An admission office director has 7 times available for interviews at a

Question

An admission office director has 7 times available for interviews at afternoon. There are 12 students disputing the vacancies. In how many different ways can the director set up his/her program (answering the candidates individually)?

(A) 12!/(5!7!)
(B) 12!/7!
(C) 12!/5!
(D) 12!
(E) 12^7

(A) 12!/(5!7!) 
(B) 12!/7! 
(C) 12!/5! 
(D) 12! 
(E) 12^7

Archit3110 · Answer

IMO A ; 12c7 ways possible to arrange interviews
12!/(5!7!)

IanStewart · Answer

I don't think the wording is sufficiently clear, but I'd assume the director has 12 choices for the first open time in her schedule, 11 choices for the next, and so on. Since she can only interview seven people in total, the number of possible schedules will be (12)(11)(10)(9)(8)(7)(6), which is equal to 12!/5!.

SPatel1992 · Answer

I am confused again!

Why is it not 12!/(5!7!)?

Shishou · Answer

The answer is C. 12!/5!. Why? The director has 12 options for time slot 1, 11 for time slot 2,10 for time slot 3,and so on making it 12*11*10*8*7*6*5 which is equivalent to 12P5 or 12!/(12-7)! Hence answer is C

pa1deep91 · Answer

Since, this will involve arrangements as well. Thus, possible ways are 12P7 =>  12!/5! (C)

Shashank123abc · Answer

What is the correct answer for this. Is it 12!/5! or 12!/(5!7!) . Since arrangement is not necessary here, we can easily mark 12c7 in this case

ScottTargetTestPrep · Answer

The number of ways to set up the program is 12P7 = 12!/(12 - 7)! = 12!/5!.

Answer: C

Umber · Answer

Arrangement is necessary here. Hence, ways of choosing 7 in 12 is 12C7. All these 7 will now be arrange in 7! the answer will be 12C7*7! = 12!/5! hence option C.

An admission office director has 7 times available for interviews at a

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An admission office director has 7 times available for interviews at a

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