Last visit was: 23 Apr 2026, 00:39 It is currently 23 Apr 2026, 00:39
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
GMATPASSION
Joined: 05 Mar 2011
Last visit: 02 Nov 2015
Posts: 100
Own Kudos:
966
 [52]
Given Kudos: 42
Status:Retaking next month
Affiliations: None
Location: India
Concentration: Marketing, Entrepreneurship
GMAT 1: 570 Q42 V27
GPA: 3.01
WE:Sales (Manufacturing)
GMAT 1: 570 Q42 V27
Posts: 100
Kudos: 966
 [52]
5
Kudos
Add Kudos
46
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,763
Own Kudos:
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,763
Kudos: 810,711
 [28]
12
Kudos
Add Kudos
16
Bookmarks
Bookmark this Post
User avatar
GyanOne
Joined: 24 Jul 2011
Last visit: 22 Apr 2026
Posts: 3,237
Own Kudos:
1,719
 [17]
Given Kudos: 33
Status: World Rank #4 MBA Admissions Consultant
Expert
Expert reply
Posts: 3,237
Kudos: 1,719
 [17]
9
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
General Discussion
avatar
shirisha091
Joined: 02 Aug 2012
Last visit: 07 Aug 2012
Posts: 3
Given Kudos: 15
Posts: 3
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Why is the ratio 6:4:3 for AB:BC:AC? Not seeing where the 6 came from.
User avatar
EvaJager
Joined: 22 Mar 2011
Last visit: 31 Aug 2016
Posts: 513
Own Kudos:
2,370
 [3]
Given Kudos: 43
WE:Science (Education)
Posts: 513
Kudos: 2,370
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
shirisha091
Why is the ratio 6:4:3 for AB:BC:AC? Not seeing where the 6 came from.

Divide through the given equality 2AB = 3BC = 4AC by 12 and get \(\frac{AB}{6}=\frac{BC}{4}=\frac{AC}{3}\), which can also be written as AB:BC:AC = 6:4:3.
User avatar
greatps24
Joined: 22 Nov 2010
Last visit: 23 Jan 2017
Posts: 199
Own Kudos:
Given Kudos: 75
Location: India
GMAT 1: 670 Q49 V33
WE:Consulting (Telecommunications)
GMAT 1: 670 Q49 V33
Posts: 199
Kudos: 508
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(2) AC^2 + AB^2 > BC^2 --> this condition will hold for equilateral triangle (all angles are 60 degrees) as well as for a right triangle with right angle at B or C (so in this case one angle will be 90 degrees, for example consider a right triangle: AC=5, AB=4 and BC=3). Not sufficient.

Bunuel,

Can you please explain the above mentioned statement. I am not able to understand
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,763
Own Kudos:
810,711
 [3]
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,763
Kudos: 810,711
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
greatps24
(2) AC^2 + AB^2 > BC^2 --> this condition will hold for equilateral triangle (all angles are 60 degrees) as well as for a right triangle with right angle at B or C (so in this case one angle will be 90 degrees, for example consider a right triangle: AC=5, AB=4 and BC=3). Not sufficient.

Bunuel,

Can you please explain the above mentioned statement. I am not able to understand

If AC=AB=BC=1 (satisfies AC^2 + AB^2 > BC^2) --> ABC is an equilateral triangle (all angles are 60 degrees) --> all angles are less than 90 degrees.
If AC=5, AB=4 and BC=3 (satisfies AC^2 + AB^2 > BC^2) --> ABC is a right triangle --> NOT all angles are less than 90 degrees.

Hope it's clear.
User avatar
WholeLottaLove
Joined: 13 May 2013
Last visit: 13 Jan 2014
Posts: 301
Own Kudos:
Given Kudos: 134
Posts: 301
Kudos: 640
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Are all angles of triangle ABC smaller than 90 degrees?

(1) 2AB = 3BC = 4AC
(2) AC^2 + AB^2 > BC^2

A triangle where a^2 + b^2 = c^2 is a right triangle, but is there any way of determining if measures greater than or less than that (say, if a^2 + b^2 was greater than c^2) lead to a triangle having measures greater than or less than 90?

I see how 1 is sufficient. ABC will always have that exact ratio of side lengths. The triangle could be 2x3x4 or 200x300x400 but the angle measurements will always be the same.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,763
Own Kudos:
810,711
 [2]
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,763
Kudos: 810,711
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
WholeLottaLove
Are all angles of triangle ABC smaller than 90 degrees?

