EgmatQuantExpert wrote:
An unfortunate thief was caught while trying to decode the 3-digit numerical code of a lock. The Police caught him while he was making the second-last possible unique attempt. How many attempts did the thief make in total?
A. 5
B. 26
C. 719
D. 999
E. 1000
We are talking about the 3-digit numerical code. There are 10^3 or 1000 possibilities.
Since the thief is making his second-last possible unique attempt, he would be making
his 1000-1 = 999 attempt.
Therefore, the thief will be making his
999th attempt(Option D)
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