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# An outlet sold 200 chairs and 120 tables. Each chair was sold at a los

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Joined: 02 Sep 2009
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An outlet sold 200 chairs and 120 tables. Each chair was sold at a los  [#permalink]

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25 Feb 2020, 00:54
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Difficulty:

35% (medium)

Question Stats:

69% (01:18) correct 31% (02:07) wrong based on 27 sessions

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An outlet sold 200 chairs and 120 tables. Each chair was sold at a loss of $20. What is the average profit on the table? (1) The total revenue is$4000
(2) The total profit is $2500 Project DS Butler Data Sufficiency (DS3) For DS butler Questions Click Here _________________ Math Expert Joined: 02 Aug 2009 Posts: 8320 Re: An outlet sold 200 chairs and 120 tables. Each chair was sold at a los [#permalink] ### Show Tags 25 Feb 2020, 22:41 1 Bunuel wrote: An outlet sold 200 chairs and 120 tables. Each chair was sold at a loss of$20. What is the average profit on the table?

(1) The total revenue is $4000 (2) The total profit is$2500

Let the profit be a and b, so we are looking for b..
Total profit = 200a+120b=200*(-20)+120b=120b-4000

(1) The total revenue is $4000 If the selling prices are c and t respectively, 200c+120t=4000 There is nothing much we can do with this (2) The total profit is$2500
So $$120b-4000=2500....120b=6500...b=\frac{6500}{12}$$
Suff

B
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An outlet sold 200 chairs and 120 tables. Each chair was sold at a los  [#permalink]

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25 Feb 2020, 22:55
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Bunuel wrote:
An outlet sold 200 chairs and 120 tables. Each chair was sold at a loss of $20. What is the average profit on the table? (1) The total revenue is$4000
(2) The total profit is $2500 Project DS Butler Data Sufficiency (DS3) For DS butler Questions Click Here Question: Average Profit on Table = ? but the loss on chairs = 200*20 = 4000 Statement 1: The total revenue is$4000

200c + 120t = 4000

Cost of table is unknown and also the revenue through chairs or table is unknown hence

NOT SUFFICIENT

Statement 2: The total profit is $2500 Total Loss of on chairs = 4000 i.e. Profit on Tables = 2500+4000 = 6500 Avearge Profit per table = $$\frac{Total Profit on tables }{ Total Number of tables} = 6500/120 = 54.16$$ SUFFICIENT Answer: Option B _________________ Prosper!!! GMATinsight .............(Bhoopendra Singh and Dr.Sushma Jha) e-mail: info@GMATinsight.com l Call : +91-9999687183 / 9891333772 Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi Click Here for Uneditable GOOGLE reviews Click here for Our VERBAL & QUANT private tutoring package details My Recent Posts Q-1-Integer-Divisibility l Q-2-Inequality DS l Q-3-Standard Deviation l Q-4-Functions ACCESS FREE GMAT TESTS HERE:22 FREE (FULL LENGTH) GMAT CATs LINK COLLECTION GMATWhiz Representative Joined: 07 May 2019 Posts: 501 Location: India Re: An outlet sold 200 chairs and 120 tables. Each chair was sold at a los [#permalink] ### Show Tags 25 Feb 2020, 23:55 1 Bunuel wrote: An outlet sold 200 chairs and 120 tables. Each chair was sold at a loss of$20. What is the average profit on the table?

(1) The total revenue is $4000 (2) The total profit is$2500

Solution

Step 1: Analyse Question Stem

• Let the average profit on selling a table be $x. • Also, let the cost price of a chair and a table be $$CP_c$$and $$CP_t$$ (in dollars), respectively. Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE Statement 1: The total revenue is$4000
• $$(CP_c – 20)*200 + (CP_t + x)*120 = 4000$$
• Since we don’t know $$CP_c$$and $$CP_t$$, we cannot find the value of x.
Hence, statement 1 is NOT sufficient and we can eliminate answer options A and D.

Statement 2: The total profit is $2500 • Total profit =$2500
o Profit made on sale of tables - Loss made on sale of chairs = 2500
o $$120*x – 20*200 = 2500 ⇒ x = \frac{6500}{120}$$
Hence, statement 2 is sufficient.
Thus, the correct answer is Option B.
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Re: An outlet sold 200 chairs and 120 tables. Each chair was sold at a los   [#permalink] 25 Feb 2020, 23:55
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