(1) 2AB = 3BC = 4AC
(2) AC^2 + AB^2 > BC^2

A triangle where a^2 + b^2 = c^2 is a right triangle, but is there any way of determining if measures greater than or less than that (say, if a^2 + b^2 was greater than c^2) lead to a triangle having measures greater than or less than 90?

I see how 1 is sufficient. ABC will always have that exact ratio of side lengths. The triangle could be 2x3x4 or 200x300x400 but the angle measurements will always be the same.

You can see why (2) is not sufficient here: are-all-angles-of-triangle-abc-smaller-than-90-degrees-129298.html#p1060697

As for your other question, say the lengths of the sides of a triangle are a, b, and c, where the largest side is c.

For a right triangle: \(a^2 +b^2= c^2\).
For an acute triangle: \(a^2 +b^2>c^2\).
For an obtuse triangle: \(a^2 +b^2<c^2\).
User avatar
WholeLottaLove
Joined: 13 May 2013
Last visit: 13 Jan 2014
Posts: 301
Own Kudos:
Given Kudos: 134
Posts: 301
Kudos: 640
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
WholeLottaLove
Are all angles of triangle ABC smaller than 90 degrees?

(1) 2AB = 3BC = 4AC
(2) AC^2 + AB^2 > BC^2

For a right triangle: \(a^2 +b^2= c^2\).
For an acute triangle: \(a^2 +b^2>c^2\).
For an obtuse triangle: \(a^2 +b^2<c^2\).

Then wouldn't 2) be sufficient? According to \(a^2 +b^2<c^2\), AC^2 + AB^2 > BC^2 shows that the two legs combined are greater than the third implying that this is an acute triangle.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,763
Own Kudos:
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,763
Kudos: 810,711
Kudos
Add Kudos
Bookmarks
Bookmark this Post
WholeLottaLove
Bunuel
WholeLottaLove
Are all angles of triangle ABC smaller than 90 degrees?

(1) 2AB = 3BC = 4AC
(2) AC^2 + AB^2 > BC^2

For a right triangle: \(a^2 +b^2= c^2\).
For an acute triangle: \(a^2 +b^2>c^2\).
For an obtuse triangle: \(a^2 +b^2<c^2\).

Then wouldn't 2) be sufficient? According to \(a^2 +b^2<c^2\), AC^2 + AB^2 > BC^2 shows that the two legs combined are greater than the third implying that this is an acute triangle.

No, because we don't know whether BC is the largest side.
User avatar
Ergenekon
Joined: 19 Apr 2013
Last visit: 17 Jun 2019
Posts: 471
Own Kudos:
Given Kudos: 537
Concentration: Strategy, Healthcare
GMAT 1: 730 Q48 V41
GPA: 4
GMAT 1: 730 Q48 V41
Posts: 471
Kudos: 288
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel, could you explain how we will find angles when we have ratio of sides as in 1). I understand that it will have the same angles, but how can we find them?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,763
Own Kudos:
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,763
Kudos: 810,711
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ergenekon
Bunuel, could you explain how we will find angles when we have ratio of sides as in 1). I understand that it will have the same angles, but how can we find them?

Finding the angles is not our aim (and this is not what you need to know for the GMAT). The aim is to determine whether we CAN find them.
User avatar
NickHalden
Joined: 15 Feb 2012
Last visit: 19 Jun 2016
Posts: 70
Own Kudos:
Given Kudos: 216
Status:Perspiring
Concentration: Marketing, Strategy
GPA: 3.6
WE:Engineering (Computer Software)
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel,

From your analysis,
a^2 + b^2 < c^2 ------------------ (c is largest then obtuse angle)
so,
3^2 + 4^2 < 6^2 -------------------- Then we have an obtuse angle.

So statement 1 becomes insufficient,
Plz help to clarify....
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,763
Own Kudos:
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,763
Kudos: 810,711
Kudos
Add Kudos
Bookmarks
Bookmark this Post
NickHalden
Bunuel,

From your analysis,
a^2 + b^2 < c^2 ------------------ (c is largest then obtuse angle)
so,
3^2 + 4^2 < 6^2 -------------------- Then we have an obtuse angle.

So statement 1 becomes insufficient,
Plz help to clarify....

The question asks: are all angles of triangle ABC smaller than 90 degrees?

