs. 18 mins. E. 12 hrs. 45 mins.

Re: Adam and Brianna plan to install a new tile floor in a classroom. Adam [#permalink]

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06 Oct 2014, 03:27

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Bunuel wrote:

Tough and Tricky questions: Work/Rate.

Adam and Brianna plan to install a new tile floor in a classroom. Adam works at a constant rate of 50 tiles per hour, and Brianna works at a constant rate of 55 tiles per hour. If the new floor consists of exactly 1400 tiles, how long will it take Adam and Brianna working together to complete the classroom floor?

A. 26 hrs. 44 mins. B. 26 hrs. 40 mins. C. 13 hrs. 20 mins. D. 13 hrs. 18 mins. E. 12 hrs. 45 mins.

We need to find the individual time for Adam and Brianna to put the 1400 tiles.

Adam: \(1400*\frac{1}{50}\)= 28 Hours.

Brianna : \(1400*\frac{1}{55}\)=Mathematically it comes to 25.45. When we convert the decimal to time we get. 25 hours 27 Minutes.

Re: Adam and Brianna plan to install a new tile floor in a classroom. Adam [#permalink]

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06 Oct 2014, 04:55

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Gnpth wrote:

Bunuel wrote:

Tough and Tricky questions: Work/Rate.

Adam and Brianna plan to install a new tile floor in a classroom. Adam works at a constant rate of 50 tiles per hour, and Brianna works at a constant rate of 55 tiles per hour. If the new floor consists of exactly 1400 tiles, how long will it take Adam and Brianna working together to complete the classroom floor?

A. 26 hrs. 44 mins. B. 26 hrs. 40 mins. C. 13 hrs. 20 mins. D. 13 hrs. 18 mins. E. 12 hrs. 45 mins.

We need to find the individual time for Adam and Brianna to put the 1400 tiles.

Adam: \(1400*\frac{1}{50}\)= 28 Hours.

Brianna : \(1400*\frac{1}{55}\)=Mathematically it comes to 25.45. When we convert the decimal to time we get. 25 hours 27 Minutes.

=13. 33 Converting it into hours ==> 13 hours 19.8 Minutes => 13 hours 20 Minutes. Answer is C.

Bunuel: I hope you have some different approach to this problem. Please post your explanation.

actually we don't need to all these complex calculations

w=1400 units when adam and briana work together, they will lay 55+50=105 tiles in an hour.

therefore total time taken to lay 1400 tiles on the floor = 1400/105 = 40/3 hour =13(1/3) hour or 13 hour and (1/3)*60 minutes =13 hour and 20 minutes.

Re: Adam and Brianna plan to install a new tile floor in a classroom. Adam [#permalink]

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02 Oct 2016, 05:35

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Adam installs at a constant rate of 50 tiles per hour Brianna installs at a constant rate of 55 tiles per hour If both persons work together they can install 105 tiles in a hour Total number of installs to be done = 1400 time required for installation of 1400 tiles = \(\frac{1400}{105}\) = 13.3333 hrs = 13 hrs 20 mins Correct answer - C

Re: Adam and Brianna plan to install a new tile floor in a classroom. Adam [#permalink]

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27 May 2017, 04:48

Bunuel wrote:

Tough and Tricky questions: Work/Rate.

Adam and Brianna plan to install a new tile floor in a classroom. Adam works at a constant rate of 50 tiles per hour, and Brianna works at a constant rate of 55 tiles per hour. If the new floor consists of exactly 1400 tiles, how long will it take Adam and Brianna working together to complete the classroom floor?

A. 26 hrs. 44 mins. B. 26 hrs. 40 mins. C. 13 hrs. 20 mins. D. 13 hrs. 18 mins. E. 12 hrs. 45 mins.

W=R X T or, R=W/T

Adam's Rate, A=50 tiles per hour Brianna's Rate, B=55 tiles per hour

Combine rate (A+B) =50+55 =105 tiles per hour (We can ONLY ADD RATE of work in Work Rate problems)

105 tiles per hour 1 tile = 1/105 hour 1400 Tiles =1400/105 hour = 200/15 hours =40/3 hours =(39+1)/3 =39/3 + 1/3 hours =13 hours + 1/3 x 60 min =13 hours and 20 minutes Hence, Answer is:

Re: Adam and Brianna plan to install a new tile floor in a classroom. Adam [#permalink]

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27 May 2017, 08:04

Bunuel wrote:

Tough and Tricky questions: Work/Rate.

Adam and Brianna plan to install a new tile floor in a classroom. Adam works at a constant rate of 50 tiles per hour, and Brianna works at a constant rate of 55 tiles per hour. If the new floor consists of exactly 1400 tiles, how long will it take Adam and Brianna working together to complete the classroom floor?

A. 26 hrs. 44 mins. B. 26 hrs. 40 mins. C. 13 hrs. 20 mins. D. 13 hrs. 18 mins. E. 12 hrs. 45 mins.

\(\frac{1400}{(55+50)} = 13 \frac{1}{3}\) \(Hrs\)

Thus, the correct answer must be (C) _________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

Adam and Brianna plan to install a new tile floor in a classroom. Adam works at a constant rate of 50 tiles per hour, and Brianna works at a constant rate of 55 tiles per hour. If the new floor consists of exactly 1400 tiles, how long will it take Adam and Brianna working together to complete the classroom floor?

A. 26 hrs. 44 mins. B. 26 hrs. 40 mins. C. 13 hrs. 20 mins. D. 13 hrs. 18 mins. E. 12 hrs. 45 mins.

Since Adam works at a constant rate of 50 tiles per hour and Brianna works at a constant rate of 55 tiles per hour, their combined rate is 105 tiles per hour.

If we let t = the time they work together, we have:

Re: Adam and Brianna plan to install a new tile floor in a classroom. Adam [#permalink]

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18 Sep 2017, 11:23

I am privileged to be among Super computers who solve this question within 1mins 20seconds. Guess I am too dumb to take close to 1min 45seconds to get through this!
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