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At a party, John collected $96 to buy p equally-priced pizzas. When
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15 Jun 2017, 23:41
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Question Stats:
68% (02:32) correct 32% (02:52) wrong based on 112 sessions
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At a party, John collected $96 to buy p equally-priced pizzas. When he called the store, however, they were running a promotion for $2 off of each pizza, so he was able to buy 4 more pizzas than he expected for the same $96. How much was the cost of each pizza after the discount?
At a party, John collected $96 to buy p equally-priced pizzas. When
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16 Jun 2017, 00:01
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Bunuel wrote:
At a party, John collected $96 to buy p equally-priced pizzas. When he called the store, however, they were running a promotion for $2 off of each pizza, so he was able to buy 4 more pizzas than he expected for the same $96. How much was the cost of each pizza after the discount?
A. $6 B. $8 C. $9 D. $10 E. $12
Let price per pizza be \(x.\)
Total number of pizza \(= p\)
Price of \(x\) pizza's before discount \(= $96\)
\(px = 96\) ------------ (i)
Total number of pizza after discount \(= p + 4\)
Price decrease on each pizza after discount \(= x - 2\)
Given Price of pizza's after discount is \($96\). ie;
\((p+4)(x-2) = 96\) \(px + 4x -2p - 8 = 96\) \(96 + 4x - 2p -8 = 96\) ---------- (Substituting value of \(px\) from (i)) \(4x - 2p - 8 = 0\) \(4x - 2p = 8\) \(2x - p = 4\) \(p = 2x + 4\) ---------- (ii)
Substituting value of \(p\) from (ii) in equation (i), we get;
Re: At a party, John collected $96 to buy p equally-priced pizzas. When
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16 Jun 2017, 00:14
Bunuel wrote:
At a party, John collected $96 to buy p equally-priced pizzas. When he called the store, however, they were running a promotion for $2 off of each pizza, so he was able to buy 4 more pizzas than he expected for the same $96. How much was the cost of each pizza after the discount?
A. $6 B. $8 C. $9 D. $10 E. $12
Let the price for each pizza be x. Thus, \(p*x = 96\) {no. of pizza*price of each pizza = Total sum of money John had} =>\(p = \frac{96}{x}\) -- eqn. (1)
After the discount, reduced price of each pizza = \((x-2)\) and thus, he could buy 4 extra pizza. So, no. of pizzas becomes \((p+4)\) thus the equation changes to : (p+4)*(x-2) = 96 =>\(p+4 = \frac{96}{(x-2)}\) -- eqn (2)
As the price cant be a negative value, \(x= 8\) As x was the original price for the pizzas, i.e., price before discount, price after discount = \((x-2)\) = \(6\)
At a party, John collected $96 to buy p equally-priced pizzas. When
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16 Jun 2017, 02:22
Since John bought p equally priced pizzas, with 96$, and we assume each of the pizza cost 'c' From the question stem pc = 96 96(when prime factorized) gives \(2^5*3\) The cost of the pizza's cannot be \(9(3^2)\) and \(10(2*5)\). So Option C and D are out!
The second part of the question, gives us the price during promotion (p + 4)(c - 2) = 96
Now evaluating the answer options, Since price of pizza (after discount) is 8$, John would have bought 12 pizza's during the promotional period. However, price before discount would be 10$ and he would have bought 8 pizza's which doesn't give us 96$ as total cost. Hence, Option C is also not right
If price after discount is 6$, he would have bought 16 pizza's during the promotional period. However, price before discount would be 8$ and he would have bought 12 pizza's which gives us 96$ as total revenue. Hence, Option A is our answer
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Re: At a party, John collected $96 to buy p equally-priced pizzas. When
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16 Jun 2017, 03:23
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1
Bunuel wrote:
At a party, John collected $96 to buy p equally-priced pizzas. When he called the store, however, they were running a promotion for $2 off of each pizza, so he was able to buy 4 more pizzas than he expected for the same $96. How much was the cost of each pizza after the discount?