Any triangle which has the ratio of the sides 6:4:3, will be an obtuse triangle, and thus we have an YES answer to the question:
Attachments

MSP3420749f5897f2deg2000045fhi8h0c14f9e4f.gif
MSP3420749f5897f2deg2000045fhi8h0c14f9e4f.gif [ 1.32 KiB | Viewed 14871 times ]

User avatar
Ananabanana
Joined: 06 Apr 2020
Last visit: 21 Mar 2025
Posts: 18
Own Kudos:
18
 [1]
Given Kudos: 119
GPA: 3.61
WE:Corporate Finance (Manufacturing)
Posts: 18
Kudos: 18
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GyanOne
Statement 1: 2AB = 3BC = 4AC
=> AB = 2AC and BC = 4/3 AC
=> AB^2 + BC^2 = 4AC^2 + 16/9 AC^2 = 52 AC^2/9
=> AC^2 > AB^2 + BC^2
=> Angle B is obtuse

=> All angles are not acute. Sufficient.

Statement 2: AC^2 + AB^2 > BC^2
=> Angle A is acute
But this tells us nothing about the other angles. Insufficient.

Therefore (A) is the answer.

Hi there,
Sorry I couldn't understand why it can be inferred like this. (Though it doesn't impact to the "sufficiency" of conclusion but I just want to make sure my understand is correct)

Isn't AB supposed to be the longest side? (logically because only 2 times AB is already 3 times BC and 4 times AC, so AB is the longest and AC is the shortest side)

AB^2 = 4AC^2
BC^2 + AC^2 = 16/9 AC^2 + AC^2 = 25/9* AC^2
As 25/9 = (5/3)^2 <(6/3)^2 = 2^2 = 4,
=> BC^2 + AC^2 <AB^2
=> angle C, not B, is an obtuse angle, right?

Thanks!
User avatar
ANSHUMANDASHISB
Joined: 31 May 2020
Last visit: 05 Aug 2023
Posts: 3
Own Kudos:
Given Kudos: 8
Posts: 3
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
So,

in this rule -

For a right triangle: a2+b2=c2a2+b2=c2.
For an acute triangle: a2+b2>c2a2+b2>c2.
For an obtuse triangle: a2+b2<c2a2+b2<c2

A<B<C ? Please let me know. Thanks
User avatar
Aishyk97
Joined: 13 Sep 2021
Last visit: 11 Mar 2026
Posts: 82
Own Kudos:
Given Kudos: 77
Posts: 82
Kudos: 36
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
WholeLottaLove
Are all angles of triangle ABC smaller than 90 degrees?

(1) 2AB = 3BC = 4AC
(2) AC^2 + AB^2 > BC^2

A triangle where a^2 + b^2 = c^2 is a right triangle, but is there any way of determining if measures greater than or less than that (say, if a^2 + b^2 was greater than c^2) lead to a triangle having measures greater than or less than 90?

I see how 1 is sufficient. ABC will always have that exact ratio of side lengths. The triangle could be 2x3x4 or 200x300x400 but the angle measurements will always be the same.

You can see why (2) is not sufficient here: https://gmatclub.com/forum/are-all-angl ... l#p1060697

As for your other question, say the lengths of the sides of a triangle are a, b, and c, where the largest side is c.

For a right triangle: \(a^2 +b^2= c^2\).
For an acute triangle: \(a^2 +b^2>c^2\).
For an obtuse triangle: \(a^2 +b^2<c^2\).

Hi, Is B insufficient because we don't know which side is the largest side?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,763
Own Kudos:
810,711
 [1]
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,763
Kudos: 810,711
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Aishyk97
Bunuel
WholeLottaLove
Are all angles of triangle ABC smaller than 90 degrees?

(1) 2AB = 3BC = 4AC
(2) AC^2 + AB^2 > BC^2

A triangle where a^2 + b^2 = c^2 is a right triangle, but is there any way of determining if measures greater than or less than that (say, if a^2 + b^2 was greater than c^2) lead to a triangle having measures greater than or less than 90?

I see how 1 is sufficient. ABC will always have that exact ratio of side lengths. The triangle could be 2x3x4 or 200x300x400 but the angle measurements will always be the same.

You can see why (2) is not sufficient here: https://gmatclub.com/forum/are-all-angl ... l#p1060697

As for your other question, say the lengths of the sides of a triangle are a, b, and c, where the largest side is c.

For a right triangle: \(a^2 +b^2= c^2\).
For an acute triangle: \(a^2 +b^2>c^2\).
For an obtuse triangle: \(a^2 +b^2<c^2\).

Hi, Is B insufficient because we don't know which side is the largest side?

Yes, if we were given the information that BC is the largest side in triangle ABC and that AC^2 + AB^2 > BC^2, we could deduce that triangle ABC is acute, meaning that all of its angles are less than 90 degrees.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,959
Own Kudos:
Posts: 38,959
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109763 posts
498 posts
212 posts