A. $6 B. $8 C. $9 D. $10 E. $12
Instead of taking variables and solving the equations, this question can be best done by jumping to the options directly.
John collected $96 to buy p pizzas, each of same price. So obviously, 96 will be divisible by p, and by the un-discounted price of the pizza. The discounted price is $2 less and bought 4 more pizzas i.e. p + 4 pizzas. The discounted price would be divisible by 96 too.
Looking at the options, 6 and 8 could be the discounted and un-discounted prices. At $6, you would get 96/6 = 16 pizzas At $8, you would get 96/8 = 12 pizzas (4 less) (A match)
Hence discounted price is $6
Answer (A)
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Re: At a party, John collected $96 to buy p equally-priced pizzas. When
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16 Jun 2017, 04:12
We can do 'plug-in answers' as well. If total no. of pizzas is p, then price per pizza is 96/p. Price after discount is 96/p-2. Plug in for 10: 96/p-2 = 10, => p = 8. Now, originally price per pizza was 96/8 = 12 (rs2 off) but 96/10 = 9.6 (not four extra pizzas). So we look at a lesser no. Plug-in for 6, 96/p-2 = 6, => p = 12. Now price per pizza = 96/12 = 8. (rs 2 off) and 96/6 = 16, which is 4 extra pizzas. Ans is A
Re: At a party, John collected $96 to buy p equally-priced pizzas. When
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16 Jun 2017, 04:37
VeritasPrepKarishma wrote:
Bunuel wrote:
At a party, John collected $96 to buy p equally-priced pizzas. When he called the store, however, they were running a promotion for $2 off of each pizza, so he was able to buy 4 more pizzas than he expected for the same $96. How much was the cost of each pizza after the discount?
A. $6 B. $8 C. $9 D. $10 E. $12
Instead of taking variables and solving the equations, this question can be best done by jumping to the options directly.
John collected $96 to buy p pizzas, each of same price. So obviously, 96 will be divisible by p, and by the un-discounted price of the pizza. The discounted price is $2 less and bought 4 more pizzas i.e. p + 4 pizzas. The discounted price would be divisible by 96 too.
Looking at the options, 6 and 8 could be the discounted and un-discounted prices. At $6, you would get 96/6 = 16 pizzas At $8, you would get 96/8 = 12 pizzas (4 less) (A match)
Hence discounted price is $6
Answer (A)
That's how I went about it, however my concern was assuming that the $96 had to be divisible by both p and p+4 (especially the latter). They wouldn't have to say that there was any $ left over after in either case, right?
At a party, John collected $96 to buy p equally-priced pizzas. When
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17 Sep 2017, 02:04
Price after discount as per options given are: 6, 8, 9, 10, 12 Price before discount: 8,10,11,12,14 Price after discount and before discount should divide 96. Combination of 6 and 8 does it, therefore answer is A
Re: At a party, John collected $96 to buy p equally-priced pizzas. When
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03 Oct 2018, 17:51
Bunuel wrote:
At a party, John collected $96 to buy p equally-priced pizzas. When he called the store, however, they were running a promotion for $2 off of each pizza, so he was able to buy 4 more pizzas than he expected for the same $96. How much was the cost of each pizza after the discount?
A. $6 B. $8 C. $9 D. $10 E. $12
We can let the price of each pizza before the discount = n and create the equations:
pn = 96
p = 96/n
and
(p + 4)(n - 2) = 96
pn + 4n - 2p - 8 = 96
Substituting p = 96/n into the second equation, we have:
(96/n)n + 4n - 2(96/n) - 8 = 96
96 + 4n - 192/n - 8 = 96
4n - 8 - 192/n = 0
Multiplying by n, we have:
4n^2 - 8n - 192 = 0
n^2 - 2n - 48 = 0
(n - 8)(n + 6) = 0
n = 8 or n = -6
Since the price of a pizza can’t be negative, n = 8. However, this is the price before the discount. The price of each pizza after the discount is 8 - 2 = 6 dollars.
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68% (02:32) correct 
